Spring boot 未在Spring Boot web应用程序中呈现JSP文件
我有一个SpringBootWeb应用程序,它使用嵌入式Tomcat(默认设置)启动并运行。当它提供JSP文件作为呈现我在控制器中指定的视图的一部分时,JSP并不是这样呈现的,而是打印出内容。例如: index.jspSpring boot 未在Spring Boot web应用程序中呈现JSP文件,spring-boot,Spring Boot,我有一个SpringBootWeb应用程序,它使用嵌入式Tomcat(默认设置)启动并运行。当它提供JSP文件作为呈现我在控制器中指定的视图的一部分时,JSP并不是这样呈现的,而是打印出内容。例如: index.jsp <%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8" %> <!DOCTYPE html> <html lang="en">
<%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8" %>
<!DOCTYPE html>
<html lang="en">
<head></head>
<body>Test</body>
</html>
确保您的
pom.xml
指定Tomcat JSP依赖项,如下所示:
<dependency>
<groupId>org.apache.tomcat.embed</groupId>
<artifactId>tomcat-embed-jasper</artifactId>
<scope>provided</scope>
</dependency>
org.apache.tomcat.embed
汤姆卡特·贾斯珀
假如
嵌入式Tomcat似乎将JSP呈现视为可选的
如下所述,这个罐子有时也是必要的:
<dependency>
<groupId>javax.servlet</groupId>
<artifactId>jstl</artifactId>
<scope>provided</scope>
</dependency>
javax.servlet
jstl
假如
(我添加了这个JAR,因为它应该包含在servlet容器中。在
pom.xml
中,您需要的不是一个依赖项,而是两个依赖项(jasper和jstl)
<dependencies>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-web</artifactId>
</dependency>
<dependency>
<groupId>org.apache.tomcat.embed</groupId>
<artifactId>tomcat-embed-jasper</artifactId>
<scope>provided</scope>
</dependency>
<dependency>
<groupId>javax.servlet</groupId>
<artifactId>jstl</artifactId>
</dependency>
</dependencies>
org.springframework.boot
SpringBootStarterWeb
org.apache.tomcat.embed
汤姆卡特·贾斯珀
假如
javax.servlet
jstl
您可以更好地使用gradle(它正在追赶Maven)。在build.gradle文件中使用此依赖项
//JSP所需的依赖项
也为我工作,但我不得不搬走
<scope>provided</scope>
<dependency>
<groupId>org.apache.tomcat.embed</groupId>
<artifactId>tomcat-embed-jasper</artifactId>
</dependency>
已提供
org.apache.tomcat.embed
汤姆卡特·贾斯珀
对于我来说,工作方式与Dan提到的相同。删除提供的范围
<dependency>
<groupId>org.apache.tomcat.embed</groupId>
<artifactId>tomcat-embed-jasper</artifactId>
</dependency>
<dependency>
<groupId>javax.servlet</groupId>
<artifactId>jstl</artifactId>
</dependency>
org.apache.tomcat.embed
汤姆卡特·贾斯珀
javax.servlet
jstl
感谢guy的!除了前面描述的以外,我还解决了我的问题:
<dependency>
<groupId>org.apache.tomcat.embed</groupId>
<artifactId>tomcat-embed-jasper</artifactId>
<scope>provided</scope>
</dependency>
from:我面临的问题是在浏览器中打印jsp文件名而不是其内容 通过在pom.xml中添加下面用于jsp页面呈现的代码片段,它可以正确呈现
<dependency>
<groupId>org.apache.tomcat.embed</groupId>
<artifactId>tomcat-embed-jasper</artifactId>
</dependency>
org.apache.tomcat.embed
汤姆卡特·贾斯珀
我认为您错过了一些配置,因为集成JSP很容易,只需遵循以下步骤即可
1-tomcat embad jasper依赖项
<dependency>
<groupId>org.apache.tomcat.embed</groupId>
<artifactId>tomcat-embed-jasper</artifactId>
<scope>provided</scope>
</dependency>
<dependency>
<groupId>org.apache.tomcat.embed</groupId>
<artifactId>tomcat-embed-jasper</artifactId>
<scope>provided</scope>
</dependency>
这是它仍然有一些疑问,然后查看下面的链接
只需更改依赖项即可
<dependency>
<groupId>org.apache.tomcat.embed</groupId>
<artifactId>tomcat-embed-jasper</artifactId>
