从C中的函数访问动态分配的数组时程序崩溃
感谢您抽出时间阅读此文章。 当我试图访问以前在函数中动态分配的数组时,我的程序就会崩溃。这里有一些代码从C中的函数访问动态分配的数组时程序崩溃,c,arrays,dynamic,structure,allocation,C,Arrays,Dynamic,Structure,Allocation,感谢您抽出时间阅读此文章。 当我试图访问以前在函数中动态分配的数组时,我的程序就会崩溃。这里有一些代码 //function to allocate my array, gives an array as return Player* allocate(Player **a, int n) { *a = (Player *) malloc(sizeof(Player)*(n)); return *a; } //populating my allocated array, re
//function to allocate my array, gives an array as return
Player* allocate(Player **a, int n) {
*a = (Player *) malloc(sizeof(Player)*(n));
return *a;
}
//populating my allocated array, return an array
Player* initializePlayers(Player *a, int n){
int i=0;
char tmp[MAXCHAR];
for(i=0; i<n; i++){
printf("Insert player name %d\n", i);
scanf("%s", tmp);
strcpy(a[i].playerName,tmp);
printf("Player %s assigned.\n", a[i].playerName);
a[i].playerNumber=i;
}
return a;
}
//setup function which includes both the above ones, called from main
void setup(Player *array, int *nPlayers){
int done=0;
while (done==0){
printf("How many players?\n");
scanf("%d", nPlayers);
if (*nPlayers <2 || *nPlayers>8){
printf("Choose between 2 and 8\n");
waitFor(2);
clear();
done=0;
}
else done=1;
}
allocate(&array, *nPlayers);
initializePlayers(array, *nPlayers);
}
我对编程相当陌生,因此我可能缺少一些非常明显的东西,请不要想当然地对函数
setup()
中复制的参数array
进行修改不会影响函数main()
中的局部变量。而你的程序恰好崩溃了
您的setup()
应该是这样的:
void setup(Player **array, int *nPlayers){
/* ... */
allocate(array, *nPlayers);
initializePlayers(*array, *nPlayers);
}
Player * array=NULL;
//I'm passing nPlayers because i want the value to be saved and available on my main
setup(&array, &nPlayers);
应该这样称呼它:
void setup(Player **array, int *nPlayers){
/* ... */
allocate(array, *nPlayers);
initializePlayers(*array, *nPlayers);
}
Player * array=NULL;
//I'm passing nPlayers because i want the value to be saved and available on my main
setup(&array, &nPlayers);
请发布一份包含所有必需声明和定义的声明,包括玩家的声明
。