C# 字符串的正则表达式

我有一根像

e、 g AHDFFH XXXX

其中“AHDFFH”可以是任意长度的字符字符串。 “XXXX”将是重复的任意长度的“X”字符数，需要在表中用自动递增的数据库值替换

我需要使用正则表达式从上面的字符串中找到重复的“X”字符

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有人能帮我弄清楚吗？。

试试这个：

\b(\p{L})\1+\b

<!--
\b(\p{L})\1+\b

Options: case insensitive; ^ and $ match at line breaks

Assert position at a word boundary «\b»
Match the regular expression below and capture its match into backreference number 1 «(\p{L})»
   A character with the Unicode property “letter” (any kind of letter from any language) «\p{L}»
Match the same text as most recently matched by capturing group number 1 «\1+»
   Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Assert position at a word boundary «\b»
-->

说明：

\b(\p{L})\1+\b

<!--
\b(\p{L})\1+\b

Options: case insensitive; ^ and $ match at line breaks

Assert position at a word boundary «\b»
Match the regular expression below and capture its match into backreference number 1 «(\p{L})»
   A character with the Unicode property “letter” (any kind of letter from any language) «\p{L}»
Match the same text as most recently matched by capturing group number 1 «\1+»
   Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Assert position at a word boundary «\b»
-->

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您的意思是一些字符+（在或一些）空格+一些数字吗

如果是，您可以使用此正则表达式：

\w+\s+(\d+)

c#代码如下：

System.Text.RegularExpressions.Regex regex = new System.Text.RegularExpressions.Regex(@"\w+\s+(\d+)");
System.Text.RegularExpressions.Match m = regex.Match("aaaa 3333");
if(m.Success) {
    MessageBox.Show(m.Groups[1].Value);
}

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这可能会对你有所帮助。我建议你发布一些你正在使用的实际模式。