<scope>provided</scope>
</dependency>
<dependency>
<groupId>org.apache.tomcat.embed</groupId>
<artifactId>tomcat-embed-jasper</artifactId>
<scope>provided</scope>
</dependency>
org.apache.tomcat.embed
汤姆卡特·贾斯珀
假如
到
org.apache.tomcat.embed
汤姆卡特·贾斯珀
使用Spring MVC和嵌入式Tomcat服务器进行Spring引导的完整渐变设置:
格雷德尔先生
buildscript {
ext {
springBootVersion = '1.5.8.RELEASE'
}
repositories {
mavenCentral()
}
dependencies {
classpath("org.springframework.boot:spring-boot-gradle-plugin:${springBootVersion}")
}
}
apply plugin: 'java'
apply plugin: 'org.springframework.boot'
//WEB-MVC
compile 'org.springframework.boot:spring-boot-starter-web:1.5.8.RELEASE'
compile 'org.apache.tomcat.embed:tomcat-embed-jasper:9.0.1'
compile 'javax.servlet:jstl:1.2'
应用程序类
@SpringBootApplication
public final class App {
public static void main(final String[] args) {
new SpringApplicationBuilder(App.class)
.build(args)
.run();
}
@Bean
public ViewResolver viewResolver() {
final InternalResourceViewResolver r = new InternalResourceViewResolver();
r.setPrefix("/WEB-INF/jsp/");
r.setSuffix(".jsp");
return r;
}
}
有时tomcat嵌入jasper不可用,因此需要从tomcat嵌入jasper的maven依赖项中删除提供的 例如
org.apache.tomcat.embed
汤姆卡特·贾斯珀
如果您想使用1.5.8.RELEASE或类似版本,那么这里有一个可运行示例及其说明
您只需要在pom.xml中使用它
http://maven.apache.org/xsd/maven-4.0.0.xsd">
4.0.0
org.springframework.boot
spring启动程序父级
1.5.8.1发布
然后将jsp保存在/WEB-INF/jsp/文件夹中
这是控制器
package com.surasint.example.web.controller;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.GetMapping;
import java.util.Date;
import java.util.Map;
@Controller
public class TestController {
@GetMapping("/testjsp")
public String list(Map<String, Object> model) {
model.put("this_time",new Date().toString());
return "testjsp-view";
}
}
package com.surasint.example.web.controller;
导入org.springframework.stereotype.Controller;
导入org.springframework.web.bind.annotation.GetMapping;
导入java.util.Date;
导入java.util.Map;
@控制器
公共类测试控制器{
@GetMapping(“/testjsp”)
公共字符串列表(映射模型){
model.put(“这次”,新日期().toString());
返回“testjsp视图”;
}
}
appServlet
org.springframework.web.servlet.DispatcherSe rvlet
1.
appServlet
/*
我去掉了*所以它只是来自web.xml
appServlet
org.springframework.web.servlet.DispatcherSe rvlet
1.
appServlet
/
原因是您正在使用注释@RestController而不是@Controller
当您使用RestController注释类时,默认情况下,所有使用@RequestMapping注释的方法都采用@ResponseBody语义。换句话说,您的方法#索引将字符串/webapp/WEB-INF/index.jsp序列化为JSON,而不是将其值映射到视图
就像在其中一个答案中提到的,它必须是
@控制器
公共类控制器{
...
}我遇到了这个问题,最后解决了 我的问题是,我一直在我的
/WEB-INF/index.JSP
页面中放置JSP代码。但是,该页面直接提供服务,没有任何servlet或控制器进行处理。因此,它没有被编译的机会
我的解决方案:
index.jsp
移动到名为views
的子文件夹中
web.xml
,以便它将根目录的控制权传递给DispatcherServlet
<!-- WEB-INF/web.xml -->
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd" version="4.0">
<display-name>18-655_lab_1</display-name>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
dispatcher servlet.xml
中指定的相同基本包
路径,创建将返回ModelAndView的控制器
newmodelandview(“index”、“message”、“IT WORKS!!!”)
