如何使用espeak API枚举可用语音和语言？ 我使用C++的API来做一些简单的文本到语音合成。目前，我从关于如何开始的基本示例中复制了这一行： espeak_SetVoiceByName("default");

这似乎很好，但我知道espeak有几种不同语言的声音。如何使用espeak API枚举它们，然后在以后使用espeak API选择它们？

使用espeak_SetVoiceByProperties下定义的函数

#ifdef __cplusplus
extern "C"
#endif
ESPEAK_API espeak_ERROR espeak_SetVoiceByName(const char *name);
/* Searches for a voice with a matching "name" field.  Language is not considered.
   "name" is a UTF8 string.

   Return: EE_OK: operation achieved
           EE_BUFFER_FULL: the command can not be buffered;
             you may try after a while to call the function again.
       EE_INTERNAL_ERROR.
*/

#ifdef __cplusplus
extern "C"
#endif
ESPEAK_API espeak_ERROR espeak_SetVoiceByProperties(espeak_VOICE *voice_spec);
/* An espeak_VOICE structure is used to pass criteria to select a voice.  Any of the following
   fields may be set:

   name     NULL, or a voice name

   languages  NULL, or a single language string (with optional dialect), eg. "en-uk", or "en"

   gender   0=not specified, 1=male, 2=female

   age      0=not specified, or an age in years

   variant  After a list of candidates is produced, scored and sorted, "variant" is used to index
            that list and choose a voice.
            variant=0 takes the top voice (i.e. best match). variant=1 takes the next voice, etc
*/

espeak_VOICE

结构是在其上方不远处定义和记录的

---

espeak\u ListVoices

函数用于根据请求枚举语音，它定义在我引用的函数的正上方。

espeak API的文档就是headerfile本身。你可以找到它

要枚举现有语音，可以使用以下方法：

const espeak_VOICE **list=espeak_ListVoices(0);
espeak_VOICE *voice=0;
for(;*list!=0;++list){
    voice=*list;
    if(0!=voice){
        //Look at voice parameters such has voice->name here
    }
}

typedef struct {
    const char *name;      // a given name for this voice. UTF8 string.
    const char *languages;       // list of pairs of (byte) priority + (string) language (and dialect qualifier)
    const char *identifier;      // the filename for this voice within espeak-data/voices
    unsigned char gender;  // 0=none 1=male, 2=female,
    unsigned char age;     // 0=not specified, or age in years
    unsigned char variant; // only used when passed as a parameter to espeak_SetVoiceByProperties
    unsigned char xx1;     // for internal use
    int score;       // for internal use
    void *spare;     // for internal use
} espeak_VOICE;

稍后，当您找到要使用的语音时，可以使用以下设置：

if(0!=voice){
    espeak_SetVoiceByProperties(voice);
}

espeak\u VOICE

结构的定义如下：

const espeak_VOICE **list=espeak_ListVoices(0);
espeak_VOICE *voice=0;
for(;*list!=0;++list){
    voice=*list;
    if(0!=voice){
        //Look at voice parameters such has voice->name here
    }
}

typedef struct {
    const char *name;      // a given name for this voice. UTF8 string.
    const char *languages;       // list of pairs of (byte) priority + (string) language (and dialect qualifier)
    const char *identifier;      // the filename for this voice within espeak-data/voices
    unsigned char gender;  // 0=none 1=male, 2=female,
    unsigned char age;     // 0=not specified, or age in years
    unsigned char variant; // only used when passed as a parameter to espeak_SetVoiceByProperties
    unsigned char xx1;     // for internal use
    int score;       // for internal use
    void *spare;     // for internal use
} espeak_VOICE;

---

简单地阅读API文档？我没有找到API文档。我真的试过了，信不信由你。谷歌

espeak

。2.第一个结果。3.“文件”。4.“espeak库API”。5.阅读：）那不是单据，那是页眉。但是谢谢：-）@LennartRolland：标题是医生。你没有看到里面的文档注释解释如何使用它吗？我在回答中引用了相关的答案。^它也没有回答这个问题。@LennartRolland:是的，它回答了。请再读一遍。Q是如何列举可用的声音。