Android：您必须先对孩子的父对象2调用removeView（）

我在Android中创建一个动态添加行的表时遇到了一个问题。错误消息是：

指定的子级已具有父级。您必须调用removeView 先看孩子的父母

但是为什么呢

    void setCalendario(List<ArrayList<String>> l){
    TableLayout table = (TableLayout)findViewById(R.id.list_tableLayout1);
    TableRow tr = new TableRow(this);
    tr.removeAllViews();
    tr.setPadding(0,10,0,10);
    tr.setLayoutParams(new LayoutParams(LayoutParams.MATCH_PARENT, LayoutParams.WRAP_CONTENT));
    TextView tv_item1 = new TextView(this);
    TextView tv_item2 = new TextView(this);
    TextView tv_item3 = new TextView(this);
    for (ArrayList<String> al : l){
        int i = 0;
        for(String s : al){
            if (i == 0){
                i++;
                tv_item1.setText(s);
                tv_item1.setGravity(Gravity.CENTER);
            }
            if (i == 1){
                tv_item2.setText(s);
                tv_item2.setGravity(Gravity.CENTER);
                i++;
            }
            if (i == 2){
                tv_item3.setText(s);
                tv_item3.setGravity(Gravity.CENTER);
                tr.addView(tv_item1);
                tr.addView(tv_item2);
                tr.addView(tv_item3);
                table.addView(tr, new TableLayout.LayoutParams(LayoutParams.MATCH_PARENT, LayoutParams.WRAP_CONTENT));
            }
        }
    }

    }

xml代码：

   <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    tools:context="com.MSca.gorhinos.Calendario$PlaceholderFragment" >

    <TableLayout
    android:id="@+id/list_tableLayout1"
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:layout_marginTop="10dp"
    android:stretchColumns="0,1,2,3" >

<TableRow
    android:id="@+id/tableRow1"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content">

<TextView
                android:id="@+id/textView1"
                android:layout_width="wrap_content"
                android:layout_height="wrap_content"
                android:gravity="center"
                android:textColor="#000000"/>

<TextView
                android:id="@+id/textView2"
                android:layout_width="wrap_content"
                android:layout_height="wrap_content"
                android:gravity="center"
                android:textColor="#000000"/>

<TextView
                android:id="@+id/textView3"
                android:layout_width="wrap_content"
                android:layout_height="wrap_content"
                android:gravity="center"
                android:textColor="#000000"/>


</TableRow>
</TableLayout>

</RelativeLayout>

---

您正在使用for循环将对TextView的相同引用添加到TableRow。因此，在循环的下一次迭代中，相同的对象再次添加到TableRow或TableLayout！那时他们已经有了父母

尝试初始化outerfor循环中的TableRow和TextView对象

编辑：修改您的代码

void setCalendario(List<ArrayList<String>> l) {
    // Here we initialize the objects we re-initialize every iteration of the loop
    TableLayout table = (TableLayout)findViewById(R.id.list_tableLayout1);
    for (ArrayList<String> al : l) {
        TableRow tr = new TableRow(this);
    // I can't believe a freshly initialized TableRow object has views attached...
        tr.removeAllViews();
        tr.setPadding(0,10,0,10);
    // Not sure why these layout params are needed already, as they are specified
    // when adding this TableRow to the TableLayout object as well.
        tr.setLayoutParams(new LayoutParams(LayoutParams.MATCH_PARENT, LayoutParams.WRAP_CONTENT));
        TextView tv_item1 = new TextView(this);
        TextView tv_item2 = new TextView(this);
        TextView tv_item3 = new TextView(this);
        int i = 0;
        for(String s : al) {
            if (i == 0) {
                i++;
                tv_item1.setText(s);
                tv_item1.setGravity(Gravity.CENTER);
            }
            if (i == 1) {
                tv_item2.setText(s);
                tv_item2.setGravity(Gravity.CENTER);
                i++;
            }
            if (i == 2) {
                tv_item3.setText(s);
                tv_item3.setGravity(Gravity.CENTER);
                tr.addView(tv_item1);
                tr.addView(tv_item2);
                tr.addView(tv_item3);
                table.addView(tr, new TableLayout.LayoutParams(LayoutParams.MATCH_PARENT, LayoutParams.WRAP_CONTENT));
            }
        }
    }
    } 

---

您正在使用for循环将对TextView的相同引用添加到TableRow。因此，在循环的下一次迭代中，相同的对象再次添加到TableRow或TableLayout！那时他们已经有了父母

