Bash 如何通过shell脚本对文件中的随机字符串进行排序_Bash_Shell_Unix_Awk_Cut

Bash 如何通过shell脚本对文件中的随机字符串进行排序

bash shell unix awk

Bash 如何通过shell脚本对文件中的随机字符串进行排序,bash,shell,unix,awk,cut,Bash,Shell,Unix,Awk,Cut,我有一个随机带有这些字符串的文件。如何对它们进行水平排序并消除任何重复项 cat file ticket-125788 ticket-126824 ticket-126957 ticket-126914 ticket-127220 ticket-125948 ticket-126914 ticket-127030 ticket-127262 ticket-127012 ticket-127022 ticket-127035

我有一个随机带有这些字符串的文件。如何对它们进行水平排序并消除任何重复项

cat file
ticket-125788   ticket-126824    ticket-126957   ticket-126914
ticket-127220
ticket-125948                       ticket-126914

ticket-127030
ticket-127262
 ticket-127012  ticket-127022
ticket-127035


     ticket-126961
ticket-127024

所需输出：

ticket-125788 ticket-126824 ticket-126957 ticket-127220 ticket-125948 ticket-126914 ticket-127030 ticket-127262 ticket-127012 ticket-127022 ticket-127035 ticket-126961 ticket-127024

整个想法是

grep

每个«字符串»，然后通过

tr

将其折叠成一行

$> grep -P -o "[0-9a-z-]+" file | sort --unique | tr '\n' ' '
ticket-125788 ticket-125948 ticket-126824 ticket-126914 ticket-126957 ticket-126961 ticket-127012 ticket-127022 ticket-127024 ticket-127030 ticket-127035 ticket-127220 ticket-127262

整个想法是

grep

每个«字符串»，然后通过

tr

将其折叠成一行

$> grep -P -o "[0-9a-z-]+" file | sort --unique | tr '\n' ' '
ticket-125788 ticket-125948 ticket-126824 ticket-126914 ticket-126957 ticket-126961 ticket-127012 ticket-127022 ticket-127024 ticket-127030 ticket-127035 ticket-127220 ticket-127262

这将实现以下目的：

$ grep -o '\S*' file | sort -u | tr '\n' ' '
ticket-125788 ticket-125948 ticket-126824 ticket-126914 ticket-126957 ...

```
grep-o
```
将每张票放在一条单独的线上
```
sort-u
```
排序并删除重复项

cat file
ticket-125788   ticket-126824    ticket-126957   ticket-126914
ticket-127220
ticket-125948                       ticket-126914

ticket-127030
ticket-127262
 ticket-127012  ticket-127022
ticket-127035


     ticket-126961
ticket-127024

```
tr'\n'
```
将输出展平为单行

或者使用

xargs

：

$ xargs -n1 < file | sort -u | xargs
ticket-125788 ticket-125948 ticket-126824 ticket-126914 ticket-126957 ...

$xargs-n1

这将实现以下目的：

$ grep -o '\S*' file | sort -u | tr '\n' ' '
ticket-125788 ticket-125948 ticket-126824 ticket-126914 ticket-126957 ...

```
grep-o
```
将每张票放在一条单独的线上
```
sort-u
```
排序并删除重复项

cat file
ticket-125788   ticket-126824    ticket-126957   ticket-126914
ticket-127220
ticket-125948                       ticket-126914

ticket-127030
ticket-127262
 ticket-127012  ticket-127022
ticket-127035


     ticket-126961
ticket-127024

```
tr'\n'
```
将输出展平为单行

或者使用

xargs

：

$ xargs -n1 < file | sort -u | xargs
ticket-125788 ticket-125948 ticket-126824 ticket-126914 ticket-126957 ...

$xargs-n1