JsonIgnores,但在我看来,最好的解决方案是使用dto。也许可以看看简化样板文件。我也在HibernateJira中作为一个bug打开了这个主题。请看这里: @Entity @Table(name = "Top") public class Top
JsonIgnores,但在我看来,最好的解决方案是使用dto。也许可以看看简化样板文件。我也在HibernateJira中作为一个bug打开了这个主题。请看这里: @Entity @Table(name = "Top") public class Top,hibernate,Hibernate,JsonIgnores,但在我看来,最好的解决方案是使用dto。也许可以看看简化样板文件。我也在HibernateJira中作为一个bug打开了这个主题。请看这里: @Entity @Table(name = "Top") public class Top { @Id String id; @OneToMany(mappedBy = "top", fetch = FetchType.EAGER) List<Left> left = new Array
JsonIgnores,但在我看来,最好的解决方案是使用dto。也许可以看看简化样板文件。我也在HibernateJira中作为一个bug打开了这个主题。请看这里:
@Entity
@Table(name = "Top")
public class Top {
@Id
String id;
@OneToMany(mappedBy = "top", fetch = FetchType.EAGER)
List<Left> left = new ArrayList<>();
@OneToMany(mappedBy = "top", fetch = FetchType.EAGER)
List<Right> right = new ArrayList<>();
}
@Entity
@Table(name = "Left")
public class Left {
@Id
String id;
String parent;
@ManyToOne
@JoinColumn(name = "top_id")
Top top;
@OneToMany(mappedBy = "parent", fetch = FetchType.EAGER)
Set<Bottom> bottom;
}
@Entity
@Table(name = "Right")
public class Right {
@Id
String id;
String parent;
@ManyToOne
@JoinColumn(name = "top_id")
Top top;
@OneToMany(mappedBy = "parent", fetch = FetchType.EAGER)
Set<Bottom> bottom;
}