尝试初始化outerfor循环中的TableRow和TextView对象

编辑：修改您的代码

void setCalendario(List<ArrayList<String>> l) {
    // Here we initialize the objects we re-initialize every iteration of the loop
    TableLayout table = (TableLayout)findViewById(R.id.list_tableLayout1);
    for (ArrayList<String> al : l) {
        TableRow tr = new TableRow(this);
    // I can't believe a freshly initialized TableRow object has views attached...
        tr.removeAllViews();
        tr.setPadding(0,10,0,10);
    // Not sure why these layout params are needed already, as they are specified
    // when adding this TableRow to the TableLayout object as well.
        tr.setLayoutParams(new LayoutParams(LayoutParams.MATCH_PARENT, LayoutParams.WRAP_CONTENT));
        TextView tv_item1 = new TextView(this);
        TextView tv_item2 = new TextView(this);
        TextView tv_item3 = new TextView(this);
        int i = 0;
        for(String s : al) {
            if (i == 0) {
                i++;
                tv_item1.setText(s);
                tv_item1.setGravity(Gravity.CENTER);
            }
            if (i == 1) {
                tv_item2.setText(s);
                tv_item2.setGravity(Gravity.CENTER);
                i++;
            }
            if (i == 2) {
                tv_item3.setText(s);
                tv_item3.setGravity(Gravity.CENTER);
                tr.addView(tv_item1);
                tr.addView(tv_item2);
                tr.addView(tv_item3);
                table.addView(tr, new TableLayout.LayoutParams(LayoutParams.MATCH_PARENT, LayoutParams.WRAP_CONTENT));
            }
        }
    }
    } 

---

因此，您可以创建tv_项目1、tv_项目2和tv_项目3。然后在循环中为所有ArrayList添加此视图

tr.addView(tv_item1);
tr.addView(tv_item2);
tr.addView(tv_item3);

在第二次迭代中，您已经将tv_item1添加到tr中，并且希望再次添加。我想你只需要把这些线转移到自行车上：

TableRow tr = new TableRow(this);
tr.removeAllViews();
tr.setPadding(0,10,0,10);
tr.setLayoutParams(new LayoutParams(LayoutParams.MATCH_PARENT,LayoutParams.WRAP_CONTENT));
TextView tv_item1 = new TextView(this);
TextView tv_item2 = new TextView(this);
TextView tv_item3 = new TextView(this);

---

因此，您可以创建tv_项目1、tv_项目2和tv_项目3。然后在循环中为所有ArrayList添加此视图

tr.addView(tv_item1);
tr.addView(tv_item2);
tr.addView(tv_item3);

在第二次迭代中，您已经将tv_item1添加到tr中，并且希望再次添加。我想你只需要把这些线转移到自行车上：

TableRow tr = new TableRow(this);
tr.removeAllViews();
tr.setPadding(0,10,0,10);
tr.setLayoutParams(new LayoutParams(LayoutParams.MATCH_PARENT,LayoutParams.WRAP_CONTENT));
TextView tv_item1 = new TextView(this);
TextView tv_item2 = new TextView(this);
TextView tv_item3 = new TextView(this);

---

因为您多次尝试放置相同的文本视图。您只能使用它一次，因此必须一次又一次地实例化它：

// you remove the definition of the text views here and you put it inside the loop
    for (ArrayList<String> al : l){
        int i = 0;
        for(String s : al){
 TextView tv_item2 = new TextView(this);
TextView tv_item1 = new TextView(this);
TextView tv_item3 = new TextView(this);
            if (i == 0){
                i++;

                tv_item1.setText(s);
                tv_item1.setGravity(Gravity.CENTER);
            }
            if (i == 1){

                tv_item2.setText(s);
                tv_item2.setGravity(Gravity.CENTER);
                i++;
            }
            if (i == 2){

                tv_item3.setText(s);
                tv_item3.setGravity(Gravity.CENTER);
                tr.addView(tv_item1);
                tr.addView(tv_item2);
                tr.addView(tv_item3);
                table.addView(tr, new TableLayout.LayoutParams(LayoutParams.MATCH_PARENT, LayoutParams.WRAP_CONTENT));
            }
        }
    }

---

这不是最好的方法，你应该创建一个以i为参数的方法，并返回一个带有重心的文本视图。。。还有你的员工

因为您多次尝试放置相同的文本视图。您只能使用它一次，因此必须一次又一次地实例化它：

// you remove the definition of the text views here and you put it inside the loop
    for (ArrayList<String> al : l){
        int i = 0;
        for(String s : al){
 TextView tv_item2 = new TextView(this);
TextView tv_item1 = new TextView(this);
TextView tv_item3 = new TextView(this);
            if (i == 0){
                i++;

                tv_item1.setText(s);
                tv_item1.setGravity(Gravity.CENTER);
            }
            if (i == 1){

                tv_item2.setText(s);
                tv_item2.setGravity(Gravity.CENTER);
                i++;
            }
            if (i == 2){

                tv_item3.setText(s);
                tv_item3.setGravity(Gravity.CENTER);
                tr.addView(tv_item1);
                tr.addView(tv_item2);
                tr.addView(tv_item3);
                table.addView(tr, new TableLayout.LayoutParams(LayoutParams.MATCH_PARENT, LayoutParams.WRAP_CONTENT));
            }
        }
    }

---

这不是最好的方法，你应该创建一个以i为参数的方法，并返回一个带有重心的文本视图。。。还有你的员工

可能重复的thx，最终我理解了这位家长的问题，p.s.i++；必须把周期opsthx结束，最后我理解了这个家长的问题，p.s.i++；必须结束周期操作