Android java.lang.IllegalStateException:目标主机不能为null，也不能在参数中设置

Ulr：

当我尝试在android中使用此url和post请求时，我遇到以下错误

http://23.23.82.251:9116/solr/db/select?q=*:*+_val_:%22geodist%28%29%22&fq=(ProviderType:10)&rows=100&wt=json&indent=true&fl=ProviderID,ProviderType,ProviderName,ProviderAddress,CityAreaID,CityAreaName,City,State,Latlong,score&fq={!geofilt}&sfield=Latlong&pt=20.296059,85.82454&d=5&sort=geodist()%20asc

我使用了URLEncoder.encode（），但仍然会遇到相同的错误。你能告诉我哪里写错了吗。下面是我正在使用的代码

10-22 13:54:49.946: E/SearchResult(6659): Exception Name = java.lang.IllegalArgumentException

请试试这个

            HttpParams httpParameters = new BasicHttpParams();
            // Set the timeout in milliseconds until a connection is established.
            // The default value is zero, that means the timeout is not used. 
            int timeoutConnection = 10000;

            HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);

            // Set the default socket timeout (SO_TIMEOUT) 
            // in milliseconds which is the timeout for waiting for data.
            int timeoutSocket = 15000;
            HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);               
            httpclient = new DefaultHttpClient(httpParameters);             

            HttpPost httppost = new HttpPost(url here);
            JSONObject json = new JSONObject();
            // Execute HTTP Post Request
            HttpResponse response = httpclient.execute(httppost);
            HttpEntity httpEntity = response.getEntity();
            InputStream instream = httpEntity.getContent();
            String result= Utilities.convertStreamToString(instream);

            json=new JSONObject(result);

URLEncoder.encode（“，“UTF-8”）；

您不应该对整个URL进行编码，因为这会导致类似于

URLEncoder.encode("<url here>", "UTF-8");

正在用作URL。这将失败，因为无法将其解析为正常的HTTP URL

相反，只需尝试使用

newhttppost（“http://23.23.82.251:9116/...");
请用这种方法试试

http%3A%2F%2F23.23.82.251%3A9116%2Fsolr%2Fdb%2Fselect%3Fq%3D*%3A*%2B_val_%3A%2522geodist%2528%2529%2522%26fq%3D(ProviderType%3A10)%26rows%3D100%26wt%3Djson%26indent%3Dtrue%26fl%3DProviderID%2CProviderType%2CProviderName%2CProviderAddress%2CCityAreaID%2CCityAreaName%2CCity%2CState%2CLatlong%2Cscore%26fq%3D{!geofilt}%26sfield%3DLatlong%26pt%3D20.296059%2C85.82454%26d%3D5%26sort%3Dgeodist()%2520asc

HttpClient-HttpClient=newdefaulthttpclient（）；
HttpPost HttpPost=新的HttpPost（“http://www.yoursite.com/script.php");
试一试{
//添加您的数据
List nameValuePairs=新的ArrayList（2）；
添加（新的BasicNameValuePair（“id”，“12345”）；
添加（新的BasicNameValuePair（“stringdata”、“test”）；
setEntity（新的UrlEncodedFormEntity（nameValuePairs））；
//执行HTTP Post请求
HttpResponse response=httpclient.execute（httppost）；
}捕获（客户端协议例外e）{
//TODO自动生成的捕捉块
}捕获（IOE异常）{
//TODO自动生成的捕捉块
}
如果直接使用out编码，则会得到以下异常名称=java.lang.IllegalArgumentException。不幸的是，它在三星S3中工作，但在emulator和其他设备中不工作，这是不同的！第一个案例是IllegalStateException，第二个案例是IllegalArgumentException。发布新的异常…这两种情况下我得到了不同的异常就像我说的，请用新的异常更新你的问题。没有什么我删除了URLEncoder.encode（url在这里），然后我直接使用了HttpPost HttpPost=new HttpPost（url在这里）；那一次我得到了java.lang.IllegalArgumentException。至少如果你想从网上窃取代码片段。@nneonneo->对不起。为了便于理解，我只是将示例代码粘贴到这里。。仅此而已……如果您从web上获取示例代码，您应该通过提供指向原始.str.replace（“，“%20”）的链接来引用它；这个替换声明为我解决了这个问题。
HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost("http://www.yoursite.com/script.php");

    try {
        // Add your data
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
        nameValuePairs.add(new BasicNameValuePair("id", "12345"));
        nameValuePairs.add(new BasicNameValuePair("stringdata", "test"));
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

        // Execute HTTP Post Request
        HttpResponse response = httpclient.execute(httppost);

    } catch (ClientProtocolException e) {
        // TODO Auto-generated catch block
    } catch (IOException e) {
        // TODO Auto-generated catch block
    }