Android 在将文本发布到tumblr时，我得到的消息未经授权

我在Android应用程序中使用以下代码将文本发布到tumblr：

public class Snippet {
    HttpPost hpost = new HttpPost("http://api.tumblr.com/v2/blog/" + blogname.getText().toString() + ".tumblr.com/post");
    List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
    nameValuePairs.add(new BasicNameValuePair("type", "text"));
    nameValuePairs.add(new BasicNameValuePair("title", title));
    nameValuePairs.add(new BasicNameValuePair("body", body));
    try 
    {
        hpost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
    }
    catch (UnsupportedEncodingException e) 
    {
        debug += e.toString();
    }
    consumer = new CommonsHttpOAuthConsumer(CONSUMER_KEY, CONSUMER_SECRET);
    consumer.setTokenWithSecret(token, secret);
    try 
    {
        consumer.sign(hpost);
    } catch (OAuthMessageSignerException e) 
    {
        debug += e.toString();
    } catch (OAuthExpectationFailedException e) 
    {
        debug += e.toString();
    } catch (OAuthCommunicationException e) 
    {
        debug += e.toString();
    }
    DefaultHttpClient client = new DefaultHttpClient();
    HttpResponse resp = null;
    try 
    {
        resp = client.execute(hpost);
    } catch (ClientProtocolException e) 
    {
        debug += e.toString();
    } catch (IOException e) 
    {
        debug += e.toString();
    }
    String result = null;
    try {
        result = EntityUtils.toString(resp.getEntity());
    } catch (ParseException e) 
    {
        debug += e.toString();
    } catch (IOException e) 
    {
        debug += e.toString();
    }
}

---

我错过什么了吗？我有正确的访问令牌和密钥。

检查你的标题、正文或博客名称，如果它等于null，你的响应将是401

你首先需要在tumblr上创建一个博客，然后你就可以在该博客上发表文章。你需要手动创建一个博客，然后再在该博客上发表文章

HttpPost hpost = new HttpPost("http://api.tumblr.com/v2/blog/" + blogname.getText().toString() + ".tumblr.com/post");

---

将

.tumblr.com/post

替换为

.tumblr.com/posts

您找到了此问题的解决方案吗？我也面临同样的问题。

HttpPost hpost = new HttpPost("http://api.tumblr.com/v2/blog/" + blogname.getText().toString() + ".tumblr.com/post");