在gradleexec任务中，命令行搜索环境，但不搜索可执行文件的工作目录

Exec命令行似乎没有查看可执行命令的workingDir，而是搜索环境

如果您的项目结构如下所示：

+ projectRoot
  + libraryMod
    - build.gradle
  + app
    - gradlew
    - build.gradle

你想跑吗

./gradlew -b ../libraryMod/build.gradle someTask

作为执行董事：

exec{
  workingdir = getAbsolutePath("../app")
  commandLine = ['./gradlew', '-b ../libraryMod/build.gradle', 'someTask]
}

返回

[org.gradle.process.internal.DefaultExecHandle] Starting process 'command 'gradlew''. Working directory: /Users/dev/app Command: gradlew -b /Users/dev/libraryMod/build.gradle sometask
[DEBUG] [org.gradle.process.internal.DefaultExecHandle] Environment for process 'command 'gradlew'': {PATH=/usr/local/bin:/Library/Java/JavaVirtualMachines/jdk1.8.0_25.jdk/usr/local/bin:/usr/bin:/bin:/usr/sbin:/sbin:/opt/X11/bin, SHELL=/bin/bash, JAVA_HOME=/Library/Java/JavaVirtualMachines/jdk1.8.0_25.jdk/Contents/Home, JAVA_MAIN_CLASS_29464=org.gradle.wrapper.GradleWrapperMain, TERM=xterm-256color, OLDPWD=/Users/dev/java/android/api/TestApp, USER=dev, TMPDIR=/var/folders/gj/c0vstk4s0c5632d92hp72prxy5h3g7/T/, APP_NAME_29464=Gradle, SSH_AUTH_SOCK=/private/tmp/com.apple.launchd.HaOOxHKo1q/Listeners, DISPLAY=/private/tmp/com.apple.launchd.G54BIfEQjR/org.macosforge.xquartz:0, XPC_FLAGS=0x0, __CF_USER_TEXT_ENCODING=0x7C580DE7:0x0:0x0, Apple_PubSub_Socket_Render=/private/tmp/com.apple.launchd.pUgDDkEH6R/Render, APP_ICON_29464=/Users/dev/app/media/gradle.icns, LOGNAME=dev, LC_CTYPE=en_US.UTF-8, XPC_SERVICE_NAME=0, PWD=/Users/dev/app, SHLVL=1, HOME=/Users/dev, BUILD_NUM=802}



[DEBUG] [org.gradle.process.internal.DefaultExecHandle] Changing state to: STARTING
[DEBUG] [org.gradle.process.internal.DefaultExecHandle] Waiting until process started: command 'gradlew'.
[DEBUG] [org.gradle.process.internal.DefaultExecHandle] Changing state to: FAILED
[DEBUG] [org.gradle.process.internal.DefaultExecHandle] Process 'command 'gradlew'' finished with exit value -1 (state: FAILED)

有没有一种方法可以使用exec，使命令行第一个参数在workingDir中显示

我可以将其作为任务成功运行：

task publishAAR(type:GradleBuild){
description 'publish the lib module aar bundle to artifactory'
buildFile = libModScript
tasks = ['someTask']

}

---

但需要使用exec将其合并到更大的构建文件中

尝试将可执行文件设置为gradlew文件的绝对路径

---

这不起作用，它会启动命令。/gradlew，启动进程“command”。/gradlew“”。工作目录：/Users/dev/api/app命令：./gradlew-p/Users/dev/api/libraryMod artfiactoryPublish。但是项目目录仍然不正确，项目目录“/Users/dev/api/app//Users/dev/api/libraryMod”不存在。

exec {
    executable "${projectDir}/gradlew"
}