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Asp.net mvc asp.net mvc ajax.begineform onsuccess事件和模型验证_Asp.net Mvc_Validation_Jquery - Fatal编程技术网

Asp.net mvc asp.net mvc ajax.begineform onsuccess事件和模型验证

Asp.net mvc asp.net mvc ajax.begineform onsuccess事件和模型验证,asp.net-mvc,validation,jquery,Asp.net Mvc,Validation,Jquery,这是密码 public class MyModel { [Required] public string Title {get;set;} } public class MyController : Controller { public ActionResult Post(MyModel model) { if (!ModelState.IsValid) return PartialView(model);

这是密码

public class MyModel
{
   [Required]
   public string Title {get;set;}

}


public class MyController : Controller
{
     public ActionResult Post(MyModel model)
     {
          if (!ModelState.IsValid)
             return PartialView(model);

          return PartialView("SomeOtherView"); 
     }



}
这是我的看法

   @model MyModel

   @using(Ajax.BeginForm("Post","My",new AjaxOptions{OnSuccess = "Sucess" }) {
         Html.Partial("Post",Model)

  }

<script>
 function Success(content)
 {
   $("#somediv").html(content);

 }


</script>
@model-MyModel
@使用(Ajax.BeginForm(“Post”、“My”、new-AjaxOptions{OnSuccess=“suces”}){
Html.Partial(“Post”,Model)
}
功能成功(内容)
{
$(“#somediv”).html(内容);
}
现在,当ModelState字典没有错误时,一切都很顺利,但是当出现一些模型验证错误时,我无法在javascript中检测到它。这里有人可以帮忙吗

问候
Parminder有不同的方法来实现这一点。一种方法是让服务器端在出现错误时发送正确的HTTP代码(500):

if (!ModelState.IsValid)
{
    Response.StatusCode = 500;
    return PartialView(model);
}

并在客户端订阅OnFailure回调,并用不同的函数处理错误情况。

有不同的方法来实现这一点。一种方法是让服务器端在出现错误时发送正确的HTTP代码(500):

if (!ModelState.IsValid)
{
    Response.StatusCode = 500;
    return PartialView(model);
}
在客户端上,订阅
OnFailure
回调,并在不同的函数中处理错误情况