Java 我如何创建一个fetch服务来从JIRA检索sprint报告?有人能帮我完成pic中的第二步吗?
因此,我必须创建一个fetch服务,使用jirarestapi从JIRA检索sprint报告(基本上是数据),到目前为止,我已经在springboot中使用rest模板完成了这项工作 SpringBootApplication.javaJava 我如何创建一个fetch服务来从JIRA检索sprint报告?有人能帮我完成pic中的第二步吗?,java,spring,spring-boot,jira-rest-api,jira-rest-java-api,Java,Spring,Spring Boot,Jira Rest Api,Jira Rest Java Api,因此,我必须创建一个fetch服务,使用jirarestapi从JIRA检索sprint报告(基本上是数据),到目前为止,我已经在springboot中使用rest模板完成了这项工作 SpringBootApplication.java import org.springframework.boot.SpringApplication; import org.springframework.boot.autoconfigure.SpringBootApplication; import or
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.springframework.boot.CommandLineRunner;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.boot.web.client.RestTemplateBuilder;
import org.springframework.context.annotation.Bean;
import org.springframework.web.client.RestTemplate;
@SpringBootApplication
public class SprintBootApplication {
private static final Logger log = LoggerFactory.getLogger(SprintBootApplication.class);
public static void main(String args[]) {
SpringApplication.run(SprintBootApplication.class);
}
@Bean
public RestTemplate restTemplate(RestTemplateBuilder builder) {
return builder.build();
}
@Bean
public CommandLineRunner run(RestTemplate restTemplate) throws Exception {
return args -> {
JiraDataFields data = restTemplate.getForObject(
"https://jira.mtvi.com/rest/api/2/search?fields=issuetype,customfield_10280,parent,key,summary,status,timeestimate,aggregatetimeoriginalestimate,assignee,subtasks&jql=project", JiraDataFields.class);
log.info(data.toString());
};
}
}```
JiraDataFields.class
```package com.sprint.SprintBoot;
public class JiraDataFields {
private int id;
private String workedBy;
}```