C# 使用c语言进行字符串操作#

我有一根像下面这样的线

"177848,183074,184225,182439,21002,186745,186615,186362,188001,189777,190224,189535,190629,104602,183314,190203,190341,191050,188027,190003,158104,188564,129725,179936,189696,57340,190906,46815,185009,181315,179967,186804,181993"

我想做一堆这样的5

"177848,183074,184225,182439,21002"
"186745,186615,186362,188001,189777"
"190224,189535,190629,104602,183314"
"190203,190341,191050,188027,190003"
"158104,188564,129725,179936,189696"
"57340,190906,46815,185009,181315"
"179967,186804,181993"

我可以使用foreach来实现这一点，然后设置一个限制。 但我们需要最少一行代码来完成这项工作 编程语言是c#

IList list=new list（）{177848、183074、184225、182439、21002、186745、186615、186362、188001、189777、190224、189535、190629、104602、，
183314, 190203, 190341, 191050, 188027, 190003, 158104, 188564, 129725, 179936, 189696, 57340, 190906, 46815, 185009, 181315, 179967, 186804,
181993 };
int batchSize=5；
int length=Math.Abs（list.Count（）/batchSize）+1；
for（int i=0；i

使用正则表达式将每五个“，”替换为“\n”。

您可以使用正则表达式

string text = "177848,183074,184225,182439,21002,186745,186615,186362,188001,189777,190224,189535,190629,104602,183314,190203,190341,191050,188027,190003,158104,188564,129725,179936,189696,57340,190906,46815,185009,181315,179967,186804,181993";
string[] lines = Regex.Matches(text, "([^,]+,){1,4}[^,]+")
                      .Cast<Match>()
                      .Select(m => m.Value)
                      .ToArray();

string text=“17784818307418422518243921002186745186615186362188001189777190224189535190629104602183314190203190341191050188027190001810418856641297279936189657340190646815185009181315179967186804181993”；
string[]lines=Regex.Matches（文本，“（[^，]+，）{1,4}[^，]+”）
.Cast（）
.选择（m=>m.Value）
.ToArray（）；

或者使用regex的另一种方式：

string text = "177848,183074,184225,182439,21002,186745,186615,186362,188001,189777,190224,189535,190629,104602,183314,190203,190341,191050,188027,190003,158104,188564,129725,179936,189696,57340,190906,46815,185009,181315,179967,186804,181993";
string[] lines = Regex.Split(text, "(?<=^(?:[^,]*,){4}[^,]*(?:(?:,[^,]*){5})*),");

string text=“17784818307418422518243921002186745186615186362188001189777190224189535190629104602183314190203190341191050188027190001810418856641297279936189657340190646815185009181315179967186804181993”；
string[]lines=Regex.Split（text），（？使用StringBuilder和foreach循环最小行数：
string[]lines=new string[7]{“1778481830741842251824391002”、“186745186615118636218800118977”、“190224189535190629104602183314”、“190203190341191050188027190003”、“158018564129725179936189696”5734019090646815185009181315，“17996718680418193”}；
|=^]for（int i=0；istring text = "177848,183074,184225,182439,21002,186745,186615,186362,188001,189777,190224,189535,190629,104602,183314,190203,190341,191050,188027,190003,158104,188564,129725,179936,189696,57340,190906,46815,185009,181315,179967,186804,181993";
string[] lines = Regex.Split(text, "(?<=^(?:[^,]*,){4}[^,]*(?:(?:,[^,]*){5})*),");