如何在java中设置数组中JButtons的颜色？

假设有一个名称按钮数组：
私有JButton按钮[]=新JButton[9]
如何将此数组中所有按钮的颜色设置为蓝色

这是我的全部代码：这是一个使用按钮的井字游戏

import java.awt.*; 
import java.awt.event.*;
import javax.swing.*;
import java.awt.BorderLayout;

public class TicTacToe implements ActionListener {
private JButton buttons[] = new JButton[9];
private JFrame window = new JFrame("Tic Tac Toe");
private boolean win = false;
private int count = 0;
private int Xwins = 0, Owins = 0;
private String letter = "";
private int[][] winCombinations = new int[][] {
        {0, 1, 2}, {3, 4, 5}, {6, 7, 8}, //horizontal wins
        {0, 3, 6}, {1, 4, 7}, {2, 5, 8}, //vertical wins
        {0, 4, 8}, {2, 4, 6}                     //diagonal wins
};
String name1 = JOptionPane.showInputDialog("Please enter first player's name");
String name2 = JOptionPane.showInputDialog("Please enter second player's name");

public TicTacToe(){
    JOptionPane.showMessageDialog(null,"Remember Player 1 is X and Player 2 is O.");
    window.setSize(300,300);
    window.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    window.setLayout(new GridLayout(3,3));
    window.setVisible(true);


      for(int i=0; i<=8; i++){
          buttons[i] = new JButton();
          window.add(buttons[i]);
          buttons[i].addActionListener(this);
          buttons[i].setBackground(Color.MAGENTA);
  }
      for (JButton button: buttons) {
           button.setBackground(Color.BLUE);
        }

}

public void actionPerformed(ActionEvent event) {
        count++;
        if(count % 2 == 0){
            letter = "O";

        }else{
            letter = "X";
        }
         JButton pressedButton = (JButton)event.getSource(); 
         pressedButton.setText(letter);
         pressedButton.setEnabled(false);
         pressedButton.setBackground(Color.WHITE);


    //Determine who won
    for(int i=0; i<=7; i++){
        if( buttons[winCombinations[i][0]].getText().equals(buttons[winCombinations[i][1]].getText()) && 
                buttons[winCombinations[i][1]].getText().equals(buttons[winCombinations[i][2]].getText()) && 
                buttons[winCombinations[i][0]].getText() != ""){
                win = true;
            }
        }
        if(win == true){
            if(letter == "X"){
                JOptionPane.showMessageDialog(null, name1 + " wins the game!");
            }else{
                JOptionPane.showMessageDialog(null, name2 + " wins the game!");
            }
            playAgain();
        }else if(count == 9 && win == false){
            JOptionPane.showMessageDialog(null, "The game is tied!");
            playAgain();
        }
    } 

public void playAgain(){
    if(letter == "X"){
        Xwins++;
    }else{
        Owins++;
    }
    JOptionPane.showMessageDialog(null, name1 + " has won this many times: " + Xwins);
    JOptionPane.showMessageDialog(null, name2 + " has won this many times: " + Owins);
    int response = JOptionPane.showConfirmDialog(null, "Would you like to play again?", "Confirm", JOptionPane.YES_NO_OPTION, JOptionPane.QUESTION_MESSAGE);

    if(response == JOptionPane.YES_OPTION){
        reset();
    }else{
        System.exit(0);
    }
}

  public void reset() {
      for(int i = 0; i<=8; i++) {
              buttons[i].setText("");
              buttons[i].setEnabled(true); 
      }
      win = false;
      count = 0;
  }  

public static void main(String[] args){
    TicTacToe play = new TicTacToe();
   }
}

