Angularjs mongoose中的组嵌套内部数组
我的mongoDb内容如下:Angularjs mongoose中的组嵌套内部数组,angularjs,arrays,node.js,mongodb,mongoose,Angularjs,Arrays,Node.js,Mongodb,Mongoose,我的mongoDb内容如下: [{ "_id": { "$oid": "57c6699711bd6a0976cabe8a" }, "ID": "1111", "FullName": "AAA", "Category": [ { "CategoryId": { "$oid": "57c66ebedcba0f63c1ceea51" }, "_id": { "$oid": "57e38a8a
[{
"_id": {
"$oid": "57c6699711bd6a0976cabe8a"
},
"ID": "1111",
"FullName": "AAA",
"Category": [
{
"CategoryId": {
"$oid": "57c66ebedcba0f63c1ceea51"
},
"_id": {
"$oid": "57e38a8ad190ea1100649798"
},
"Value": [
{
"Name": ""
}
]
},
{
"CategoryId": {
"$oid": "57c3df061eb1e59d3959cc40"
},
"_id": {
"$oid": "57e38a8ad190ea1100649797"
},
"Value": [
[
"111",
"XXXX",
"2005"
],
[
"1212",
"YYYY",
"2000"
],
[
"232323",
"ZZZZZ",
"1999"
]
]
}
]
},{
"_id": {
"$oid": "57c6699711bd6a0976cabe8a"
},
"ID": "1111",
"FullName": "BBB",
"Category": [
{
"CategoryId": {
"$oid": "57c66ebedcba0f63c1ceea51"
},
"_id": {
"$oid": "57e38a8ad190ea1100649798"
},
"Value": [
{
"Name": ""
}
]
},
{
"CategoryId": {
"$oid": "57c3df061eb1e59d3959cc40"
},
"_id": {
"$oid": "57e38a8ad190ea1100649797"
},
"Value": [
[
"4444",
"XXXX",
"2005"
],
[
"7777",
"GGGG",
"2000"
],
[
"8888",
"ZZZZZ",
"1999"
]
]
}
]
}]
resume.aggregate([
{$match: {'Category.CategoryId': new ObjectId('57c3df191eb1e59d3959cc43')}},
{$unwind: '$Category'},
{$unwind: '$Category.Value'},
{$match: {'Category.CategoryId': new ObjectId('57c3df191eb1e59d3959cc43')}},
{$group: { _id: '$Category.Value', count: {$sum: 1}}},
{$project: {'_id':0, TagValue: '$_id',count: '$count'}}
],function(err, resData){
res.send(resData);
});
这里有一个名为“ResumeControle”的数组,其中包含具有不同类别id的对象
我需要
1.选择id为“57c3df061eb1e59d3959cc40”的类别
2.以上所选类别包含值作为数组
3.从值数组中,我必须根据第二个值对元素进行分组,并需要获取用户名列表
Eg输出:
[{
'CategoryName': 'XXXX',
'Users': ['AAA', 'BBB']
},
{
'CategoryName': 'YYYY',
'Users': ['AAA']
},
{
'CategoryName': 'ZZZZZ',
'Users': ['AAA', 'BBB']
},
{
'CategoryName': 'GGGG',
'Users': ['BBB']
}]
我尝试使用聚合函数进行分组,如下所示:
[{
"_id": {
"$oid": "57c6699711bd6a0976cabe8a"
},
"ID": "1111",
"FullName": "AAA",
"Category": [
{
"CategoryId": {
"$oid": "57c66ebedcba0f63c1ceea51"
},
"_id": {
"$oid": "57e38a8ad190ea1100649798"
},
"Value": [
{
"Name": ""
}
]
},
{
"CategoryId": {
"$oid": "57c3df061eb1e59d3959cc40"
},
"_id": {
"$oid": "57e38a8ad190ea1100649797"
},
"Value": [
[
"111",
"XXXX",
"2005"
],
[
"1212",
"YYYY",
"2000"
],
[
"232323",
"ZZZZZ",
"1999"
]
]
}
]
},{
"_id": {
"$oid": "57c6699711bd6a0976cabe8a"
},
"ID": "1111",
"FullName": "BBB",
"Category": [
{
"CategoryId": {
"$oid": "57c66ebedcba0f63c1ceea51"
},
"_id": {
"$oid": "57e38a8ad190ea1100649798"
},
"Value": [
{
