Java 文件不会从临时文件传输回原始文件

这是我的代码摘录。 我已经搜索了堆栈溢出，并完成了所有建议，即删除原始文件并将临时文件重命名为原始文件，我还尝试了writer.flush。下面是.txt文件的外观

成绩输入：

1) Bob Do, Comp, 18
2) Matt Well, computing, 100
3) Adam Smith, Computing, 99
4) Mike Frank-Jones, Drama, 69

MyTempFile：

Matt Well, computing, 100
Adam Smith, Computing, 99
Mike Frank-Jones, Drama, 69

删除后输入等级：

Bob Do, Comp, 18
Matt Well, computing, 100
Adam Smith, Computing, 99
Mike Frank-Jones, Drama, 69

为什么会这样？谢谢

    File deleteRecord = new File("GradeEnter.txt");
    reader = new BufferedReader(new FileReader(deleteRecord));

    File tempFile = new File("myTempFile.txt");
    BufferedWriter writer = new BufferedWriter(new FileWriter(tempFile));

    Scanner scanner = new Scanner(System.in);
    System.out.print("To delete, please Enter First Name: ");
    firstNameDelete = scanner.nextLine();
    System.out.print("Please Enter Surname: ");
    lastNameDelete = scanner.nextLine();

    String currentLine;

    while((currentLine = reader.readLine()) != null) {
        if(currentLine.contains(firstNameDelete) && currentLine.contains(lastNameDelete)) continue;
        writer.write(currentLine);
        writer.newLine();
    }
    reader.close(); 
    writer.close();
    deleteRecord.delete();
    tempFile.renameTo(deleteRecord);

---

既然临时文件应该被删除，你怎么能看到它呢？结论：重命名没有发生。不要忽略delete和renameTo返回的布尔值。为什么File.delete在删除失败时不会引发异常？@JBNizet我当时打开了临时文件。当尝试关闭它时，仍然没有任何结果happens@Adamdo Boolean deletedSuccessfully=deleteRecord.delete；并打印DeletedSuccessfully的值，该值应为true，以便代码正常工作。与renamedSuccessfully相同=tempFile.renameTodeleteRecord；您还可以将这两行代码粘在一个try块中，看看是否可以捕获一个异常，该异常将告诉您到底出了什么问题。看见