Java 如何获取用户输入并将其显示在阵列上？

我正在制作一张飞机座位表。我能够显示图表，并可以要求用户输入。我试着用他们的答案，把“X”放在他们输入状态的地方。我不知道如何将他们的输入显示在图表上，然后用X替换

import java.util.Scanner;

class AirplaneSeating {
public static void main(String[] args) {
  String[][] seatingChart = new String[10][4];
  int rows = 10;
  int columns = 4;

  Scanner inStr = new Scanner(System.in);

  seatingChart = new String[rows][columns];

  seatingChart[0][0] = "A1";
  seatingChart[0][1] = "A2";
  seatingChart[0][2] = "A3";
  seatingChart[0][3] = "A4";
  seatingChart[1][0] = "B1";
  seatingChart[1][1] = "B2";
  seatingChart[1][2] = "B3";
  seatingChart[1][3] = "B4";
  seatingChart[2][0] = "C1";
  seatingChart[2][1] = "C2";
  seatingChart[2][2] = "C3";
  seatingChart[2][3] = "C4";
  seatingChart[3][0] = "D1";
  seatingChart[3][1] = "D2";
  seatingChart[3][2] = "D3";
  seatingChart[3][3] = "D4";
  seatingChart[4][0] = "E1";
  seatingChart[4][1] = "E2";
  seatingChart[4][2] = "E3";
  seatingChart[4][3] = "E4";
  seatingChart[5][0] = "F1";
  seatingChart[5][1] = "F2";
  seatingChart[5][2] = "F3";
  seatingChart[5][3] = "F4";
  seatingChart[6][0] = "G1";
  seatingChart[6][1] = "G2";
  seatingChart[6][2] = "G3";
  seatingChart[6][3] = "G4";
  seatingChart[7][0] = "H1";
  seatingChart[7][1] = "H2";
  seatingChart[7][2] = "H3";
  seatingChart[7][3] = "H4";
  seatingChart[8][0] = "I1";
  seatingChart[8][1] = "I2";
  seatingChart[8][2] = "I3";
  seatingChart[8][3] = "I4";
  seatingChart[9][0] = "J1";
  seatingChart[9][1] = "J2";
  seatingChart[9][2] = "J3";
  seatingChart[9][3] = "J4";

  for(int i = 0; i < rows ; i++) {
    for(int j = 0; j < columns ; j++) {
       System.out.print(seatingChart[i][j] + " ");
    }
    System.out.println("");
  }

  System.out.println("What seat would you like to reserve? ");
  String str = inStr.nextLine();

  System.out.println("You chose: " + str);      

  }   
}

import java.util.Scanner；
飞机等级{
公共静态void main（字符串[]args）{
字符串[][]座位图表=新字符串[10][4]；
int行=10；
int列=4；
扫描仪安装=新扫描仪（System.in）；
seatingChart=新字符串[行][列]；
座位图[0][0]=“A1”；
座位图[0][1]=“A2”；
海图[0][2]=“A3”；
座位图[0][3]=“A4”；
座位图[1][0]=“B1”；
座位图[1][1]=“B2”；
座位图[1][2]=“B3”；
座位图[1][3]=“B4”；
座位图[2][0]=“C1”；
座位图[2][1]=“C2”；
座位图[2][2]=“C3”；
座位图[2][3]=“C4”；
座位图[3][0]=“D1”；
座位图[3][1]=“D2”；
座位图[3][2]=“D3”；
座位图[3][3]=“D4”；
海图[4][0]=“E1”；
座位图[4][1]=“E2”；
座位图[4][2]=“E3”；
海图[4][3]=“E4”；
座位图[5][0]=“F1”；
座位图[5][1]=“F2”；
座位图[5][2]=“F3”；
座位图[5][3]=“F4”；
座位图[6][0]=“G1”；
座位图[6][1]=“G2”；
座位图[6][2]=“G3”；
座位图[6][3]=“G4”；
座位图[7][0]=“H1”；
座位图[7][1]=“H2”；
座位图[7][2]=“H3”；
海图[7][3]=“H4”；
座位图[8][0]=“I1”；
座位图[8][1]=“I2”；
座位图[8][2]=“I3”；
座位图[8][3]=“I4”；
座位图[9][0]=“J1”；
座位图[9][1]=“J2”；
海图[9][2]=“J3”；
座位图[9][3]=“J4”；
对于（int i=0；i

确保str是两个字符。取第一个字符（我猜它是一个字母字符），将其转换成一个数字，并将其存储为一个变量（比如，x）。对第二个字符（比如y）执行相同的操作。将座位图[x][y]=“x”设置为“x”，然后再次运行显示循环

