Sql 使用两个组,是否可以将第二个组拆分为列?

Sql 使用两个组,是否可以将第二个组拆分为列?,sql,sql-server,pivot,Sql,Sql Server,Pivot,我有一个类似的查询: SELECT dateadd(DAY,0, datediff(day,0, archivedate)) as day, COUNT(*) item_value, item_metadata.item_label FROM item_values join item_metadata on item_values.md_ID= item_metadata.Id group by dateadd(DAY,0, datediff(day,0, archiveda

我有一个类似的查询:

SELECT dateadd(DAY,0, datediff(day,0, archivedate)) as day, 
    COUNT(*) item_value,
    item_metadata.item_label
FROM item_values
join item_metadata on item_values.md_ID= item_metadata.Id
group by dateadd(DAY,0, datediff(day,0, archivedate)), item_label
order by dateadd(DAY,0, datediff(day,0, archivedate)) desc
这将生成如下所示的数据:

day       item_value    item_label
2020-03-31  8           orange
2020-03-31  2           black
2020-03-30  28          green
2020-03-30  1           blue
2020-03-30  59          orange
2020-03-29  11          black
2020-03-29  1           blue
2020-03-29  15          green
2020-03-29  4           orange
我想让它看起来像这样:

day         orange   black   green   blue
2020-03-31  8        2       0       0
2020-03-30  59       0       28      1
2020-03-29  4        11      15      1 
这在SQL Server中可能吗

我基本上希望最终将数据可视化为一个堆叠的图表

解决 根据下面发布的其他链接,我找到的解决方案是:

 declare
    @cols nvarchar(max),
    @stmt nvarchar(max)

select @cols = isnull(@cols + ', ', '') + '[' + T.item_label + ']' from (select distinct item_label from item_metadata where Active=1) as T

select @stmt = '
select * from (SELECT dateadd(DAY,0, datediff(day,0, archivedate)) as [day], 
COUNT(*) as item_value,
item_label
  FROM item_values
  join item_metadata on item_values.md_ID= item_metadata.Id
   where Ignored=0 group by dateadd(DAY,0, datediff(day,0, archivedate)),item_label ) Visits
    pivot(sum(item_value) for item_metadata
    in (' + @cols + ') ) as pivottable order by day desc
'
exec sp_executesql  @stmt = @stmt

您可能正在寻找动态数据透视查询


DECLARE 
    @columns NVARCHAR(MAX) = '',
    @sql     NVARCHAR(MAX) = '';


SELECT @columns += QUOTENAME(item_label) + ','
From (SELECT DISTINCT item_label 
      FROM #a) A

-- remove the last comma
SET @columns = LEFT(@columns, LEN(@columns) - 1);


SET @sql = 'SELECT * 
            FROM ( SELECT day,item_value,item_label 
                   FROM  #a) src 
                   PIVOT( MAX([item_value]) FOR item_label IN ('+ @columns +')) AS pivot_table;';

-- execute the dynamic SQL
EXECUTE sp_executesql @sql;
输出


您想
透视数据。请检查此示例。-->是的,这正是我需要的