"Name": ""
}
]
},
{
"CategoryId": {
"$oid": "57c3df061eb1e59d3959cc40"
},
"_id": {
"$oid": "57e38a8ad190ea1100649797"
},
"Value": [
[
"4444",
"XXXX",
"2005"
],
[
"7777",
"GGGG",
"2000"
],
[
"8888",
"ZZZZZ",
"1999"
]
]
}
]
}]
resume.aggregate([
{$match: {'Category.CategoryId': new ObjectId('57c3df191eb1e59d3959cc43')}},
{$unwind: '$Category'},
{$unwind: '$Category.Value'},
{$match: {'Category.CategoryId': new ObjectId('57c3df191eb1e59d3959cc43')}},
{$group: { _id: '$Category.Value', count: {$sum: 1}}},
{$project: {'_id':0, TagValue: '$_id',count: '$count'}}
],function(err, resData){
res.send(resData);
});
从上面的查询中,它根据值数组进行分组。将包含三个元素的数组分组。任何人都可以根据内部数组值(单个元素,即值[1])对值进行分组,并获得所需的结果
提前感谢。您可以在项目阶段使用
$arrayElemAt
(在3.2版中引入)来选择阵列中的第二个元素
db.resume.aggregate([
{"$unwind":"$Category"},
{"$match":{"Category.CategoryId" :ObjectId("57c3df061eb1e59d3959cc40")}},
{"$unwind":"$Category.Value"},
{"$project":{"FullName":1, "secondVal" : {"$arrayElemAt": ["$Category.Value",1]} }},
{"$group":{"_id":"$secondVal", "Users":{"$addToSet":"$FullName"}}},
{"$project":{"CategoryName":"$_id", "_id": 0, "Users":1}}
])
样本输出:
{ "Users" : [ "AAA", "BBB" ], "CategoryName" : "XXXX" }
{ "Users" : [ "AAA" ], "CategoryName" : "YYYY" }
{ "Users" : [ "BBB" ], "CategoryName" : "GGGG" }
{ "Users" : [ "AAA", "BBB" ], "CategoryName" : "ZZZZZ" }
您只需将“Category.Value”字段两次,因为它有两个嵌套数组:
resume.aggregate([
{ "$match": { "Category.CategoryId": "57c3df061eb1e59d3959cc40" } },
{ "$unwind": "$Category" },
{ "$match": { "Category.CategoryId": "57c3df061eb1e59d3959cc40" } },
{ "$unwind": "$Category.Value" },// <-- unwind twice
{
"$unwind": {
"path": "$Category.Value",
"includeArrayIndex": "idx"
}
},
{ "$match": { "idx": 1 } },
{
"$group": {
"_id": "$Category.Value",
"Users": { "$push": "$FullName" },
"count": { "$sum": 1 }
}
},
{ "$project": { "_id": 0, "CategoryName": "$_id", "Users": 1, "count": 1 } }
], function(err, resData){
res.send(resData);
});
resume.aggregate([
{“$match”:{“Category.CategoryId”:“57c3df061eb1e59d3959cc40”},
{“$unwind”:“$Category”},
{“$match”:{“Category.CategoryId”:“57c3df061eb1e59d3959cc40”},
{“$unwind”:“$Category.Value”},//嗨..我的MongoDb版本-3.0.12…这是一个版本问题吗..如果是这样的话,3.0.12版本中的“$arrayElemAt”的等价物是什么?operator$arrayElemAt”是在3.2版本中引入的。因此,它在3.0版本中不起作用。3.0.12 MongoDb版本中的“$arrayElemAt”有任何等价物吗???我有e升级了我的mongodb版本,“$arrayElemAt”正在运行。但它获得了所有类别,但我只需要id与“57c3df061eb1e59d3959cc40”匹配的类别。如何在“$project”中包含此条件@user3211705:如我的回答所示,您可以在$unwind之后使用$match来限制id为57c3df061eb1e59d3959cc40的类别。上面的示例使用数组中的第一个值对数据进行分组。我应该如何使用第二个值进行分组???即值[1]…您使用的是哪个mongodb版本?我已将我的mongodb版本从3.0.12升级到3.2.10。您可以尝试使用$unwind
操作符包含一个额外字段,该字段保存数组元素索引,然后过滤该索引上的文档,如上面的更新所示。