Arrays numpy中矩阵的转置
我有一个numpy阵列:Arrays numpy中矩阵的转置,arrays,numpy,transpose,Arrays,Numpy,Transpose,我有一个numpy阵列: a = np.array([[[1,2,3],[-1,-2,-3]],[[4,5,6],[-4,-5,-6]]]) b是a的转置。我希望b是这样的: b = np.array([[[1,-1],[2,-2],[3,-3]],[[4,-4],[5,-5],[6,-6]]]) 可以用一行来做吗 编辑: 如果我有这个: a = np.empty(3,dtype = object) a[0] = np.array([[1,2,3],[-1,-2,-3]]) a[1]
a = np.array([[[1,2,3],[-1,-2,-3]],[[4,5,6],[-4,-5,-6]]])
b
是a
的转置。我希望b是这样的:
b = np.array([[[1,-1],[2,-2],[3,-3]],[[4,-4],[5,-5],[6,-6]]])
可以用一行来做吗
编辑: 如果我有这个:
a = np.empty(3,dtype = object)
a[0] = np.array([[1,2,3],[-1,-2,-3]])
a[1] = np.array([[4,5,6],[-4,-5,-6]])
我怎样才能得到b?你可以使用
np.转置(a,(0,2,1))
:
对于使用数组
dtype=object
编辑的问题,没有直接的方法来计算转置,因为numpy不知道如何转置通用对象。但是,您可以使用列表理解和分别转置每个对象:
In [90]: a = np.empty(2,dtype = object)
In [91]: a[0] = np.array([[1,2,3],[-1,-2,-3]])
In [92]: a[1] = np.array([[4,5,6],[-4,-5,-6]])
In [93]: print a
[[[ 1 2 3]
[-1 -2 -3]] [[ 4 5 6]
[-4 -5 -6]]]
In [94]: b = np.array([np.transpose(o) for o in a],dtype=object)
In [95]: print b
[[[ 1 -1]
[ 2 -2]
[ 3 -3]]
[[ 4 -4]
[ 5 -5]
[ 6 -6]]]
在回答问题并接受答案后,请不要更改您的问题。
In [90]: a = np.empty(2,dtype = object)
In [91]: a[0] = np.array([[1,2,3],[-1,-2,-3]])
In [92]: a[1] = np.array([[4,5,6],[-4,-5,-6]])
In [93]: print a
[[[ 1 2 3]
[-1 -2 -3]] [[ 4 5 6]
[-4 -5 -6]]]
In [94]: b = np.array([np.transpose(o) for o in a],dtype=object)
In [95]: print b
[[[ 1 -1]
[ 2 -2]
[ 3 -3]]
[[ 4 -4]
[ 5 -5]
[ 6 -6]]]