如何防止Grails尝试将名为Service的域类作为服务使用？

我的应用程序中有一个名为ContractedService的域类。然而，grails似乎将其识别为一个服务类（即使它位于grails app/domain目录中）。在不完全重命名类的情况下，如何防止这种情况

org.codehaus.groovy.grails.exceptions.GrailsConfigurationException: Cannot add Service class [class com.myapp.ContractedService]. It is not a Service!
    at org.codehaus.groovy.grails.commons.DefaultGrailsApplication.addArtefact(DefaultGrailsApplication.java:750)
    at org.codehaus.groovy.grails.commons.DefaultGrailsApplication.addArtefact(DefaultGrailsApplication.java:474)
    at grails.test.mixin.services.ServiceUnitTestMixin.mockService(ServiceUnitTestMixin.groovy:46)
    at org.spockframework.util.ReflectionUtil.invokeMethod(ReflectionUtil.java:138)
    at org.spockframework.runtime.extension.builtin.JUnitFixtureMethodsExtension$FixtureType$FixtureMethodInterceptor.intercept(JUnitFixtureMethodsExtension.java:145)
    at org.spockframework.runtime.extension.MethodInvocation.proceed(MethodInvocation.java:84)
    at org.spockframework.util.ReflectionUtil.invokeMethod(ReflectionUtil.java:138)
    at org.spockframework.runtime.extension.MethodInvocation.invokeTargetMethod(MethodInvocation.java:91)
    at org.spockframework.runtime.extension.MethodInvocation.proceed(MethodInvocation.java:85)
    at org.spockframework.runtime.extension.builtin.AbstractRuleInterceptor$1.evaluate(AbstractRuleInterceptor.java:37)
    at grails.test.runtime.TestRuntimeJunitAdapter$1$2.evaluate(TestRuntimeJunitAdapter.groovy:48)
    at org.spockframework.runtime.extension.builtin.TestRuleInterceptor.intercept(TestRuleInterceptor.java:38)
    at org.spockframework.runtime.extension.MethodInvocation.proceed(MethodInvocation.java:84)
    at org.spockframework.util.ReflectionUtil.invokeMethod(ReflectionUtil.java:138)
    at org.spockframework.util.ReflectionUtil.invokeMethod(ReflectionUtil.java:138)
    at org.spockframework.runtime.extension.MethodInvocation.invokeTargetMethod(MethodInvocation.java:91)
    at org.spockframework.runtime.extension.MethodInvocation.proceed(MethodInvocation.java:85)
    at org.spockframework.runtime.extension.builtin.AbstractRuleInterceptor$1.evaluate(AbstractRuleInterceptor.java:37)
    at grails.test.runtime.TestRuntimeJunitAdapter$3$4.evaluate(TestRuntimeJunitAdapter.groovy:74)
    at org.spockframework.runtime.extension.builtin.ClassRuleInterceptor.intercept(ClassRuleInterceptor.java:38)
    at org.spockframework.runtime.extension.MethodInvocation.proceed(MethodInvocation.java:84)
    at org.junit.runners.Suite.runChild(Suite.java:127)
    at org.junit.runners.Suite.runChild(Suite.java:26)
    at org.junit.runners.ParentRunner$3.run(ParentRunner.java:238)
    at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:63)
    at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:236)
    at org.junit.runners.ParentRunner.access$000(ParentRunner.java:53)
    at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:229)
    at org.junit.runners.ParentRunner.run(ParentRunner.java:309)
    at org.junit.runner.JUnitCore.run(JUnitCore.java:160)
    at com.intellij.rt.execution.application.AppMain.main(AppMain.java:134)

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您应该坚持grails约定。因此，您可以将域类重命名为ContractedServiceDefinition，并使用原始域名表映射：

static mapping = { table:'contracted_service'}

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这听起来可能没有太大帮助，但您确实应该重命名该类。即使您可以阻止Grails将其视为服务，打开它的每个开发人员都会期望看到服务，而不是域类。命名很难！：）不仅如此，Grails还基于按约定编码的思想。当你打破惯例，你就打破了圣杯。（可以这么说）。我认为你应该重新命名域类。这很公平，我可能会继续前进，但我仍然有兴趣知道答案。让服务发现依赖于路径似乎是一件容易的事情，因为域对象和服务应该位于不同的路径上。我认为只有以服务结尾并放在该目录中的类才应该被识别为服务，这似乎与文档一致。在这种情况下，域类被识别为服务。对我来说好像是个虫子。