---

我希望这不是一个太具体的答案，因为这显然是家庭作业。

你只是想以任何方式显示吗？ 您希望如何输入？有办法吗

您只需解析扫描器输入，并告诉用户像代码一样放置行、列

//Example: Input: 6,2
//Split the user input
String[] input = str.split(",");
//parse first number to make it the row
int rowuser = Integer.parseInt(input[0].trim());
//parse second number to make it the column
int columnuser = Integer.parseInt(input[1].trim());
//replace with "X" value the seatingChart[row][column]
seatingChart[rowuser][columnuser] = "X"

---

但是您仍然需要一个循环来再次显示座位表。

考虑创建将行字母映射到相应数字的

HashMap

。给定用户输入，获取第一个字符并从哈希映射中获取适当的行索引。使用库函数将第二个字符转换为

int

。现在，您的数组中有了索引，可以更改有问题的值。

查看您的程序和座位的结构方式，您可以通过简单地解析和存储输入来实现这一点

char firstChar = str.toUpperCase().charAt(0);
char secondChar = str.charAt(1);
int first = ((int) firstChar) - 101; // ascii value - 101 for upper case A
int second = ((int) secondChar) - 1; // cast the character to an int, then -1 because it's 0 indexed.

那么，设置该值所需做的就是

seatingChart[first][second] = "X";

---

然后你可以把它再打印出来。

这段代码可能会有帮助

假设在定义座椅时给出输入。例：H4

Scanner sc = new Scanner(System.in);
String input = sc.nextLine();
int x = (int)input.charAt(0)-65; //since 'A' has ASCII value of 65
int y = (int)input.charAt(1)-49; //since '0' has ASCII value of 49
// update seatingChart[x][y]

---

你可以初始化这个

  seatingChart = new String[rows][columns];

  seatingChart[0][0] = "A1";
  seatingChart[0][1] = "A2";
  seatingChart[0][2] = "A3";
  seatingChart[0][3] = "A4";
  seatingChart[1][0] = "B1";
  seatingChart[1][1] = "B2";
  seatingChart[1][2] = "B3";
  seatingChart[1][3] = "B4";
  seatingChart[2][0] = "C1";
  seatingChart[2][1] = "C2";
  seatingChart[2][2] = "C3";
  seatingChart[2][3] = "C4";
  seatingChart[3][0] = "D1";
  seatingChart[3][1] = "D2";
  seatingChart[3][2] = "D3";
  seatingChart[3][3] = "D4";
  seatingChart[4][0] = "E1";
  seatingChart[4][1] = "E2";
  seatingChart[4][2] = "E3";
  seatingChart[4][3] = "E4";
  seatingChart[5][0] = "F1";
  seatingChart[5][1] = "F2";
  seatingChart[5][2] = "F3";
  seatingChart[5][3] = "F4";
  seatingChart[6][0] = "G1";
  seatingChart[6][1] = "G2";
  seatingChart[6][2] = "G3";
  seatingChart[6][3] = "G4";
  seatingChart[7][0] = "H1";
  seatingChart[7][1] = "H2";
  seatingChart[7][2] = "H3";
  seatingChart[7][3] = "H4";
  seatingChart[8][0] = "I1";
  seatingChart[8][1] = "I2";
  seatingChart[8][2] = "I3";
  seatingChart[8][3] = "I4";
  seatingChart[9][0] = "J1";
  seatingChart[9][1] = "J2";
  seatingChart[9][2] = "J3";
  seatingChart[9][3] = "J4";

像这样：

    String[][] seatingChart = new String[rows][columns];
    for(int i = 0; i < rows; i++) {
        for(int j = 0; j < columns; j++) {
            seatingChart[i][j] = "" + ((char)('A' + i)) + ((char)('1' + j));
        }
    }

然后您只需遍历数组，并找到匹配项：

  for(int i = 0; i < rows ; i++) {
    for(int j = 0; j < columns ; j++) {
       if(seatingChart[i][j].equals(str)) {
           System.out.print("XX" + " ");
       } else {
           System.out.print(seatingChart[i][j] + " ");
       }
    }
    System.out.println("");
  }

for（int i=0；i

您卡在什么部位？您是否在

str

中正确地获取了值，但不知道如何将其转换为数组索引？您需要使用不同的数据结构，因为您还需要存储状态。您希望将

“x”

而不是字符串

“A1”

，

“H3”

等。这取决于用户给出的字符串中的哪一个？感谢您的响应。是的，我得到str中的值，但不知道如何获取该值，并在座位表上将用户选择的值（str值）设为X。X是用来模拟座位有人坐。欢迎来到StackOverflow。虽然这可能是一个很好的答案，但对原始海报的澄清问题应该只放在帖子下方的评论中，而不要包含在答案中。

  for(int i = 0; i < rows ; i++) {
    for(int j = 0; j < columns ; j++) {
       if(seatingChart[i][j].equals(str)) {
           System.out.print("XX" + " ");
       } else {
           System.out.print(seatingChart[i][j] + " ");
       }
    }
    System.out.println("");
  }