SpringWeb应用中jsp中的javax.el.PropertyNotFoundException，即使存在属性_Java_Spring_Jsp_Spring Mvc

SpringWeb应用中jsp中的javax.el.PropertyNotFoundException，即使存在属性

java spring jsp spring-mvc

SpringWeb应用中jsp中的javax.el.PropertyNotFoundException，即使存在属性,java,spring,jsp,spring-mvc,Java,Spring,Jsp,Spring Mvc,我是SpringMVC的新手，对javax.el.PropertyNotFoundException的错误有点迷茫，我目前在我的第一个测试应用程序中遇到了这个错误。我试图显示一个人员列表，然后按下一个按钮进入一个新页面，要求输入新的人员详细信息所以我选了个人模特 public class Person { private String firstName; private String lastName; public String getFirstName() { r

我是SpringMVC的新手，对javax.el.PropertyNotFoundException的错误有点迷茫，我目前在我的第一个测试应用程序中遇到了这个错误。我试图显示一个人员列表，然后按下一个按钮进入一个新页面，要求输入新的人员详细信息

所以我选了个人模特

    public class Person {

private String firstName;
private String lastName;


public String getFirstName() {
    return firstName;
}
public void setFirstName(String firstName) {
    this.firstName = firstName;
}
public String getLastName() {
    return lastName;
}
public void setLastName(String lastName) {
    this.lastName = lastName;
}

    }

每当用户请求新的人员输入时，就会调用addPersonInitial方法。此后，当用户填写表单时，提交由函数addPersonFinal处理。该函数应添加新条目并重定向回显示已有人员列表的页面

    @Controller
    @RequestMapping(value="person")
    public class PersonController{

@Autowired
private PersonService personservice;

@RequestMapping(value="viewAll", method=RequestMethod.GET)
public ModelAndView viewAll() {
    ModelAndView mav = new ModelAndView();
    mav.setViewName("viewAll");
    mav.addObject("persons", personservice.getAllPersons());
    return mav;
}

@RequestMapping(value="addPersonInitial", method = RequestMethod.GET)
public ModelAndView addPersonInitial() {
    ModelAndView mav = new ModelAndView();
    mav.setViewName("addPersonInitial");
    mav.addObject("person", new Person());
    return mav;
}

@RequestMapping(value="addPersonFinal", method = RequestMethod.POST)
public ModelAndView addPersonFinal(@ModelAttribute(value="person") Person person) {
    this.personservice.addPerson(person);
    return this.viewAll();
}

    }

jsp中的代码是

    <html>
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
    <title>Add Person Initial</title>
    </head> 
    <body>
    <table>
<tbody>
<form:form method="POST" action="addPersonFinal" commandName="person">
    <tr>
    <td><label for="firstName">First Name: </label><form:input path= "firstName" /> </td>
    <td><label for="lastName">Last Name: </label><form:input path="lastName" /></td>
    </tr>
    <tr>
        <td colspan="2"><input type="submit" value="Add" /></td>
    </tr>
</form:form>
</tbody>
    </table>
    </body>
    </html>

一切看起来都很好…试着清理和构建项目。运行服务器时，请确保服务器上有一个新版本。请提供简要的项目结构？

org.apache.jasper.JasperException: javax.el.PropertyNotFoundException: Property 'FirstName' not found on type net.viralpatel.spring3.model.Person
    org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:549)
    org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:470)
    org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
    org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
    org.springframework.web.servlet.view.InternalResourceView.renderMergedOutputModel(InternalResourceView.java:238)
    org.springframework.web.servlet.view.AbstractView.render(AbstractView.java:250)
    org.springframework.web.servlet.DispatcherServlet.render(DispatcherServlet.java:1060)
    org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:798)
    org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:716)
    org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:647)
    org.springframework.web.servlet.FrameworkServlet.doPost(FrameworkServlet.java:563)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:647)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:728)`enter code here`