Python:用一个或多个关键字参数扩展方法的优雅习惯用法是什么?
我试图用一个关键字参数扩展一个方法,同时对该方法的其余签名保持公正;我只是想把它传下去。尝试0:Python:用一个或多个关键字参数扩展方法的优雅习惯用法是什么?,python,Python,我试图用一个关键字参数扩展一个方法,同时对该方法的其余签名保持公正;我只是想把它传下去。尝试0: class SomeSuperclass(object): pass # in reality: some implementation for some_method class SomeClass(SomeSuperclass): def some_method(self, my_kwarg=42, *args, **kwargs): super(SomeCla
class SomeSuperclass(object):
pass # in reality: some implementation for some_method
class SomeClass(SomeSuperclass):
def some_method(self, my_kwarg=42, *args, **kwargs):
super(SomeClass, self).some_method(*args, **kwargs)
do_something_interesting_with(my_kwarg)
SomeClass().some_method('arg 0', 'arg 1', some_kwargs=5, my_kwarg=8)
这不起作用:
Traceback (most recent call last):
File "test.py", line 9, in <module>
SomeClass().some_method('arg 0', 'arg 1', some_kwargs=5, my_kwarg=8)
TypeError: some_method() got multiple values for keyword argument 'my_kwarg'
这是每夸克3行原油…我会使用,就像这样:
class SomeSuperclass(object):
def some_method(self, *args, **kwargs):
print 'SomeSuperclass: args=%s kwargs=%s' % (args, kwargs)
class SomeClass(SomeSuperclass):
def some_method(self, *args, **kwargs):
my_kwarg = kwargs.pop('my_kwarg', 42) # 42 is the default
print 'SomeClass: my_kwarg=%s' % my_kwarg
super(SomeClass, self).some_method(*args, **kwargs)
SomeClass().some_method('arg 0', 'arg 1', some_kwargs=5, my_kwarg=8)
SomeClass().some_method('arg 0', 'arg 1', some_kwargs=5)
运行时,将打印出:
SomeClass: my_kwarg=8
SomeSuperclass: args=('arg 0', 'arg 1') kwargs={'some_kwargs': 5}
SomeClass: my_kwarg=42
SomeSuperclass: args=('arg 0', 'arg 1') kwargs={'some_kwargs': 5}
您可以使用{}.pop()
将您的3行积垢变为1行:
my_kwarg = kwargs.pop('my_kwarg', 42)
我认为这也行得通:my_-kwarg=kwargs.pop('my_-kwarg',42)
my_kwarg = kwargs.pop('my_kwarg', 42)