C++ sse快速加载阵列的前半部分

假设我有一个大小为8的数组，其中填充了无符号int

unsigned int t[8]

现在我想将每个元素的前16位加载到128位寄存器中：

__m128i to_fill

有没有快速的方法可以做到这一点？而不是使用循环和掩蔽位

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每个元素？

您需要加载两个4 x 32位整数的向量，屏蔽每个元素的高16位，然后将它们打包成一个8 x 16位整数的向量

__m128i v_lo = _mm_loadu_si128((__m128i *)&t[0]);
__m128i v_hi = _mm_loadu_si128((__m128i *)&t[4]);
v_lo = _mm_and_si128(v_lo, _mm_set1_epi32(0xffff));
v_hi = _mm_and_si128(v_hi, _mm_set1_epi32(0xffff));
__m128i v = _mm_packs_epi32(v_lo, v_hi);

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您需要加载两个4 x 32位整数的向量，屏蔽每个元素的高16位，然后将它们打包成一个8 x 16位整数的向量

__m128i v_lo = _mm_loadu_si128((__m128i *)&t[0]);
__m128i v_hi = _mm_loadu_si128((__m128i *)&t[4]);
v_lo = _mm_and_si128(v_lo, _mm_set1_epi32(0xffff));
v_hi = _mm_and_si128(v_hi, _mm_set1_epi32(0xffff));
__m128i v = _mm_packs_epi32(v_lo, v_hi);