Sql Oracle每月滚动或运行总计
目标:每个月底所有报表的滚动/运行总计 代码: 电流输出:Sql Oracle每月滚动或运行总计,sql,oracle,Sql,Oracle,目标:每个月底所有报表的滚动/运行总计 代码: 电流输出: MNTH STMTS 7/1/2009 1 10/1/2010 4 6/1/2011 26 9/1/2011 211 10/1/2011 163 11/1/2011 119 期望输出: MNTH STMTS 7/1/2009 1 10/1/2010 5 6/1/2011 31 9/1/2011 242 10/1/2011 405 11/1/2011
MNTH STMTS
7/1/2009 1
10/1/2010 4
6/1/2011 26
9/1/2011 211
10/1/2011 163
11/1/2011 119
期望输出:
MNTH STMTS
7/1/2009 1
10/1/2010 5
6/1/2011 31
9/1/2011 242
10/1/2011 405
11/1/2011 524
听起来好像你想要的是跑步总数。您可以使用分析
SUM
函数进行此操作
select mnth,
sum(stmts) over (order by mnth) stmts
from (select TRUNC(ACTHX.STMT_HX_STMT_DATE, 'MM') AS MNTH,
COUNT(ACTHX.INVOICE) as STMTS
from ACTHX
group by TRUNC(ACTHX.STMT_HX_STMT_DATE, 'MM'))
ORDER BY mnth
一种替代解决方案,提供相同的滚动总计,而不使用子查询
SELECT
DISTINCT TRUNC(ACTHX.STMT_HX_STMT_DATE,'MM') AS MNTH
,count(ACTHX.INVOICE) OVER (ORDER BY TRUNC(ACTHX.STMT_HX_STMT_DATE,'MM')) AS STMTS
FROM ACTHX
ORDER BY
TRUNC(ACTHX.STMT_HX_STMT_DATE,'MM')
运行总数。。。是的,这就是我要找的;)
SELECT
DISTINCT TRUNC(ACTHX.STMT_HX_STMT_DATE,'MM') AS MNTH
,count(ACTHX.INVOICE) OVER (ORDER BY TRUNC(ACTHX.STMT_HX_STMT_DATE,'MM')) AS STMTS
FROM ACTHX
ORDER BY
TRUNC(ACTHX.STMT_HX_STMT_DATE,'MM')