未检测到XmlJavaTypeAdapter
对于JAXB专家来说,希望这是一个简单的例子: 我试图封送一个不可修改的类,它没有定义默认的无参数构造函数。我已经定义了一个未检测到XmlJavaTypeAdapter,java,jaxb,Java,Jaxb,对于JAXB专家来说,希望这是一个简单的例子: 我试图封送一个不可修改的类,它没有定义默认的无参数构造函数。我已经定义了一个XmlAdapter实现,但它似乎没有被接受。我提出了一个简单的自包含示例,但仍然无法奏效。谁能告诉我哪里做错了 不可变类 @XmlJavaTypeAdapter(FooAdapter.class) @XmlRootElement public class Foo { private final String name; private final int age;
XmlAdapter
实现,但它似乎没有被接受。我提出了一个简单的自包含示例,但仍然无法奏效。谁能告诉我哪里做错了
不可变类
@XmlJavaTypeAdapter(FooAdapter.class)
@XmlRootElement
public class Foo {
private final String name;
private final int age;
public Foo(String name, int age) {
this.name = name;
this.age = age;
}
public String getName() { return name; }
public int getAge() { return age; }
}
适配器和值类型
public class FooAdapter extends XmlAdapter<AdaptedFoo, Foo> {
public Foo unmarshal(AdaptedFoo af) throws Exception {
return new Foo(af.getName(), af.getAge());
}
public AdaptedFoo marshal(Foo foo) throws Exception {
return new AdaptedFoo(foo);
}
}
class AdaptedFoo {
private String name;
private int age;
public AdaptedFoo() {}
public AdaptedFoo(Foo foo) {
this.name = foo.getName();
this.age = foo.getAge();
}
@XmlAttribute
public String getName() { return name; }
public void setName(String name) { this.name = name; }
@XmlAttribute
public int getAge() { return age; }
public void setAge(int age) { this.age = age; }
}
com.sun.xml.internal.bind.v2.runtime.IllegalAnnotationsException: 1 counts of IllegalAnnotationExceptions
Foo does not have a no-arg default constructor.
this problem is related to the following location:
at Foo
at com.sun.xml.internal.bind.v2.runtime.IllegalAnnotationsException$Builder.check(IllegalAnnotationsException.java:91)
at com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl.getTypeInfoSet(JAXBContextImpl.java:451)
at com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl.<init>(JAXBContextImpl.java:283)
at com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl.<init>(JAXBContextImpl.java:126)
at com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl$JAXBContextBuilder.build(JAXBContextImpl.java:1142)
at com.sun.xml.internal.bind.v2.ContextFactory.createContext(ContextFactory.java:130)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:601)
at javax.xml.bind.ContextFinder.newInstance(ContextFinder.java:248)
at javax.xml.bind.ContextFinder.newInstance(ContextFinder.java:235)
at javax.xml.bind.ContextFinder.find(ContextFinder.java:445)
at javax.xml.bind.JAXBContext.newInstance(JAXBContext.java:637)
at javax.xml.bind.JAXBContext.newInstance(JAXBContext.java:584)
at Marshal2.main(Marshal2.java:11)
堆栈跟踪
public class FooAdapter extends XmlAdapter<AdaptedFoo, Foo> {
public Foo unmarshal(AdaptedFoo af) throws Exception {
return new Foo(af.getName(), af.getAge());
}
public AdaptedFoo marshal(Foo foo) throws Exception {
return new AdaptedFoo(foo);
}
}
class AdaptedFoo {
private String name;
private int age;
public AdaptedFoo() {}
public AdaptedFoo(Foo foo) {
this.name = foo.getName();
this.age = foo.getAge();
}
@XmlAttribute
public String getName() { return name; }
public void setName(String name) { this.name = name; }
@XmlAttribute
public int getAge() { return age; }
public void setAge(int age) { this.age = age; }
}
com.sun.xml.internal.bind.v2.runtime.IllegalAnnotationsException: 1 counts of IllegalAnnotationExceptions
Foo does not have a no-arg default constructor.
