使用表达式Yii2选择字符串被检测为列

我有这样一个问题：

use yii\db\Expression;

public function search($params)
{
$query = (new \yii\db\Query())
        ->select([
                "ir.id",
                "ir.no_surat",
                "tc.level",
                "nominal" => 'tc.cleaning',
                new Expression("clean as tagihan"),
                "tc.ditagihkan_bulan"
            ])

        ->from('ydepotras_estimator.repair_estimate as re')
        ->leftJoin(['ydepotras_estimator.inspection_report as ir'],
            "ir.id = re.inspection_id")
        ->innerJoin(['ydepotras_finance.tagihan_cleaning as tc'],
            " re.id = tc.repair_estimate_id");
}

$cleanigQuery->union($oneBarQuery, true);

    $query = (new \yii\db\Query())
        ->select('*')
        ->from(['u' => $cleanigQuery])
        ->orderBy('no_surat');

    $dataProvider = new ActiveDataProvider([
        'query' => $query,

    ]);

请参见

新表达式（“像塔吉汉一样干净”），

Yii2检测到

clean

为列。但我需要tagihan列上的clean as值

+----+-------------+
| id |   tagihan   |
+----+-------------+
| 1  |   clean     |
| 2  |   clean     |
+----+-------------+

更新

义乌联盟2

$cleanigQuery = (new \yii\db\Query())
        ->select([
            "ir.id",
            "ir.no_surat",
            "tc.level",
            "nominal" => 'tc.cleaning',
            new Expression("clean as tagihan"),
            "tc.ditagihkan_bulan"
        ])
        ->from('ydepotras_estimator.repair_estimate as re')
        ->leftJoin(['ydepotras_estimator.inspection_report as ir'],
            "ir.id = re.inspection_id")
        ->innerJoin(['ydepotras_finance.tagihan_cleaning as tc'],
            " re.id = tc.repair_estimate_id");

$oneBarQuery = (new \yii\db\Query())
        ->select([
            "ir.id",
            "ir.no_surat",
            "tob.level",
            "nominal" => 'tob.one_bar',
                new Expression("one_bar as tagihan"),
            "tob.ditagihkan_bulan"
        ])
        ->from('ydepotras_estimator.repair_estimate as re')
        ->leftJoin(['ydepotras_estimator.inspection_report as ir'],
            "ir.id = re.inspection_id")
        ->innerJoin(['ydepotras_finance.tagihan_one_bar as tob'],
            " re.id = tob.repair_estimate_id");

所以，我可以这样做：

use yii\db\Expression;

public function search($params)
{
$query = (new \yii\db\Query())
        ->select([
                "ir.id",
                "ir.no_surat",
                "tc.level",
                "nominal" => 'tc.cleaning',
                new Expression("clean as tagihan"),
                "tc.ditagihkan_bulan"
            ])

        ->from('ydepotras_estimator.repair_estimate as re')
        ->leftJoin(['ydepotras_estimator.inspection_report as ir'],
            "ir.id = re.inspection_id")
        ->innerJoin(['ydepotras_finance.tagihan_cleaning as tc'],
            " re.id = tc.repair_estimate_id");
}

$cleanigQuery->union($oneBarQuery, true);

    $query = (new \yii\db\Query())
        ->select('*')
        ->from(['u' => $cleanigQuery])
        ->orderBy('no_surat');

    $dataProvider = new ActiveDataProvider([
        'query' => $query,

    ]);

---

在这种情况下，您可以使用文字select语句

          ->select("ir.id, ir.no_surat, tc.level, 
                tc.cleaning, 'clean' as tagihan, tc.ditagihkan_bulan")

---

在这种情况下，您可以使用文字select语句

          ->select("ir.id, ir.no_surat, tc.level, 
                tc.cleaning, 'clean' as tagihan, tc.ditagihkan_bulan")

---

像这样：

$query->select（“*，CONCAT（'clean'）as tagihan”）

像这样：

$query->select（“*，CONCAT（'clean'）as tagihan”）

我已经尝试过很多次了，但仍然是“field list”中未知的列“clean”，请确保您有一个干净的列，如果可能的话，您必须分配表别名。。回答更新我很确定，我没有一个列的名称为“clean”，如果你没有一个列的名称为clean。。你为什么要选择它。。或者更好，你说的“像tagihan一样干净”是什么意思？在这种情况下，你需要一个文本值，例如：“干净”像tagihan。。答案已更新。我已经用这种方法尝试了很多时间，但仍然是“字段列表”中的未知列“clean”。请确保您有一个clean列，如果可以，则必须分配表别名。。回答更新我很确定，我没有一个列的名称为“clean”，如果你没有一个列的名称为clean。。你为什么要选择它。。或者更好，你说的“像tagihan一样干净”是什么意思？在这种情况下，你需要一个文本值，例如：“干净”像tagihan。。答案已更新。