客户端无法向服务器Java套接字发送消息
我正在尝试使用客户端和服务器处理一个简单的项目,其中客户端发送一个字符串,服务器将反向发送回客户端。然而,他们在发送和接收信息时都被挂断了。所以我要告诉你我在程序中的位置,它在哪里停止…这是我的客户端和服务器的控制台输出 客户客户端无法向服务器Java套接字发送消息,java,sockets,Java,Sockets,我正在尝试使用客户端和服务器处理一个简单的项目,其中客户端发送一个字符串,服务器将反向发送回客户端。然而,他们在发送和接收信息时都被挂断了。所以我要告诉你我在程序中的位置,它在哪里停止…这是我的客户端和服务器的控制台输出 客户 Connecting to server... S: Connected to server at 4446 You sent Oranges, sending message... 服务器 Waiting for a connection... Connection
Connecting to server...
S: Connected to server at 4446
You sent Oranges, sending message...
服务器
Waiting for a connection...
Connection received from /127.0.0.1 on port 4446
Waiting for response...
我读过一些关于如何使用确切的消息输出和输入的文章。因此,就像客户机发送带有新行的输入一样,服务器应该期望在中读取该行。虽然我在代码中没有看到这一点,但我的直觉是这就是问题所在
我的代码如下
Client.java
import java.io.IOException;
import java.io.PrintWriter;
import java.net.Socket;
import java.net.UnknownHostException;
import java.util.Scanner;
public class Client
{
PrintWriter out;
Scanner conIn;
public static void main(String[] args) throws UnknownHostException, IOException
{
Client c = new Client();
c.run();
}
public void run() throws UnknownHostException, IOException
{
System.out.println("Connecting to server...");
Socket connection = new Socket("localhost", 4446); //Connects to server
out = new PrintWriter(connection.getOutputStream());
conIn = new Scanner(connection.getInputStream());
String msg = conIn.nextLine();
System.out.println(msg);
String s = "Oranges";
System.out.println("You sent " + s + ", sending message...");
out.println(s); //STOPS HERE
msg = conIn.nextLine();
System.out.println(msg);
out.flush();
}
}
Server.java
import java.io.IOException;
import java.io.PrintWriter;
import java.net.ServerSocket;
import java.net.Socket;
import java.util.Scanner;
public class Server implements Runnable
{
ServerSocket serverSocket;
Scanner in;
PrintWriter out;
Socket connection = null;
public static void main(String[] args)
{
Server s = new Server();
s.run();
}
public void run()
{
try
{
serverSocket = new ServerSocket(4446); //Create server
System.out.println("Waiting for a connection...");
this.connection = serverSocket.accept(); //Accept connection
System.out.println("Connection recieved from " + connection.getInetAddress() + " on port " + connection.getLocalPort());
out = new PrintWriter(connection.getOutputStream()); //Gets output to connection
out.flush();
in = new Scanner(connection.getInputStream()); //Gets input to connection
out.println("S: Connected to server at " + serverSocket.getLocalPort());
out.flush();
System.out.println("Waiting for response...");
String msg = in.nextLine(); //STOPS HERE
System.out.println("Message recieved! Reversing now.");
String rMsg = reverse(msg);
System.out.println("Returning message...");
out.println("S: Your message was: " + msg + " and it is now " + rMsg);
out.flush();
}
catch (IOException e)
{
e.printStackTrace();
}
}
public String reverse(String s)
{
String revS = "";
for(int i = s.length() - 1; i >= 0; i--)
{
revS = revS + s.charAt(i);
}
return revS;
}
}
Put
out.flush()在out.println之后的code>
如果您执行out.flush()代码>紧跟在out.println之后代码>?啊,这似乎奏效了,谢谢!我想他们会希望每次都堆叠起来,或者在你发送一堆输出后再做。但我想这并没有多大意义,哈哈。谢谢,当你在等待数据的交叉传输时,你不能“叠加”。最好使用线程来同时允许输出和输入。哦,好的,是的,这是设置线程的下一步,以便服务器可以处理多个客户端。@Carson您可以回答自己的问题并将其标记为已接受,这将向人们显示您不再需要有关问题的帮助。