Java Can'；第二个病例一个多个一个？

我正在尝试存储用户的订单集合。一个用户可能有多个订单，但一个订单只有一个用户。因此形成了1-M关系。Items和ItemOrders之间也存在相同的关系，ItemOrder由一个Item和要订购的Item数量组成。因此，一个ItemOrder有一个项目，但一个项目可以有多个ItemOrder

在我的测试套件中，我成功地正确地创建了Items和ItemOrders。然而，当我扩展测试以同时创建用户和订单时，我得到了“订单”的SQLSyntaxErrorException。。。这很奇怪，因为它应该是完全相同的程序来实现这两个结果。。。我不知道我做错了什么，有什么想法吗

@Entity
public class ItemEntity implements EntityInt {
    @Id
    @GeneratedValue(generator = "incrementor")
    @Column(name = "item_id", unique = true)
    public int id;

    @OneToMany(mappedBy="item")
    public Set<OrderItemEntity> orderItems = new HashSet<>();

}

@Entity
public class OrderItemEntity implements EntityInt {

    @Id
    @GeneratedValue(generator = "incrementor")
    @Column(name = "order_item_id", unique = true)
    public int id;

    @Column(name = "amount", nullable = false)
    public int amount;

    @ManyToOne
    @JoinColumn(name="item_id", nullable = false)
    private ItemEntity item;

    public OrderItemEntity(ItemEntity item, int amount) {
        this.setItem(item);
        this.amount = amount;
    }

    public void setItem(ItemEntity item) {
        if (this.item != null)
            this.item.orderItems.remove(this);
        this.item = item;
        this.item.orderItems.add(this);
    }
}

@Entity
public class OrderEntity implements EntityInt {

    @Id
    @GeneratedValue(generator = "incrementor")
    @Column(name = "order_id", unique = true)
    public int id;

    @ManyToOne
    @JoinColumn(name="user_id", nullable = false)
    public UserEntity user;

    public UserEntity getUser() {
        return user;
    }

    public void setUser(UserEntity user) {
        if (this.user != null)
            this.user.orders.remove(this);
        this.user = user;
        this.user.orders.add(this);
    }
}

@Entity
public class UserEntity implements EntityInt {

        @Id
        @GeneratedValue(generator = "incrementor")
        @Column(name = "user_id", unique = true)
        public int id;

        @OneToMany(mappedBy="user")
        public Set<OrderEntity> orders = new HashSet<>();

}

EntityInt包含基本DAO主要用于执行CRUD操作的方法。它包含诸如getId（）、getVersion（）、createVerifyIsUnqieuQuery（）等内容

BasicDao是主要的存储库访问类，由itemsDao、UsersDao等扩展。这是测试用例使用的BasicDao的相关部分：

BasicDao.java

private static final String PERSISTENCE_UNIT_NAME = "org.hibernate.lab1_web_shop.jpa";

    public static EntityManagerFactory getEntityManagerFactory() {
        return  Persistence.createEntityManagerFactory(PERSISTENCE_UNIT_NAME);
    }

    public static EntityInt insert(EntityInt entity) throws Exception {
        EntityManagerFactory factory = getEntityManagerFactory();
        EntityManager em = factory.createEntityManager();
        try {
            em.getTransaction().begin();
            Query isUniqueQuery = entity.createVerifyIsUniqueQuery(em);
            if (isUniqueQuery != null) {
                List<EntityInt> resultList = isUniqueQuery.getResultList();
                if (resultList.size() == 0) {
                    entity.beforeInsert(em);
                    em.persist(entity);
                } else {
                    entity = null;
                }
            } else {
                // There is no uniqueness filter so we insert it as is
                entity.beforeInsert(em);
                em.persist(entity);
            }
            em.getTransaction().commit();
            // Returns the persistent entity along with any database modified attributes
            return entity;
        } catch (Exception e) {
            em.getTransaction().rollback();
            throw new Exception(e);
        } finally {
            em.close();
        }
    }

我还测试了删除BasicDao并在一次提交中完成所有操作，但仍然会重复相同的错误。

---

问题是，我将表命名为“Order”。这是从上面的堆栈跟踪中获得的。

我用一个小小的spring启动应用程序重现了您的实体和测试：一切正常！您的帖子需要补充：例如，整个stacktrace。此外，您没有解释什么是EntityInt，基本DAO是如何实现的，等等。感谢您为我检查这一部分。我会调查一下BasicDao，看看是否有错误。我已经附加了更多与测试相关的部分以及堆栈跟踪中的原因。

private static final String PERSISTENCE_UNIT_NAME = "org.hibernate.lab1_web_shop.jpa";

    public static EntityManagerFactory getEntityManagerFactory() {
        return  Persistence.createEntityManagerFactory(PERSISTENCE_UNIT_NAME);
    }

    public static EntityInt insert(EntityInt entity) throws Exception {
        EntityManagerFactory factory = getEntityManagerFactory();
        EntityManager em = factory.createEntityManager();
        try {
            em.getTransaction().begin();
            Query isUniqueQuery = entity.createVerifyIsUniqueQuery(em);
            if (isUniqueQuery != null) {
                List<EntityInt> resultList = isUniqueQuery.getResultList();
                if (resultList.size() == 0) {
                    entity.beforeInsert(em);
                    em.persist(entity);
                } else {
                    entity = null;
                }
            } else {
                // There is no uniqueness filter so we insert it as is
                entity.beforeInsert(em);
                em.persist(entity);
            }
            em.getTransaction().commit();
            // Returns the persistent entity along with any database modified attributes
            return entity;
        } catch (Exception e) {
            em.getTransaction().rollback();
            throw new Exception(e);
        } finally {
            em.close();
        }
    }

Caused by: javax.persistence.RollbackException: Error while committing the transaction
Caused by: javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not execute statement
Caused by: org.hibernate.exception.SQLGrammarException: could not execute statement
Caused by: java.sql.SQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Order (user_id, version, order_id) values (9, 0, 10)' at line 1