import java.awt.*；
导入java.awt.event.*；
导入javax.swing.*；
导入java.awt.BorderLayout；
公共类TicTacToe实现ActionListener{
私有JButton按钮[]=新JButton[9]；
专用JFrame窗口=新JFrame（“Tic Tac Toe”）；
私有布尔赢=假；
私有整数计数=0；
私有int Xwins=0，Owins=0；
私人字符串字母=”；
私有int[][]winCombinations=新int[][]{
{0,1,2}，{3,4,5}，{6,7,8}，//横向获胜
{0,3,6}，{1,4,7}，{2,5,8}，//垂直获胜
{0,4,8}，{2,4,6}//对角赢
};
String name1=JOptionPane.showInputDialog（“请输入第一个玩家的名字”）；
String name2=JOptionPane.showInputDialog（“请输入第二个玩家的名字”）；
公共交通{
showMessageDialog（null，“记住播放器1是X，播放器2是O.”；
设置窗口大小（300300）；
window.setDefaultCloseOperation（JFrame.EXIT_ON_CLOSE）；
setLayout（新的GridLayout（3,3））；
window.setVisible（true）；
对于（int i=0；i您需要在
reset
方法的
for
循环中将按钮颜色重置为蓝色：

buttons[i].setBackground(Color.blue);

下面是在我的机器和Mac OSX机器上生成的应用程序的外观。选择后按钮将变为白色：



如果您使用的是Mac OSX，则系统的外观可能也会出现问题。您可以在
main
方法中进行如下更改：

public static void main(String[] args){
   try {
      // Set cross-platform Java L&F (also called "Metal")
      UIManager.setLookAndFeel(UIManager.getCrossPlatformLookAndFeelClassName());
      // alternatively, the following should load the default L&F for your system
      //UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
   } catch (Exception e) {}

   TicTacToe play = new TicTacToe();
}

@808声音在正确的轨道上-一些标准的外观和感觉（例如Windows）使按钮的颜色变得奇怪/困难/难以更改

在程序开始时，尝试通过设置LAF

UIManager.setLookAndFeel(UIManager.getCrossPlatformLookAndFeelClassName()); 

这实际上是
按钮的副作用

背景和内容是两个不同的概念。虽然您可以更改背景颜色，但它可能不会更改按钮的内容区域。事实上，在不同的外观下，它的行为可能会有所不同

相反，使用
JLabel
，它更容易控制

public class TicTacToe implements ActionListener {

    private JLabel labels[] = new JLabel[9];
    private JFrame window = new JFrame("Tic Tac Toe");
    private boolean win = false;
    private int count = 0;
    private int Xwins = 0, Owins = 0;
    private String letter = "";
    private int[][] winCombinations = new int[][]{
        {0, 1, 2}, {3, 4, 5}, {6, 7, 8}, //horizontal wins
        {0, 3, 6}, {1, 4, 7}, {2, 5, 8}, //vertical wins
        {0, 4, 8}, {2, 4, 6} //diagonal wins
    };
    String name1 = JOptionPane.showInputDialog("Please enter first player's name");
    String name2 = JOptionPane.showInputDialog("Please enter second player's name");

    public TicTacToe() {
        JOptionPane.showMessageDialog(null, "Remember Player 1 is X and Player 2 is O.");
        window.setSize(300, 300);
        window.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        window.setLayout(new GridLayout(3, 3));
        window.setVisible(true);

        MouseHandler handler = new MouseHandler();

        for (int i = 0; i <= 8; i++) {
            labels[i] = new JLabel();
            labels[i].setOpaque(true);
            labels[i].setBorder(new LineBorder(Color.LIGHT_GRAY));
            labels[i].setHorizontalAlignment(JLabel.CENTER);
            window.add(labels[i]);
            labels[i].addMouseListener(handler);
            labels[i].setBackground(Color.MAGENTA);
        }
//        for (JButton button : buttons) {
//            button.setBackground(Color.BLUE);
//        }

