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Java 如何使用GoogleGSON库解析下面给出的json_Java_Json_Gson - Fatal编程技术网

Java 如何使用GoogleGSON库解析下面给出的json

Java 如何使用GoogleGSON库解析下面给出的json,java,json,gson,Java,Json,Gson,我有这个JSON { "309":{ "productId":309, "name":"Heat Gear Polo"}, "315":{ "productId":310, "name":"Nike"}, "410":{ "productId":311, "name":"Armani"} } 示例模型类是 public class Product { private int productId; private String name; //

我有这个JSON

{
    "309":{ "productId":309,  "name":"Heat Gear Polo"},
    "315":{ "productId":310,  "name":"Nike"},
    "410":{ "productId":311,  "name":"Armani"}
}
示例模型类是

public class Product
{
   private int productId;
   private String name;

   // getter and setter for productId and name fields
}

如何在产品类中存储上述json数据?我应该为Product类使用数组还是
ArrayList
,如何使用Google Gson库使用它?

您需要将整个JSON字符串解析为
Map
,使用
TypeToken
指定泛型类型。下面是一些工作代码:

import java.lang.reflect.Type;
import java.util.Map;

import com.google.common.reflect.TypeToken;
import com.google.gson.Gson;

public class JsonTest {
  private static final String JSON = "{" +
    "\"309\":{ \"productId\":309,  \"name\":\"Heat Gear Polo\"}," +
    "\"315\":{ \"productId\":310,  \"name\":\"Nike\"},"+
    "\"410\":{ \"productId\":311,  \"name\":\"Armani\"}"+
  "}";

  public static void main(String... args) {
    Gson g = new Gson();
    Type type = new TypeToken<Map<Integer, Product>>(){}.getType();
    Map<Integer, Product> map = g.fromJson(JSON, type);

    System.out.println(map);
  }

  public static class Product
  {
     private int productId;
     private String name;

    @Override
    public String toString() {
      return String.format("Product [productId=%s, name=%s]", productId, name);
    }     
  }
}
import java.lang.reflect.Type;
导入java.util.Map;
导入com.google.common.reflect.TypeToken;
导入com.google.gson.gson;
公共类JsonTest{
私有静态最终字符串JSON=“{”+
“\'309\':{\'productId\':309,\'name\':\'Heat Gear Polo\'”+
“\'315\':{\'productId\':310,\'name\':\'Nike\'”+
“\'410\':{\'productId\':311,\'name\':\'Armani\'”+
"}";
公共静态void main(字符串…参数){
Gson g=新的Gson();
Type Type=new-TypeToken(){}.getType();
Map Map=g.fromJson(JSON,类型);
系统输出打印项次(map);
}
公共静态类产品
{
私有int-productId;
私有字符串名称;
@凌驾
公共字符串toString(){
返回String.format(“产品[productId=%s,name=%s]”,productId,name);
}     
}
}
公共静态void main(字符串[]args)
{
尝试
{
Gson Gson=新的Gson();
字符串json=“{\'309\”:{\'productId\”:309,\'name\:\'Heat Gear Polo\”,\'315\:{\'productId\”:310,\'name\:\'Nike\”,\'410\:{\'productId\”:311,\'name\:'Armani\};
Type Type=new-TypeToken(){}.getType();
Map myMap=gson.fromJson(json,类型);
System.out.println(myMap);
}
捕获(例外e)
{
//TODO:处理异常
}
}

我想唯一的方法就是从JSON生成一个映射,然后迭代映射。请提供一些示例代码。产品类是否需要“静态”?它可以是singleton吗?在我的示例中,我只将其作为一个内部类,以便将其放入一个文件中。显然,您可以在它自己的文件中拥有它自己的顶级类。
public static void main(String[] args)
{
    try
    {
        Gson gson = new Gson();

        String json = "{\"309\":{ \"productId\":309,  \"name\":\"Heat Gear Polo\"},\"315\":{ \"productId\":310,  \"name\":\"Nike\"},\"410\":{ \"productId\":311,  \"name\":\"Armani\"}}";
        Type type = new TypeToken<Map<String, Product>>(){}.getType();
        Map<String, Product> myMap = gson.fromJson(json, type);
        System.out.println(myMap);
    }
    catch (Exception e)
    {
        // TODO: handle exception
    }
}