oracle12c、sql、分组依据
原始sql是:oracle12c、sql、分组依据,sql,oracle,group-by,count,oracle12c,Sql,Oracle,Group By,Count,Oracle12c,原始sql是: select c.col1,a.col2,count(1) from table_1 a,table_2 b.table_3 c where a.key =b.key and b.no = c.no group by c.col1,a.col2 having count(a.col2) >1; 输出: c.col1 a.col2 count(1) aa1 bb1 2 aa1 bb2 3 aa1 bb3 5 aa2 bb8
select c.col1,a.col2,count(1) from table_1 a,table_2 b.table_3 c where a.key =b.key and b.no = c.no group by c.col1,a.col2 having count(a.col2) >1;
输出:
c.col1 a.col2 count(1)
aa1 bb1 2
aa1 bb2 3
aa1 bb3 5
aa2 bb8 1
aa2 bb1 4
我试着得到如下的输出集
c.col1 count(1)
aa1 10
aa2 5
如何编写sql?我相信,如果您只需从select和group by中删除
col2
,就可以做到这一点。因为不再返回col2
,所以还应该删除having语句。我认为应该是这样的:
选择
c、 col1,
计数(1)
从…起
表1 a,
表2 b,
表3 c
哪里
a、 钥匙
b.no=c.no
分组
c、 col1;
我希望这会有所帮助。我相信,如果您只需将
col2
从select和group by中删除,就可以做到这一点。因为不再返回col2
,所以还应该删除having语句。我认为应该是这样的:
选择
c、 col1,
计数(1)
从…起
表1 a,
表2 b,
表3 c
哪里
a、 钥匙
b.no=c.no
分组
c、 col1;
我希望这能有所帮助。使用sum()和groupby来表示col1
select c.col1, sum(a.col2) as total
from table_1 a,table_2 b.table_3 c
where a.key =b.key and b.no = c.no
group by c.col1;
输出--
c.col1 total
aa1 10
aa2 5
对col1使用sum()和group by
select c.col1, sum(a.col2) as total
from table_1 a,table_2 b.table_3 c
where a.key =b.key and b.no = c.no
group by c.col1;
输出--
c.col1 total
aa1 10
aa2 5
一个“简单”的选项是将当前查询(重写为使用JOIN
s,这是目前连接表的首选方式)用作内联视图:
SELECT col1, SUM (cnt)
FROM ( SELECT c.col1, a.col2, COUNT (*) cnt --> your current query begins here
FROM table_1 a
JOIN table_2 b ON a.key = b.key
JOIN table_3 c ON c.no = b.no
GROUP BY c.col1, a.col2
HAVING COUNT (a.col2) > 1) --> and ends here
GROUP BY col1;
或者,从
选择中删除a.col2
:
SELECT c.col1, COUNT (*) cnt
FROM table_1 a
JOIN table_2 b ON a.key = b.key
JOIN table_3 c ON c.no = b.no
GROUP BY c.col1, a.col2
HAVING COUNT (a.col2) > 1;
一个“简单”的选项是将当前查询(重写为使用JOIN
s,这是目前连接表的首选方式)用作内联视图:
SELECT col1, SUM (cnt)
FROM ( SELECT c.col1, a.col2, COUNT (*) cnt --> your current query begins here
FROM table_1 a
JOIN table_2 b ON a.key = b.key
JOIN table_3 c ON c.no = b.no
GROUP BY c.col1, a.col2
HAVING COUNT (a.col2) > 1) --> and ends here
GROUP BY col1;
或者,从选择中删除a.col2
:
SELECT c.col1, COUNT (*) cnt
FROM table_1 a
JOIN table_2 b ON a.key = b.key
JOIN table_3 c ON c.no = b.no
GROUP BY c.col1, a.col2
HAVING COUNT (a.col2) > 1;
有陈述是重点~~有陈述是重点~~在这种情况下,您可以添加以下内容:having count(1)>1在这种情况下,您可以添加以下内容:having count(1)>1