Recursion 使用递归时Ocaml错误取消绑定值_Recursion_Ocaml

Recursion 使用递归时Ocaml错误取消绑定值

recursion ocaml

Recursion 使用递归时Ocaml错误取消绑定值,recursion,ocaml,Recursion,Ocaml,我的代码非常基本，因为我对ocaml还很陌生我试图递归调用函数，但在函数名上收到一条未绑定值错误消息 let count_help x a lst = match lst with [] -> a | (s,i)::t -> if s = x then count_help x a+1 t else count_help x a t ;; let count_assoc lst x = count_help x 0 lst ;; 错误是在count\U

我的代码非常基本，因为我对ocaml还很陌生我试图递归调用函数，但在函数名上收到一条未绑定值错误消息

let count_help x a lst = match lst with 
    [] -> a
    | (s,i)::t -> if s = x then count_help x a+1 t else count_help x a t
;;

let count_assoc lst x =
    count_help x 0 lst
;;

错误是在count\U help中调用count\U help的行上未绑定值count\U help

这段代码只需计算给定字符x的关联出现的次数

let rec count_help ...

允许在其定义中递归使用名称

count\u help