意味着
查找名为DispatcherServlet
“/WEB-INF/views/“+”索引“+”.jsp”
- 它编译jsp文件,将
的所有实例替换为${message}
它可以工作!!!
${message}
放在index.jsp
文件的某个地方
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
</head>
<body>
<h1>${message}</h1>
</body>
</html>
${message}
http://localhost:8080/[项目名称]/
对于我来说,使用SpringBootVersion1.5.10.RELEASE,它可以添加以下maven依赖项 注意:仅用于不为这两个项目提供
org.apache.tomcat.embed
汤姆卡特·贾斯珀
javax.servlet
jstl
并在application.properties中提供以下配置
<dependency>
<groupId>org.apache.tomcat.embed</groupId>
<artifactId>tomcat-embed-jasper</artifactId>
<!--scope>provided</scope-->
</dependency>
<groupId>com.surasint.example</groupId>
<artifactId>spring-boot-02</artifactId>
<version>1.0-SNAPSHOT</version>
<packaging>war</packaging>
<properties>
<maven.compiler.target>1.8</maven.compiler.target>
<maven.compiler.source>1.8</maven.compiler.source>
</properties>
<dependencies>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-web</artifactId>
</dependency>
<!-- JSP -->
<dependency>
<groupId>org.apache.tomcat.embed</groupId>
<artifactId>tomcat-embed-jasper</artifactId>
<scope>provided</scope>
</dependency>
<!-- jstl for jsp -->
<dependency>
<groupId>javax.servlet</groupId>
<artifactId>jstl</artifactId>
</dependency>
</dependencies>
<build>
<plugins>
<plugin>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-maven-plugin</artifactId>
</plugin>
</plugins>
</build>
spring.mvc.view.prefix: /WEB-INF/jsp/
spring.mvc.view.suffix: .jsp
package com.surasint.example.web.controller;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.GetMapping;
import java.util.Date;
import java.util.Map;
@Controller
public class TestController {
@GetMapping("/testjsp")
public String list(Map<String, Object> model) {
model.put("this_time",new Date().toString());
return "testjsp-view";
}
}
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherSe rvlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
I took the * off so it was just from web.xml
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherSe rvlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<!-- WEB-INF/web.xml -->
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd" version="4.0">
<display-name>18-655_lab_1</display-name>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
<!-- WEB-INF/dispatcher-servlet.xml -->
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd">
<mvc:annotation-driven />
<context:component-scan
base-package="com.app.controller" />
<mvc:default-servlet-handler />
<bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/views/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
</beans>
package com.app.controller;
@Controller
@RequestMapping(value = "/")
public class RootController {
@RequestMapping(method = RequestMethod.GET)
public ModelAndView homeGet() {
return new ModelAndView("index", "message", "IT WORKS!!!");
}
}
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
</head>
<body>
<h1>${message}</h1>
</body>
</html>
<dependency>
<groupId>org.apache.tomcat.embed</groupId>
<artifactId>tomcat-embed-jasper</artifactId>
<!--<scope>provided</scope>-->
</dependency>
<dependency>
<groupId>javax.servlet</groupId>
<artifactId>jstl</artifactId>
<!--<scope>provided</scope>-->
</dependency>
<dependency>
<groupId>javax.servlet</groupId>
<artifactId>jstl</artifactId>
</dependency>
<dependency>
<groupId>org.apache.tomcat</groupId>
<artifactId>tomcat-jasper</artifactId>
<version>9.0.1</version>
</dependency>
@Controller
public class IndexController {
@RequestMapping("/index")
public String index(Model model) {
model.addAttribute("name", "jancsi");
return "index";
}
}
@Configuration
@EnableWebMvc
@ComponentScan
public class WebConfig implements WebMvcConfigurer {
@Override
public void configureViewResolvers(ViewResolverRegistry registry) {
registry.jsp("/WEB-INF/views/", ".jsp");
}
@Override
public void configureDefaultServletHandling(DefaultServletHandlerConfigurer configurer) {
configurer.enable();
}
}