Angularjs 如何获取在child'；“在父级上的窗体”按钮是否单击？

Parent.html

<div ng-controller="parentController">

<div ng-include="'views/Child.html'">
</div>

<button ng-click="GetChildModel()">
</button>   

</div>

<form ng-controller="childcontroller">
<input type="text" ng-model="child.Firstname">
</input>
 <input type="text" ng-model="child.Lastname">
</input>
</form>

Child.html

<div ng-controller="parentController">

<div ng-include="'views/Child.html'">
</div>

<button ng-click="GetChildModel()">
</button>   

</div>

<form ng-controller="childcontroller">
<input type="text" ng-model="child.Firstname">
</input>
 <input type="text" ng-model="child.Lastname">
</input>
</form>

我的问题是，我需要将child.html中定义的模型放入父控制器，即parentController

---

如何实现这一点？

如果添加“name”属性，表单可以成为控制器

<form name="child">
<input type="text" name="Firstname">
</form>

---

您可以在父控制器中使用：$scope.child.Firstname访问父控制器：

$scope.child = {};
$scope.GetChildModel = function() {
    console.log(angular.toJson($scope.child));
}