Warning: file_get_contents(/data/phpspider/zhask/data//catemap/1/angular/26.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
如何在mat sidenav Angular 7中引用右routerlink?_Angular_Angular7 - Fatal编程技术网

如何在mat sidenav Angular 7中引用右routerlink?

如何在mat sidenav Angular 7中引用右routerlink?,angular,angular7,Angular,Angular7,我是新来的我需要在我的mat列表项中使用与子mat sidenav内容中相同的路由器链接 例如: [routerLink]=“['/list',{outlets:{sidebar:['general',employee.userId]}}] 是正确的链接,我还需要与submat sidenav content中的链接相同。相反,我有以下路由器链接,这是不正确的: [routerLink]=“['/list',{outlets:{sidebar:['general',userId]}] 我不知道如

我是新来的我需要在我的
mat列表项中使用与子
mat sidenav内容中相同的路由器链接

例如:
[routerLink]=“['/list',{outlets:{sidebar:['general',employee.userId]}}]

是正确的链接,我还需要与sub
mat sidenav content
中的链接相同。相反,我有以下路由器链接,这是不正确的:

[routerLink]=“['/list',{outlets:{sidebar:['general',userId]}]

我不知道如何做到这一点,并将感谢任何帮助解决这个问题。多谢各位

<mat-sidenav-container class="sidenav-container">

<mat-sidenav #drawer class="sidenav" fixedInViewport [attr.role]="(isHandset$ | async) ? 'dialog' : 'navigation'" [mode]="(isHandset$ | async) ? 'over' : 'side'" [opened]="(isHandset$ | async) === false">
    <mat-toolbar>List of Employee</mat-toolbar>
    <mat-nav-list>
        <div *ngFor="let employee of employees">
            <mat-list-item>
                <a [routerLink]="['/list',{outlets: {sidebar: ['general', employee.userId]}}]">{{employee.firstName}}
            </a>
            </mat-list-item>
        </div>
    </mat-nav-list>
</mat-sidenav>

<mat-sidenav-content> 
    <mat-toolbar color="accent" class="navbar">
        <span><a mat-list-item [routerLink]="['/list',{outlets: {sidebar: ['general', userId]}}]">
                <mat-icon>assignment_ind</mat-icon>General
            </a></span>
        <span><a mat-list-item [routerLink]="['/list',{outlets: {sidebar: ['vehicleInformation', userId]}}]">
                <mat-icon>directions_car</mat-icon>Vehicle Information
            </a></span>
        <span> <a mat-list-item [routerLink]="['/list',{outlets: {sidebar: ['OLOUserRights']}}]">
                <mat-icon>vpn_key</mat-icon>OLO User Rights
            </a></span>
    </mat-toolbar>

    <router-outlet name="sidebar"></router-outlet>

</mat-sidenav-content>

雇员名单
{{employee.firstName}
总任务
方向与车辆信息
vpn_keyOLO用户权限

**HTML**
{{employee.firstName}
**Ts文件**
senddata(){
这个.router.navigate(['/list',{outlets:{sidebar:['general',employee.userId]}]);
}
**HTML**
{{employee.firstName}
**Ts文件**
senddata(){
这个.router.navigate(['/list',{outlets:{sidebar:['general',employee.userId]}]);
}
这是我的解决方案:

 <div *ngFor="let employee of employees">
                    <mat-list-item>
                     <a routerLinkActive="active" (click)='saveUserID(employee.userId)' [routerLink]="['/list',{outlets: {sidebar: ['general', employee.userId]}}]">{{employee.firstName}}
            </a>list-item>
                </div>
}这是我的解决方案:

 <div *ngFor="let employee of employees">
                    <mat-list-item>
                     <a routerLinkActive="active" (click)='saveUserID(employee.userId)' [routerLink]="['/list',{outlets: {sidebar: ['general', employee.userId]}}]">{{employee.firstName}}
            </a>list-item>
                </div>

}

谢谢!但是如何将当前Id传递给“senddata()”。每次从员工列表中导航到姓名时,我都需要使用此Employee.id。如何检测更改?(ngModelChange)=“senddata(employee.firstName)”您可以在每次更改时使用此选项,这将触发并发送特定的ID谢谢!但是如何将当前Id传递给“senddata()”。每次从员工列表中导航到姓名时,我都需要使用此Employee.id。如何检测更改?(ngModelChange)=“senddata(employee.firstName)”您可以在每次更改时使用它,这将触发并发送特定id
    **Ts File**
    saveUserID(id: number): void { 
this.globalId = id;