this problem is related to the following location:
at Foo
at com.sun.xml.internal.bind.v2.runtime.IllegalAnnotationsException$Builder.check(IllegalAnnotationsException.java:91)
at com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl.getTypeInfoSet(JAXBContextImpl.java:451)
at com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl.<init>(JAXBContextImpl.java:283)
at com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl.<init>(JAXBContextImpl.java:126)
at com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl$JAXBContextBuilder.build(JAXBContextImpl.java:1142)
at com.sun.xml.internal.bind.v2.ContextFactory.createContext(ContextFactory.java:130)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:601)
at javax.xml.bind.ContextFinder.newInstance(ContextFinder.java:248)
at javax.xml.bind.ContextFinder.newInstance(ContextFinder.java:235)
at javax.xml.bind.ContextFinder.find(ContextFinder.java:445)
at javax.xml.bind.JAXBContext.newInstance(JAXBContext.java:637)
at javax.xml.bind.JAXBContext.newInstance(JAXBContext.java:584)
at Marshal2.main(Marshal2.java:11)
com.sun.xml.internal.bind.v2.runtime.IllegalAnnotationsException:1次illegalannotationException计数
Foo没有无参数默认构造函数。
此问题与以下位置有关:
在福
位于com.sun.xml.internal.bind.v2.runtime.IllegalAnnotationsException$Builder.check(IllegalAnnotationsException.java:91)
位于com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl.getTypeInfoSet(JAXBContextImpl.java:451)
位于com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl.(JAXBContextImpl.java:283)
位于com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl.(JAXBContextImpl.java:126)
位于com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl$JAXBContextBuilder.build(JAXBContextImpl.java:1142)
位于com.sun.xml.internal.bind.v2.ContextFactory.createContext(ContextFactory.java:130)
在sun.reflect.NativeMethodAccessorImpl.invoke0(本机方法)处
在sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)中
在sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)中
位于java.lang.reflect.Method.invoke(Method.java:601)
位于javax.xml.bind.ContextFinder.newInstance(ContextFinder.java:248)
位于javax.xml.bind.ContextFinder.newInstance(ContextFinder.java:235)
位于javax.xml.bind.ContextFinder.find(ContextFinder.java:445)
位于javax.xml.bind.JAXBContext.newInstance(JAXBContext.java:637)
位于javax.xml.bind.JAXBContext.newInstance(JAXBContext.java:584)
位于Marshal2.main(Marshal2.java:11)
请注意,我使用的是JDK 1.7.0_05。以下内容应该会有所帮助: FOO作为根对象 在类型级别指定
@XmlJavaTypeAdapter
时,它仅适用于引用该类的字段/属性,而不适用于该类的实例是XML树中的根对象时。这意味着您必须自己将Foo
转换为AdaptedFoo
,并在AdaptedFoo
上创建JAXBContext
,而不是Foo
封送
package forum11966714;
import javax.xml.bind.*;
public class Marshal {
public static void main(String[] args) {
Foo foo = new Foo("Adam", 34);
try {
JAXBContext jaxbContext = JAXBContext.newInstance(AdaptedFoo.class);
Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
// output pretty printed
jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
jaxbMarshaller.marshal(new AdaptedFoo(foo), System.out);
} catch (JAXBException e) {
e.printStackTrace();
}
}
}
适配食物
您需要将@XmlRootElement
注释添加到AdaptedFoo
类中。您可以从Foo
类中删除相同的注释
package forum11966714;
import javax.xml.bind.annotation.*;
@XmlRootElement
class AdaptedFoo {
private String name;
private int age;
public AdaptedFoo() {
}
public AdaptedFoo(Foo foo) {
this.name = foo.getName();
this.age = foo.getAge();
}
@XmlAttribute
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
@XmlAttribute
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
}
FOO作为嵌套对象 当
Foo
不是根对象时,一切都按照映射它的方式工作。我已经扩展了您的模型来演示这是如何工作的
栏
public class Marshal {
public static void main(String[] args) {
Foo foo = new Foo("Adam", 34);
try {
JAXBContext jaxbContext = JAXBContext.newInstance(Foo.class);
Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
// output pretty printed
jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
jaxbMarshaller.marshal(foo, System.out);
} catch (JAXBException e) {
e.printStackTrace();
}
}
}
package forum11966714;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class Bar {
private Foo foo;
public Foo getFoo() {
return foo;
}
public void setFoo(Foo foo) {
this.foo = foo;
}
}
演示
请注意,在引导JAXBContext
时,JAXB参考实现不允许您指定Foo
类
package forum11966714;
import java.io.File;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;
import javax.xml.bind.Unmarshaller;
public class Demo {
public static void main(String[] args) {
try {
JAXBContext jaxbContext = JAXBContext.newInstance(Bar.class);
Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
File xml = new File("src/forum11966714/input.xml");
Bar bar = (Bar) jaxbUnmarshaller.unmarshal(xml);
Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
jaxbMarshaller.marshal(bar, System.out);
} catch (JAXBException e) {
e.printStackTrace();
}
}
}
input.xml/Output
<?xml version="1.0" encoding="UTF-8"?>
<bar>
<foo name="Jane Doe" age="35"/>
</bar>
我知道情况并非如此,但如果在字段中放置@XmlJavaTypeAdapter时出现此类错误,请检查是否指定了名称空间。你可能需要它 在我的情况下,这不起作用:
@XmlElement(name = "Expiration")
@XmlJavaTypeAdapter(DateAdapter.class)
private Date expiration;
在指定命名空间之前:
@XmlElement(name = "Expiration", namespace="http://site/your.namespace")
@XmlJavaTypeAdapter(DateAdapter.class)
private Date expiration;
谢谢布莱斯!(我想我最初看的是你的博客)。看起来问题是我在引导过程中将Foo.class指定给JAXBContext。遗憾的是,JAXB在这一点上无法工作,因为我已经为Foo指定了一个适配器。。。使引导有点复杂。@b尽管你似乎是这个关于编组/解编的难题的专家)也许你可以在我的问题上给我一些指导。我有一个XML,它的根元素是
,里面有很多单类型元素,例如