利用GDB:C++开发类对象创建

考虑下面的代码，我已经写了：

#include <iostream>
#include <cstring>
#include <cstdlib>



using namespace std;

class employee{
int ID;
char* name;

        public:

employee(int id,const char* ptr);
~employee();
int getID();
char* getName();
};

employee::employee(int id,const char* ptr):ID(id){
        name= (char*) malloc((strlen(ptr)+1)*sizeof(char));
        strcpy(name,ptr);
        cout << "Employee with ID : " << ID << " Name : " << name << " constructed." << endl;
}

employee::~employee(){
        cout << "Employee with ID : " << ID << " Name : " << name << " destructed." << endl;
        free(name);
        name=NULL;
}

int employee::getID(){return ID;}
char* employee::getName(){return name;}


int main()
{
 employee Ob1(145645,"Edward Collins");
 cout << "Employee Details:" << endl;
 cout << "ID: " << Ob1.getID() << " Name : " << Ob1.getName() << endl;


return 0;
}

现在我试图找出存储Ob1、Ob1.ID、Ob1.name、Ob1.getID、Ob1.getName的地址：

$ gdb GDB
(gdb) break 39
Breakpoint 1 at 0x4012f5: file GDB.cpp, line 39.
(gdb) run


Breakpoint 1, main () at GDB.cpp:39
39       employee Ob1(145645,"Edward Collins");
(gdb) s
employee::employee (this=0x22abf8, id=145645, ptr=0x4020b8 <_data_start__+184> "Edward Collins") at GDB.cpp:21
21      employee::employee(int id,const char* ptr):ID(id){
(gdb)

所以基本上我可以看到ID的地址；但我想找出构造对象的类成员的所有地址，并想在gdb的帮助下探索如何在内存中构造类对象，即地址Ob1、Ob1.ID、Ob1.name、Ob1.getID、Ob1.getName

有人能帮忙吗？

为什么要查看这些东西的地址？若要显示类成员的值，请尝试打印*此。

$ gdb GDB
(gdb) break 39
Breakpoint 1 at 0x4012f5: file GDB.cpp, line 39.
(gdb) run


Breakpoint 1, main () at GDB.cpp:39
39       employee Ob1(145645,"Edward Collins");
(gdb) s
employee::employee (this=0x22abf8, id=145645, ptr=0x4020b8 <_data_start__+184> "Edward Collins") at GDB.cpp:21
21      employee::employee(int id,const char* ptr):ID(id){
(gdb)

Breakpoint 1, main () at GDB.cpp:39
39       employee Ob1(145645,"Edward Collins");
(gdb) s
employee::employee (this=0x22abf8, id=145645, ptr=0x4020b8 <_data_start__+184> "Edward Collins") at GDB.cpp:21
21      employee::employee(int id,const char* ptr):ID(id){
(gdb) s
22              name= (char*) malloc((strlen(ptr)+1)*sizeof(char));
(gdb) s
23              strcpy(name,ptr);
(gdb) s
24              cout << "Employee with ID : " << ID << " Name : " << name << " constructed." << endl;
(gdb) print &ID
$1 = (int *) 0x22abf8
(gdb) x/d 0x22abf8
0x22abf8:       145645
(gdb) print &name
$2 = (char **) 0x22abfc
(gdb) x/d 0x22abfc
0x22abfc:       537103464
(gdb) info locals
No locals.
(gdb)