删除T-SQL中的最后一个数字

如何从tsql中的数据和组中删除最后的数字，
查询

从表1中按浏览器分组选择浏览器

结果

所需格式

  Chrome
  Firefox
  IE
  Safari
  InternetExplorer
  Mozilla
  IEMobile

---

注意：我们不知道客户端使用哪个浏览器这对您有效

select distinct browser from (
select REPLACE (REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE 
(browser, '0', ''),'1', ''),'2', ''),'3', ''),'4', ''),'5', ''),
          '6', ''),'7', ''),'8', ''),'9', '') as  browser
 from  TestTable  group by  browser)  temp

您可以使用嵌套的REPLACE（），它的深度可以达到32级：

DECLARE @mystring NVARCHAR(30)

SET @mystring = 'TEST76'

select REPLACE
(REPLACE
(REPLACE
(REPLACE
(REPLACE
(REPLACE
(REPLACE
(REPLACE
(REPLACE
(REPLACE (@mystring, '0', ''),
'1', ''),
'2', ''),
'3', ''),
'4', ''),
'5', ''),
'6', ''),
'7', ''),
'8', ''),
'9', '')

结果：试验

---

希望这有帮助。

您可以这样做：

WITH ExampleCte(Browser) AS (
    SELECT 
        'Chrome11'           UNION ALL SELECT 
        'Chrome28'           UNION ALL SELECT 
        'Chrome30'           UNION ALL SELECT 
        'Chrome31'           UNION ALL SELECT 
        'Chrome32'           UNION ALL SELECT 
        'Chrome33'           UNION ALL SELECT 
        'Firefox12'          UNION ALL SELECT 
        'Firefox22'          UNION ALL SELECT 
        'Firefox30'          UNION ALL SELECT 
        'Firefox32'          UNION ALL SELECT 
        'Firefox33'          UNION ALL SELECT 
        'IE10'               UNION ALL SELECT 
        'IE7'                UNION ALL SELECT 
        'IE8'                UNION ALL SELECT 
        'IE9'                UNION ALL SELECT 
        'IEMobile'           UNION ALL SELECT 
        'IEMobile10'         UNION ALL SELECT 
        'InternetExplorer11' UNION ALL SELECT 
        'Mozilla'            UNION ALL SELECT 
        'Opera9'             UNION ALL SELECT 
        'Safari'             UNION ALL SELECT 
        'Safari5'            UNION ALL SELECT 
        'Safari6'
)
SELECT 
    Browser,
    Left(Browser, Len(Browser) - PatIndex('%[^0-9]%', Reverse(Browser)) + 1) AS BrowserWithoutNumber
FROM 
    ExampleCte

;WITH CTE
AS
(
    SELECT
        (
        CASE 
            WHEN PATINDEX('%[0-9.-]%', browser) = 0 
            THEN browser
            ELSE SUBSTRING(browser,0,PATINDEX('%[0-9.-]%', browser)) 
        END
        ) AS browser
    FROM 
        @tbl AS tbl
)
SELECT
    *
FROM
    CTE
GROUP BY
    CTE.browser

Chrome
Firefox
IE
IEMobile
InternetExplorer
Mozilla
Opera
Safari

WITH cte AS
   (SELECT rtrim(
              substring(
                 browser,
                 1,
                 PATINDEX('%[0-9]%', browser) -1
              )
           ) as browser
    FROM table)
SELECT cte.browser FROM cte
GROUP BY cte.browser

测试数据：

DECLARE @tbl TABLE(browser VARCHAR(100))

INSERT INTO @tbl
VALUES
('Chrome11'),('Chrome28'),('Chrome30'),
('Chrome31'),('Chrome32'),('Chrome33'),
('Firefox12'),('Firefox22'),('Firefox30'),
('Firefox32'),('Firefox33'),('IE10'),
('IE7'),('IE8'),('IE9'),('IEMobile'),
('IEMobile10'),('InternetExplorer11'),('Mozilla'),
('Opera9'),('Safari'),('Safari5'),('Safari6')

然后是这样的查询：

;WITH CTE
AS
(
    SELECT
        (
        CASE 
            WHEN PATINDEX('%[0-9.-]%', browser) = 0 
            THEN browser
            ELSE SUBSTRING(browser,0,PATINDEX('%[0-9.-]%', browser)) 
        END
        ) AS browser
    FROM 
        @tbl AS tbl
)
SELECT
    *
FROM
    CTE
GROUP BY
    CTE.browser

Chrome
Firefox
IE
IEMobile
InternetExplorer
Mozilla
Opera
Safari

WITH cte AS
   (SELECT rtrim(
              substring(
                 browser,
                 1,
                 PATINDEX('%[0-9]%', browser) -1
              )
           ) as browser
    FROM table)
SELECT cte.browser FROM cte
GROUP BY cte.browser

这将得到如下输出：

;WITH CTE
AS
(
    SELECT
        (
        CASE 
            WHEN PATINDEX('%[0-9.-]%', browser) = 0 
            THEN browser
            ELSE SUBSTRING(browser,0,PATINDEX('%[0-9.-]%', browser)) 
        END
        ) AS browser
    FROM 
        @tbl AS tbl
)
SELECT
    *
FROM
    CTE
GROUP BY
    CTE.browser

Chrome
Firefox
IE
IEMobile
InternetExplorer
Mozilla
Opera
Safari

WITH cte AS
   (SELECT rtrim(
              substring(
                 browser,
                 1,
                 PATINDEX('%[0-9]%', browser) -1
              )
           ) as browser
    FROM table)
SELECT cte.browser FROM cte
GROUP BY cte.browser

参考：

创建一个函数：

Create Function fnStrFromAlphaNum(@str varchar(100))
returns varchar(100)
as
begin
    if patindex('%[0-9]%',@str)>0
        set @str = SUBSTRING(@str,1,patindex('%[0-9]%',@str)-1)
    return @str
end

在查询中调用此函数：

select distinct fnStrFromAlphaNum(browser)
from table1

您可以这样做：

;WITH CTE
AS
(
    SELECT
        (
        CASE 
            WHEN PATINDEX('%[0-9.-]%', browser) = 0 
            THEN browser
            ELSE SUBSTRING(browser,0,PATINDEX('%[0-9.-]%', browser)) 
        END
        ) AS browser
    FROM 
        @tbl AS tbl
)
SELECT
    *
FROM
    CTE
GROUP BY
    CTE.browser

Chrome
Firefox
IE
IEMobile
InternetExplorer
Mozilla
Opera
Safari

WITH cte AS
   (SELECT rtrim(
              substring(
                 browser,
                 1,
                 PATINDEX('%[0-9]%', browser) -1
              )
           ) as browser
    FROM table)
SELECT cte.browser FROM cte
GROUP BY cte.browser