Doctrine orm 条令联接查询以获取大于1的所有记录
我尝试使用普通的sql查询Doctrine orm 条令联接查询以获取大于1的所有记录,doctrine-orm,createquery,Doctrine Orm,Createquery,我尝试使用普通的sql查询 SELECT activity_shares.id FROM `activity_shares` INNER JOIN (SELECT `activity_id` FROM `activity_shares` GROUP BY `activity_id` HAVING COUNT(`activity_id`) > 1 ) dup ON activity_shares.activity_id = dup.activity_id 这给了我记录id说10和11
SELECT activity_shares.id FROM `activity_shares`
INNER JOIN (SELECT `activity_id` FROM `activity_shares`
GROUP BY `activity_id`
HAVING COUNT(`activity_id`) > 1 ) dup ON activity_shares.activity_id = dup.activity_id
这给了我记录id说10和11
但我在《条令查询生成器》中尝试过的相同查询
$qb3=$this->getEntityManager()->createQueryBuilder('c')
->add('select','c.id')
->add('from','MyBundleDataBundle:ActivityShare c')
->innerJoin('c.activity', 'ca')
// ->andWhere('ca.id = c.activity')
->groupBy('ca.id')
->having('count(ca.id)>1');
编辑:
$query3=$qb3->getQuery();
$query3->getResult();
生成的SQL是:
SELECT a0_.id AS id0 FROM activity_shares a0_
INNER JOIN activities a1_ ON a0_.activity_id = a1_.id
GROUP BY a1_.id HAVING count(a1_.id) > 1
只给出一条10的记录。我想两条都要。我不知道哪里出错了。知道吗
我的表格结构是:
ActivityShare
+-----+---------+-----+---
| Id |activity |Share| etc...
+-----+---------+-----+----
| 1 | 1 |1 |
+-----+---------+-----+---
| 2 | 1 | 2 |
+-----+---------+-----+---
活动
是活动
表的外键。
我想获取Id的1和2简化SQL
首先,让我简化该查询,使其得到相同的结果:
SELECT id FROM `activity_shares`
GROUP BY `id`
HAVING COUNT(`activity_id`) > 1
造船工
如果您像sql建议的那样在表中存储活动的id:
您可以使用简化SQL生成查询:
$results =$this->getEntityManager()->createQueryBuilder('c')
->add('select','c.id')
->add('from','MyBundleDataBundle:ActivityShare c')
->groupBy('c.id')
->having('count(c.activity)>1');
->getResult();
如果使用关联表(条令逻辑)
在这里,您必须使用join,但计数可能很复杂
解决方案1
像使用实体一样使用关联表(在我看来,您只需要id)
假设表名为activityshare\u activity
它将有两个字段activity_id和activityshare_id,如果您想办法向该表中添加一个新的列id并使其自动递增+主,那么其余的就很简单了:
正在调用的新实体ActivityShareActivity
$results =$this->getEntityManager()->createQueryBuilder('c')
->add('select','c.activityshare_id')
->add('from','MyBundleDataBundle:ActivityShareActivity c')
->groupBy('c.activityshare_id')
->having('count(c.activity_id)>1');
->getResult();
添加新标识列以使其与条令兼容的步骤(您需要执行一次):
$result=$this->getEntityManager()->createQueryBuilder()
->select('c.id')
->from('MyBundleDataBundle:ActivityShare', 'c')
->innerJoin('c.activity', 'ca')
->groupBy('c.id') //note: it's c.id not ca.id
->having('count(ca.id)>1')
->getResult();
我最后发布了这篇文章,因为我不能100%确定have+count的输出,但它应该很好:)谢谢你的回答。我终于得到了答案 我的问题是:
$subquery=$this->getEntityManager()->createQueryBuilder('as')
->add('select','a.id')
->add('from','MyBundleDataBundle:ActivityShare as')
->innerJoin('as.activity', 'a')
->groupBy('a.id')
->having('count(a.id)>1');
$query=$this->getEntityManager()->createQueryBuilder('c')
->add('select','c.id')
->add('from','ChowzterDataBundle:ActivityShare c')
->innerJoin('c.activity', 'ca');
$query->andWhere($query->expr()->in('ca.id', $subquery->getDql()))
;
$result = $query->getQuery();
print_r($result->getResult());
SQL看起来像:
SELECT a0_.id AS id0 FROM activity_shares a0_ INNER JOIN activities a1_ ON a0_.activity_id = a1_.id WHERE a1_.id IN (SELECT a2_.id FROM activity_shares a3_ INNER JOIN activities a2_ ON a3_.activity_id = a2_.id GROUP BY a2_.id HAVING count(a2_.id) > 1
您要执行什么来获取结果?必须有一行,如
$query->getResult()
来检索实体。如果你有什么$query->getSingleResult()
你只会得到一行。我已经编辑了这个问题。请参考。看起来不错。尝试$query3->getSql()
获取SQL字符串,并使用MySql客户端将其直接执行到数据库中。看看你是否得到了相同的结果。是的。它只给出了一个记录。结果我得到了一个记录的正确Id。但是我想要两个记录Id。我在MySql客户端尝试的上面的常规sql查询。它给了我两个记录Id。谢谢你的回答。你的简化查询将只给出一个记录Id。假设有两个Id为1和2的记录满足条件计数>1。它将只给我第一个记录Id 1。我想要两者。我猜groupBy
应该在活动Id上,而不是活动共享表Id上。