如果bash中不满足任何条件，则打印语句

我有一个bash脚本来确定某人的aws密钥是否超过90天。如果是，脚本会向他们发送一封电子邮件，其中包含有关如何旋转关键点的信息

如果没有超过90天的密钥，我希望脚本打印一条语句，这样就不会发送电子邮件

对于每个用户的密钥，我有两个独立的if语句：

if [ "$key1dtSec" -lt "$taSec" ]; then
    printf "%s created on %s\\nThis key is %s days old and needs to be replaced.\\nAn email will be sent." "$user_access_key1" "$key1_date_created." "$key1AgeDays"
    echo -e  "$template1" | /usr/bin/mail --append="Content-type: text/html" -s "AWS Key Rotation Needed for $user_name in $aws_key" "$email_address"
    echo; echo
fi

if [ "$key2dtSec" -lt "$taSec" ]; then
    printf "%s created on %s.\\nThis key is %s days old and needs to be replaced.\\nAn email will be sent." "$user_access_key2" "$key2_date_created"  "$key2AgeDays"
    echo -e  "$template2" | /usr/bin/mail --append="Content-type: text/html" -s "AWS Key Rotation Needed for $user_name in $aws_key" "$email_address"
    echo; echo
fi

key1dtSec

和

key2dtSec

是aws钥匙的使用时间（以秒为单位）

taSec

设置为90天前

如果我使用一个

elif

语句，并且对两个键只使用一个If/then语句，那么只会执行第一个If语句，该语句指示键是否超过90天

我如何写这封信，以便：

如果第一个密钥超过90天并且发送了电子邮件

如果第二个密钥超过90天，则会发送电子邮件

如果没有钥匙超过90天，则会打印一条消息，说明没有钥匙超过90天

---

希望我正确地理解了你的问题。请检查下面的答案

    key1=0
    key2=0

    if [ "$key1dtSec" -lt "$taSec" ]; then
        printf "%s created on %s\\nThis key is %s days old and needs to be replaced.\\nAn email will be sent." "$user_access_key1" "$key1_date_created." "$key1AgeDays"
        echo -e  "$template1" | /usr/bin/mail --append="Content-type: text/html" -s "AWS Key Rotation Needed for $user_name in $aws_key" "$email_address"
        echo; echo
        key1=1
       fi

     if [ "$key2dtSec" -lt "$taSec" ]; then
            printf "%s created on %s.\\nThis key is %s days old and needs to be replaced.\\nAn email will be sent." "$user_access_key2" "$key2_date_created"  "$key2AgeDays"
        echo -e  "$template2" | /usr/bin/mail --append="Content-type: text/html" -s "AWS Key Rotation Needed for $user_name in $aws_key" "$email_address"
        echo; echo
        key2=1
       fi

     if [  "$key1" -eq 0 && "$key2" -eq 0]; then 
        echo "no key is older than 90 days."
        fi

---

希望我正确地理解了你的问题。请检查下面的答案

    key1=0
    key2=0

    if [ "$key1dtSec" -lt "$taSec" ]; then
        printf "%s created on %s\\nThis key is %s days old and needs to be replaced.\\nAn email will be sent." "$user_access_key1" "$key1_date_created." "$key1AgeDays"
        echo -e  "$template1" | /usr/bin/mail --append="Content-type: text/html" -s "AWS Key Rotation Needed for $user_name in $aws_key" "$email_address"
        echo; echo
        key1=1
       fi

     if [ "$key2dtSec" -lt "$taSec" ]; then
            printf "%s created on %s.\\nThis key is %s days old and needs to be replaced.\\nAn email will be sent." "$user_access_key2" "$key2_date_created"  "$key2AgeDays"
        echo -e  "$template2" | /usr/bin/mail --append="Content-type: text/html" -s "AWS Key Rotation Needed for $user_name in $aws_key" "$email_address"
        echo; echo
        key2=1
       fi

     if [  "$key1" -eq 0 && "$key2" -eq 0]; then 
        echo "no key is older than 90 days."
        fi

---

如果我理解正确，您的逻辑如下：

if condition1; then # first key
  action1 # send email
fi

if condition2; then # second key
  action2 # send different email
fi

if ! condition1 && ! condition2; then # neither key
  action3 # print something
fi

---

如果是这样，请将

条件1

替换为

[“$key1dtSec”-lt“$taSec”]

，与

条件2

相同，并在每个块中插入适当的操作。

如果我理解正确，您的逻辑如下：

if condition1; then # first key
  action1 # send email
fi

if condition2; then # second key
  action2 # send different email
fi

if ! condition1 && ! condition2; then # neither key
  action3 # print something
fi

---

如果是这样，将

条件1

替换为

[“$key1dtSec”-lt“$taSec”]

，与

条件2

相同，并在每个块中插入适当的操作。

-eq 0]

结尾处是一个语法错误，这会创建两个额外的全局变量，其中一个（或零，如我的回答）就足够了。@Tom Fenech，谢谢你的建议。请原谅语法错误

-eq 0]

结尾是一个语法错误，这会创建两个额外的全局变量，其中一个（或零，如我的回答）就足够了。@Tom Fenech感谢您的建议。原谅语法错误