R 将不同长度向量的列表转换为“tible”`

我目前有一个不同长度的字符向量列表。像这样：

list(
  c('this','is','first'),
  c('this','is','second','it','longer'),
  c('this is a list','that is length 2')
)

data_frame(column_1 =
             c('this is first',
               'this is second it longer',
               'this is a list that is length 2'))

我想将列表中每个向量的所有元素合并到

tibble

中的一行中。像这样：

list(
  c('this','is','first'),
  c('this','is','second','it','longer'),
  c('this is a list','that is length 2')
)

data_frame(column_1 =
             c('this is first',
               'this is second it longer',
               'this is a list that is length 2'))

---

如果可能的话，我想使用base R或来自

tidyverse

的包

您可以使用

purrr

和

stringr

x <- list(
  c('this','is','first'),
  c('this','is','second','it','longer'),
  c('this is a list','that is length 2')
)

tibble(column1= map_chr(x, str_flatten, " "))

---

您可以使用

purr

和

stringr

x <- list(
  c('this','is','first'),
  c('this','is','second','it','longer'),
  c('this is a list','that is length 2')
)

tibble(column1= map_chr(x, str_flatten, " "))