    }

    public void actionPerformed(ActionEvent event) {
    }

    public void playAgain() {
        if (letter == "X") {
            Xwins++;
        } else {
            Owins++;
        }
        JOptionPane.showMessageDialog(null, name1 + " has won this many times: " + Xwins);
        JOptionPane.showMessageDialog(null, name2 + " has won this many times: " + Owins);
        int response = JOptionPane.showConfirmDialog(null, "Would you like to play again?", "Confirm", JOptionPane.YES_NO_OPTION, JOptionPane.QUESTION_MESSAGE);

        if (response == JOptionPane.YES_OPTION) {
            reset();
        } else {
            System.exit(0);
        }
    }

    public void reset() {
        for (int i = 0; i <= 8; i++) {
            labels[i].setText("");
            labels[i].setEnabled(true);
        }
        win = false;
        count = 0;
    }

    public class MouseHandler extends MouseAdapter {

        @Override
        public void mouseClicked(MouseEvent event) {
            count++;
            if (count % 2 == 0) {
                letter = "O";

            } else {
                letter = "X";
            }
            JLabel pressedLabel = (JLabel) event.getSource();
            pressedLabel.setText(letter);
            pressedLabel.setEnabled(false);
            pressedLabel.setBackground(Color.WHITE);


            //Determine who won
            for (int i = 0; i <= 7; i++) {
                if (labels[winCombinations[i][0]].getText().equals(labels[winCombinations[i][1]].getText())
                                && labels[winCombinations[i][1]].getText().equals(labels[winCombinations[i][2]].getText())
                                && labels[winCombinations[i][0]].getText() != "") {
                    win = true;
                }
            }
            if (win == true) {
                if (letter == "X") {
                    JOptionPane.showMessageDialog(null, name1 + " wins the game!");
                } else {
                    JOptionPane.showMessageDialog(null, name2 + " wins the game!");
                }
                playAgain();
            } else if (count == 9 && win == false) {
                JOptionPane.showMessageDialog(null, "The game is tied!");
                playAgain();
            }
        }
    }

    public static void main(String[] args) {
        EventQueue.invokeLater(new Runnable() {
            @Override
            public void run() {
                try {
                    UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
                } catch (Exception ex) {
                }

                TicTacToe play = new TicTacToe();
            }
        });
    }
}


public类TicTacToe实现ActionListener{
私有JLabel标签[]=新JLabel[9]；
专用JFrame窗口=新JFrame（“Tic Tac Toe”）；
私有布尔赢=假；
私有整数计数=0；
私有int Xwins=0，Owins=0；
私人字符串字母=”；
私有int[][]winCombinations=新int[][]{
{0,1,2}，{3,4,5}，{6,7,8}，//横向获胜
{0,3,6}，{1,4,7}，{2,5,8}，//垂直获胜
{0,4,8}，{2,4,6}//对角赢
};
String name1=JOptionPane.showInputDialog（“请输入第一个玩家的名字”）；
String name2=JOptionPane.showInputDialog（“请输入第二个玩家的名字”）；
公共交通{
showMessageDialog（null，“记住播放器1是X，播放器2是O.”；
设置窗口大小（300300）；
window.setDefaultCloseOperation（JFrame.EXIT_ON_CLOSE）；
setLayout（新的GridLayout（3,3））；
window.setVisible（true）；
MouseHandler handler=新的MouseHandler（）；
对于（int i=0；i Hm，这很奇怪。所以当窗口第一次出现时，上面所有的按钮都是灰色的？当您单击它们时它们会改变颜色吗？您是如何构建项目的？也就是说，您是使用Eclipse还是从命令行编译？还有，您使用的是什么版本的Java？我使用的是Eclipse。我如何确定Java的版本我正在使用？在Eclipse中，您可以进入“窗口”菜单，然后选择“首选项”->“Java”->“已安装的JRE”。这应该会显示一个JRE列表，并选中默认的JRE。嗯。我认为它是Java SE 7。为了准确使用，我会在按钮中放置彩色图标，而不知道如何绘制
X
或
O
或无符号。：）