Asp.net 如何将标签作为DynamicContextKey发送到面板中？

我有十个这样的块…我在面板\u表\u 1和面板\u播放器\u 1中通过代码隐藏放置了一个标签…我想将面板\u表\u 1中的文本o标签作为DynamicContextKey发送。我应该如何做？

有人可以指导我吗？这是解决方案：

    <tr class="content" id="row1" onmouseover="$find('pce_1').showPopup();" onmouseout="$find('pce_1').hidePopup();">
<td class="style28">
    &nbsp;</td>
        <td class="style30">
            <asp:Panel ID="panel_player_1" runat="server">
            </asp:Panel>
        </td>
        <td class="style21" align="right">
            <asp:Panel ID="panel_table_1" runat="server" Width="50px">
            <ajaxToolkit:PopupControlExtender ID="PopupControlExtender1" runat="server" PopupControlID="Panel222" TargetControlID="panel_table_1"
               DynamicContextKey='<%# Eval("panel_table_1") %>' BehaviorID="pce_1"
               DynamicControlID="Panel222"
               DynamicServiceMethod="GetDynamicContent" Position="Bottom" OffsetX="-485" />
            </asp:Panel>
        </td>

</tr>