Android 当设备处于睡眠状态时，不会调用IntentService

我正在从WakefullBroadcastReceiver触发IntentService

    Intent i = new Intent(context, MyService.class);
    i.putExtras(bundle);
    Log.i("StartService","Before Wakelock");
    WakeLock lock = MyService.getLock(context);
    Log.i("StartService","After Wakelock");
    lock.acquire();
    Log.i("StartService","After Aquire");
    context.startService(i);    
    lock.release();
    Log.i("StartService","After Release");

将显示以上所有日志。但是我的服务没有被呼叫

意向服务

public class MyService extends IntentService {
private static final String NAME = MyService.class.getName() + ".Lock";
private static volatile WakeLock lockStatic = null;

synchronized public static PowerManager.WakeLock getLock(Context context) {
    if (lockStatic == null) {
        PowerManager mgr = (PowerManager) context
                .getSystemService(Context.POWER_SERVICE);
        lockStatic = mgr.newWakeLock(PowerManager.PARTIAL_WAKE_LOCK, NAME);
        lockStatic.setReferenceCounted(true);
    }
    return (lockStatic);
}

public MyService(String name) {
    super(name);
}

public MyService() {
    super("MyService");
}

@Override
protected void onHandleIntent(Intent intent) {
    try {
        Log.i("IntentService", "In HandleIntent");
    } finally {

    }

}

}

有人能帮我吗？？？

在onCreate（）中，您需要将标志添加到窗口中。例如：

 @Override
    protected void onCreate(Bundle savedInstanceState) {
      getWindow().addFlags(WindowManager.LayoutParams.FLAG_SHOW_WHEN_LOCKED | WindowManager.LayoutParams.FLAG_DISMISS_KEYGUARD | WindowManager.LayoutParams.FLAG_KEEP_SCREEN_ON | WindowManager.LayoutParams.FLAG_TURN_SCREEN_ON | WindowManager.LayoutParams.FLAG_ALLOW_LOCK_WHILE_SCREEN_ON);`
}

---

我已经在这里发布了我的服务

您是否在清单文件中声明了您的服务？如果您实际使用的是

WakefulBroadcastReceiver

，并且您按照文档使用它，您不需要自己的

WakeLock

@Kartheek Yes，当设备处于活动状态时，服务被调用。即使设备处于睡眠状态，您是否要唤醒该设备。@Kartheek，即使设备处于睡眠/唤醒状态，我也要启动该服务