在Android中打开活动而不单击通知
是否有一种方法可以在收到推送通知时打开活动,而无需单击通知 示例:-假设我希望在收到推送通知时打开MainActivity。我可以通过单击通知面板中的通知来实现这一点。但我希望在收到通知后立即打开活动(甚至不单击通知)。有可能吗?是的(但这可能取决于您使用什么来接收推送)在Android中打开活动而不单击通知,android,push-notification,Android,Push Notification,是否有一种方法可以在收到推送通知时打开活动,而无需单击通知 示例:-假设我希望在收到推送通知时打开MainActivity。我可以通过单击通知面板中的通知来实现这一点。但我希望在收到通知后立即打开活动(甚至不单击通知)。有可能吗?是的(但这可能取决于您使用什么来接收推送) 在您的代码中,当接收推送时,不要构建和显示通知,而是创建并广播一个将打开您的活动的意图。在您的onMessageReceived方法中,使用以下代码创建广播 Intent intent = new Intent();
在您的代码中,当接收推送时,不要构建和显示通知,而是创建并广播一个将打开您的活动的意图。在您的onMessageReceived方法中,使用以下代码创建广播
Intent intent = new Intent();
intent.setAction("some string");
//intent.addFlags(Intent.FLAG_INCLUDE_STOPPED_PACKAGES);
sendBroadcast(intent);
Log.d("BroadCastData","BroadCastData");
Intent newAct = new Intent(context,yourCallClassName.class);
newAct.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(newAct);
创建一个单独的类,并使用BroadcastReceiver对其进行扩展。在onReceive内部编写以下代码
Intent intent = new Intent();
intent.setAction("some string");
//intent.addFlags(Intent.FLAG_INCLUDE_STOPPED_PACKAGES);
sendBroadcast(intent);
Log.d("BroadCastData","BroadCastData");
Intent newAct = new Intent(context,yourCallClassName.class);
newAct.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(newAct);
将接收者添加到清单文件的最后一步
<receiver android:name=".GetingBroadCastData" > //.GetingBroadCastData is classs name
<intent-filter>
<action android:name="some string" />
</intent-filter>
</receiver>
//.GetingBroadCastData是类的名称
希望这对您有所帮助。我知道现在有点晚了,但它对firebase类中的firebase内部的其他人很有用
public class FireMsgService extends FirebaseMessagingService {
public static final String NOTIFICATION_CHANNEL_ID = "10001" ;
private final static String default_notification_channel_id = "default" ;
String toke;
@Override
public void onMessageReceived(RemoteMessage remoteMessage) {
super.onMessageReceived(remoteMessage);
String message = remoteMessage.getNotification().getBody();
}
创建广播接收器并添加以下代码
public class OnMessageRecieverBroadCast extends BroadcastReceiver {
public static final String NOTIFICATION_CHANNEL_ID = "10001";
public static String NOTIFICATION_ID = "notification-id";
public static String NOTIFICATION = "notification";
public static String NOTIFICATION_MSG = "notificationmsg";
String MsgTitle = "";
String MsgBody;
public void onReceive(Context context, Intent intent) {
if (intent.getExtras() != null) {
Log.d("TestTag", "keySet() size" + intent.getExtras().keySet().size());
for (String key : intent.getExtras().keySet()) {
Object value = intent.getExtras().get(key);
MsgBody = (String) intent.getExtras().get("gcm.notification.body");
MsgTitle = (String) intent.getExtras().get("gcm.notification.title");
Intent intent1 = new Intent(context, NotificationDialogActivity.class);
intent1.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
intent1.putExtra("value", MsgBody);
intent1.putExtra("NOTIFICATION_MSG_TITLE", MsgTitle);
context.startActivity(intent1);
}
}
}
内部onCreate
方法
onCreate(){
if (getIntent().getExtras() != null) {
toke = getIntent().getStringExtra("value");
dialogOpenTop(NotificationDialogActivity.this, toke);
}
//add dialog method
public void dialogOpenTop(final Context context, String toke) {
final Dialog dialog = new Dialog(NotificationDialogActivity.this);
dialog.setContentView(R.layout.alert);
dialog.getWindow().setBackgroundDrawable(new
ColorDrawable(Color.TRANSPARENT));
dialog.setCancelable(false);
dialog.show
}
在舱单中:
<service
android:name=".notification.FireMsgService"
android:exported="false">
<intent-filter>
<action android:name="com.google.firebase.MESSAGING_EVENT" />
</intent-filter>
</service>
<receiver
android:name=".notification.OnMessageRecieverBroadCast"
android:exported="true"
android:permission="com.google.android.c2dm.permission.SEND">
<intent-filter>
<action android:name="com.google.android.c2dm.intent.RECEIVE" />
</intent-filter>
</receiver
>
您的setAction字符串和manifest receiver action android名称字符串应该相同。这是一个工作代码。您能分享代码片段吗?@aditya