Java流处理映射列表的总和值
我想确定行或更好的列的数量:构建一个映射列表的总和,比如list>rows 是否有可能对每个不同列的所有值求和?函数应返回一个映射,列为键,所有值之和为值Java流处理映射列表的总和值,java,functional-programming,java-stream,Java,Functional Programming,Java Stream,我想确定行或更好的列的数量:构建一个映射列表的总和,比如list>rows 是否有可能对每个不同列的所有值求和?函数应返回一个映射,列为键,所有值之和为值 summMap.get("columname") 假设我有以下地图列表: List<Map<String, Long>> mapList = new ArrayList(); Map<String, Object> map1 = new HashMap<>(); Map<String,
summMap.get("columname")
假设我有以下地图列表:
List<Map<String, Long>> mapList = new ArrayList();
Map<String, Object> map1 = new HashMap<>();
Map<String, Object> map2 = new HashMap<>();
Map<String, Object> map3 = new HashMap<>();
map1.put("col1", 90);
map1.put("col2", 50);
map1.put("col3", 10);
map2.put("col1", 90);
map2.put("col2", 50);
map2.put("col3", 10);
map3.put("col1", 90);
map3.put("col2", 50);
map3.put("col3", 10);
mapList.add(map1);
mapList.add(map2);
mapList.add(map3);
Map<String, Long> sum = mapList.stream().distinct().sum() // Example
// result i'm awaiting/expecting
Long sumVal1 = sum.get("col1"); // 270
Long sumVal2 = sum.get("col2"); // 150
Long sumVal3 = sum.get("col3"); // 30
Long sumVal=sum.getcol1 这是一个简单的解决方案,它将根据您的要求给出结果:
List<Map<String, Long>> mapList = new ArrayList();
Map<String, Long> map1 = new HashMap<>();
Map<String, Long> map2 = new HashMap<>();
Map<String, Long> map3 = new HashMap<>();
map1.put("col1", 90L);
map1.put("col2", 50L);
map1.put("col3", 10L);
map2.put("col1", 90L);
map2.put("col2", 50L);
map2.put("col3", 10L);
map3.put("col1", 90L);
map3.put("col2", 50L);
map3.put("col3", 10L);
mapList.add(map1);
mapList.add(map2);
mapList.add(map3);
Map<String, Long> sum = new HashMap<>();
mapList.forEach(map -> map.keySet().forEach(
s -> {
mapList.stream()
.collect(Collectors.groupingBy(foo -> s,
Collectors.summingLong(foo -> map.get(s)))).forEach(
(id, sumTargetCost) ->
sum.put(s, sumTargetCost)
);
}
));
Long sumVal1 = sum.get("col1"); // 270
Long sumVal2 = sum.get("col2"); // 150
Long sumVal3 = sum.get("col3"); // 30
System.out.println("SumVal1: " + sumVal1 + ", SumVal2: " + sumVal2 + ", SumVal3: " + sumVal3);
这不支持并行执行,但可以通过修改reduce中的最后一个参数来实现: 通过测试:
final List<Map<String, Long>> maps = new ArrayList<>();
Map<String, Long> map1 = new HashMap<>();
Map<String, Long> map2 = new HashMap<>();
map1.put("col1", 90L);
map1.put("col2", 50L);
map2.put("col1", 90L);
map2.put("col2", 50L);
map2.put("col3", 100L);
maps.add(map1);
maps.add(map2);
final Map<String, Long> sums = reduceLongs(maps);
assertEquals(180L, sums.get("col1").longValue());
assertEquals(100L, sums.get("col2").longValue());
assertEquals(100L, sums.get("col3").longValue());
这很简单
Map<String, Long> sum = mapList.stream()
.flatMap(m -> m.entrySet().stream())
.collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue, Long::sum));
Holger已经提供了一个干净的解决方案,但我认为您也可以尝试flatMap和groupingBy作为: 你问题的整体解决方案是:
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import static java.util.stream.Collectors.*;
public class ListMapSum {
public static void main(String... args) {
List<Map<String, Long>> mapList = new ArrayList();
Map<String, Long> map1 = new HashMap<>();
Map<String, Long> map2 = new HashMap<>();
Map<String, Long> map3 = new HashMap<>();
map1.put("col1", 90L);
map1.put("col2", 50L);
map1.put("col3", 10L);
map2.put("col1", 90L);
map2.put("col2", 50L);
map2.put("col3", 10L);
map3.put("col1", 90L);
map3.put("col2", 50L);
map3.put("col3", 10L);
mapList.add(map1);
mapList.add(map2);
mapList.add(map3);
Map<String, Long> sum = mapList.stream().flatMap(map -> map.entrySet().stream())
.collect(groupingBy(Map.Entry::getKey, summingLong(Map.Entry::getValue)));
Long sumVal1 = sum.get("col1"); // 270
Long sumVal2 = sum.get("col2"); // 150
Long sumVal3 = sum.get("col3"); // 30
}
}
显示您获得的代码。您的问题不清楚-请重新表述您的问题。因此,您有一个映射列表作为columnname、value,并且您希望每个唯一columnname的[value]之和。对吗?我为每个独特的列添加了一个示例Yes。
Map<String, Long> sum = mapList.stream().flatMap(map -> map.entrySet().stream())
.collect(groupingBy(Map.Entry::getKey, summingLong(Map.Entry::getValue)));
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import static java.util.stream.Collectors.*;
public class ListMapSum {
public static void main(String... args) {
List<Map<String, Long>> mapList = new ArrayList();
Map<String, Long> map1 = new HashMap<>();
Map<String, Long> map2 = new HashMap<>();
Map<String, Long> map3 = new HashMap<>();
map1.put("col1", 90L);
map1.put("col2", 50L);
map1.put("col3", 10L);
map2.put("col1", 90L);
map2.put("col2", 50L);
map2.put("col3", 10L);
map3.put("col1", 90L);
map3.put("col2", 50L);
map3.put("col3", 10L);
mapList.add(map1);
mapList.add(map2);
mapList.add(map3);
Map<String, Long> sum = mapList.stream().flatMap(map -> map.entrySet().stream())
.collect(groupingBy(Map.Entry::getKey, summingLong(Map.Entry::getValue)));
Long sumVal1 = sum.get("col1"); // 270
Long sumVal2 = sum.get("col2"); // 150
Long sumVal3 = sum.get("col3"); // 30
}
}