获取android和java.lang.IllegalStateException中的联系人号码
我试图得到联系电话和姓名。我得到的名字是正确的，但当我试图得到的数字，我得到的错误 代码如下：获取android和java.lang.IllegalStateException中的联系人号码,android,android-contacts,Android,Android Contacts,我试图得到联系电话和姓名。我得到的名字是正确的，但当我试图得到的数字，我得到的错误 代码如下： public void onActivityResult(int reqCode, int resultCode, Intent data) { super.onActivityResult(reqCode, resultCode, data); ArrayList<String> contactList = new ArrayList<String>();
public void onActivityResult(int reqCode, int resultCode, Intent data) {
super.onActivityResult(reqCode, resultCode, data);
ArrayList<String> contactList = new ArrayList<String>();
switch (reqCode) {
case (0):
if (resultCode == Activity.RESULT_OK) {
Uri contactData = data.getData();
Cursor c = getContentResolver().query(contactData, null, null,
null, null);
if (c.moveToFirst()) {
String name = c
.getString(c
.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
String phoneNumber = c.getString(c
.getColumnIndex(Phone.NUMBER));
String contact = name + "" + phoneNumber;
contactList.add(contact);
}
}
break;
}
08-12 16:25:19.790: E/WindowManager(14381): Activity tr.com.turkcell.shmobile.MainActivity has leaked window com.android.internal.policy.impl.PhoneWindow$DecorView@421c0090 that was originally added here
ContentResolver cr = getContentResolver();
Cursor cursor = cr.query(uri, projection, selection, null, sortOrder);
while(cursor.moveToNext()){//this loops through contacts and put them in object ContactTest which i already made
ContactTest c1 = new ContactTest();
c1.setContactName(cursor.getString(/*name index*/));
c1.setContactID(cursor.getString(/*id index you will need it*/));
Cursor pCursor = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?", new String[] {c1.getContactID()}, null);
while(pCursor.moveToNext()){ // this loops through the contact number's
c1.setContactPhone(pCursor.getString(pCursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)));
}
}