codeigniter引导模式弹出窗口
我在我的站点中使用了引导模式弹出窗口。单击按钮,弹出窗口将打开。它正在处理以下代码 HTML:codeigniter引导模式弹出窗口,codeigniter,twitter-bootstrap,Codeigniter,Twitter Bootstrap,我在我的站点中使用了引导模式弹出窗口。单击按钮,弹出窗口将打开。它正在处理以下代码 HTML: 启动演示模式 但是按钮来自数组 <?php $args['test'] = array( array( 'type' => 'submit', 'id' => ' text', 'label' => 'Launch demo modal', 'desc' => site_
启动演示模式
但是按钮来自数组
<?php
$args['test'] = array(
array(
'type' => 'submit',
'id' => ' text',
'label' => 'Launch demo modal',
'desc' => site_url('test'),
'class' => 'span3',
'default' => '',
'options' => ''),
);
?>
如何在数组中传递
“data toggle=“modal”data target=“#myModal”
。没有什么不同,只需在数组中添加以下属性:
array(
'type' => 'submit',
'id' => ' musicfileupload',
'label' => 'Launch demo modal',
'desc' => site_url('test'),
'class' => 'span3',
'default' => '',
'options' => '',
'data-toggle' => 'modal', // <--
'data-target' => '#myModal' // <--
);
数组(
'类型'=>'提交',
'id'=>'musicfileupload',
“标签”=>“启动演示模式”,
'desc'=>站点url('test'),
'class'=>'span3',
'默认'=>'',
'选项'=>'',
“数据切换”=>“模式”、//“#myModal”//“提交”,
'id'=>'musicfileupload',
“标签”=>“启动演示模式”,
'desc'=>站点url('test'),
'class'=>'span3',
'默认'=>'',
'选项'=>'',
“数据切换”=>“模式”、//“#我的模式”//
array(
'type' => 'submit',
'id' => ' musicfileupload',
'label' => 'Launch demo modal',
'desc' => site_url('test'),
'class' => 'span3',
'default' => '',
'options' => '',
'data-toggle' => 'modal', // <--
'data-target' => '#myModal' // <--
);
$data = array(
'type' => 'submit',
'id' => ' musicfileupload',
'label' => 'Launch demo modal',
'desc' => site_url('test'),
'class' => 'span3',
'default' => '',
'options' => '',
'data-toggle' => 'modal', // <--
'data-target' => '#myModal' // <--
);
echo form_button($data);