Sql 为每个查询选择最新更新
我有两个表,需要创建一个查询,用最新的日志更新返回所有当前打开的查询 表-sv_查询Sql 为每个查询选择最新更新,sql,Sql,我有两个表,需要创建一个查询,用最新的日志更新返回所有当前打开的查询 表-sv_查询 inquiry_id | status | state | owner_grp | ------------------------------------------------ 1 OPEN Acknowledged DEV 2 OPEN Acknowledged DEV 3 OPEN Rea
inquiry_id | status | state | owner_grp |
------------------------------------------------
1 OPEN Acknowledged DEV
2 OPEN Acknowledged DEV
3 OPEN Reassigned DEV
4 OPEN Reassigned DEV
表-sv_日志
diary_id| inquiry_id | change_dt| change_uid |
------------------------------------------------
1 1 2/1/2013 JBLOGGS
2 1 3/1/2013 JBLOGGS
3 1 4/1/2013 JSMITH
1 2 2/1/2013 JBLOGGS
2 2 4/1/2013 JSMITH
1 3 4/1/2013 JSMITH
2 3 6/1/2013 JBLOGGS
1 4 5/1/2013 JBLOGGS
2 4 8/1/2013 JBLOGGS
我现在使用的代码是
SELECT
t1.inquiry_id,
t1.state,
t1.status,
t1.business_impact,
t1.priority,
t1.owner_rep,
t1.owner_grp,
t2.change_dt as diary_updated,
t2.change_uid as diary_updated_by
FROM sv_inquiry t1
JOIN sv_diary t2
on t1.inquiry_id = t2.inquiry_id
WHERE
owner_grp = 'DEV'
AND state <> 'Closed'
AND status is not null
但是,当我只需要基于sv_日记表中的日期的最新日记条目时,这会返回每个查询的所有日记条目。我该怎么做
为表格的垃圾格式道歉,但我不能想出如何在这个网站上创建一个像样的表格结构
谢谢请尝试通过以下方式分组:
SELECT tt.*,
t2.change_dt,
t2.change_uid
FROM
(
SELECT t1.inquiry_id,
t1.state,
t1.status,
t1.business_impact,
t1.priority,
t1.owner_rep,
t1.owner_grp,
MAX(t2.diary_id) as diary_id
FROM sv_inquiry t1
JOIN sv_diary t2 on t1.inquiry_id = t2.inquiry_id
WHERE owner_grp = 'DEV'
AND state <> 'Closed'
AND status is not null
GROUP BY t1.inquiry_id, t1.state, t1.status, t1.business_impact, t1.priority, t1.owner_rep, t1.owner_grp,
) tt
INNER JOIN sv_diary td on t1.inquiry_id = t2.inquiry_id
您可以尝试以下查询:-
SELECT t1.inquiry_id, t1.state, t1.status, t1.business_impact, t1.priority, t1.owner_rep, t1.owner_grp,
t2.change_dt as diary_updated, t2.change_uid as diary_updated_by
FROM sv_inquiry t1
JOIN (select * from (select d.*,row_number(over partition by inquiry_id order by dairy_updated desc) rn from sv_diary d) where rn =1) t2 on t1.inquiry_id = t2.inquiry_id
WHERE owner_grp = 'DEV'
AND state <> 'Closed'
AND status is not null
我还没有测试过,所以如果你发现任何问题,请告诉我。
我在这里使用了分析查询,它比子查询工作得更快。您必须按日期列排序,并将其限制为第一个元素: MYSQL: SQL Server 如果您使用的是不同的dbms,则可以执行类似的操作来完成此操作。尝试以下操作:
SELECT t1.inquiry_id, t1.state, t1.status, t1.business_impact, t1.priority,
t1.owner_rep, t1.owner_grp, t2.change_dt as diary_updated,
t2.change_uid as diary_updated_by
FROM sv_inquiry t1
LEFT JOIN (
SELECT t1.*
FROM sv_diary t1 JOIN(
SELECT inquery_id, MAX(change_dt)
FROM sv_diary
GROUP BY inquery_id
) t2 ON t1.inquery_id = t2.inquery_id AND t1.change_dt = t2.change_dt
) t2 on t1.inquiry_id = t2.inquiry_id
WHERE t1.owner_grp = 'DEV'
AND t1.state <> 'Closed'
AND t1.status is not null
你说的最新日记更新是什么意思?今天完成的所有更新?您使用的是什么数据库mysql/Microsoft SQL Server?请使用having语句获取最近的日期!
SELECT
t1.inquiry_id,
t1.state,
t1.status,
t1.business_impact,
t1.priority,
t1.owner_rep,
t1.owner_grp,
t2.change_dt as diary_updated,
t2.change_uid as diary_updated_by
FROM sv_inquiry t1
JOIN sv_diary t2
on t1.inquiry_id = t2.inquiry_id
WHERE
owner_grp = 'DEV'
AND state <> 'Closed'
AND status is not null
ORDER BY t2.change_dt DESC
LIMIT 1;
SELECT TOP 1
t1.inquiry_id,
t1.state,
t1.status,
t1.business_impact,
t1.priority,
t1.owner_rep,
t1.owner_grp,
t2.change_dt as diary_updated,
t2.change_uid as diary_updated_by
FROM sv_inquiry t1
JOIN sv_diary t2
on t1.inquiry_id = t2.inquiry_id
WHERE
owner_grp = 'DEV'
AND state <> 'Closed'
AND status is not null
ORDER BY t2.change_dt DESC;
SELECT t1.inquiry_id, t1.state, t1.status, t1.business_impact, t1.priority,
t1.owner_rep, t1.owner_grp, t2.change_dt as diary_updated,
t2.change_uid as diary_updated_by
FROM sv_inquiry t1
LEFT JOIN (
SELECT t1.*
FROM sv_diary t1 JOIN(
SELECT inquery_id, MAX(change_dt)
FROM sv_diary
GROUP BY inquery_id
) t2 ON t1.inquery_id = t2.inquery_id AND t1.change_dt = t2.change_dt
) t2 on t1.inquiry_id = t2.inquiry_id
WHERE t1.owner_grp = 'DEV'
AND t1.state <> 'Closed'
AND t1.status is not null