Ruby 如何将Thor:：Group注册为带参数的子命令

这个问题开始了。但随着我对雷神了解的加深，情况发生了重大变化

我试图创建一个Thor:：Group子命令，它接受一个参数。奇怪的是，如果没有争论，它就会起作用

我可以使用Thor:：Group作为子命令吗

当我键入：

foo counter

foo/bin/foo

---

它回答：

计数器调用不正确。以foo计数器号码呼叫

我有一个解决方案。我使用的不是Thor:：Group，而是调用

bin/foo如下所示：

#!/usr/bin/env ruby

require 'foo'

Foo::CLI.start

module Foo

  class Generate < Thor

    desc "project [name]", "Prints the project making step"
    def project(name)
      puts "making first project file #{name}"
      invoke :config
      invoke :project_sub
    end

    desc "config [name]", "Prints the config making step"
    def config(name)
      puts "making first config file #{name}"
      invoke :project_sub
    end

    desc "project_sub [name]", "Prints the project_sub making step"
    def project_sub(name)
      puts "making subsystem file #{name}"
    end

    def self.banner(task, namespace = false, subcommand = true)
       task.formatted_usage(self, true, subcommand).split(':').join(' ')
    end

  end

end

lib/cli.rb-将“generate”注册为基本命令foo:

module Foo
  class CLI < Thor
    register(Generate, 'generate', 'generate [something]', 'Type foo generate for more help.')
  end
end

请注意横幅覆盖。这意味着键入带有无效或缺少参数的：

foo generate project

，将给出正确的帮助消息：

"project" was called incorrectly. Call as "foo generate project [name]".

相对于

"project" was called incorrectly. Call as "foo project [name]".

> making first project file fred
> making first config file fred
> making subsystem file fred

"project" was called incorrectly. Call as "foo generate project [name]".

"project" was called incorrectly. Call as "foo project [name]".