Java 使用HtmlUnit登录LinkedIn并导航到Connections网页

目前我正在尝试使用HtmlUnit 2.20登录LinkedIn。但我无法登录。下面是我的代码

public static void Login(String username, String password) {
         final WebClient webClient = new WebClient(BrowserVersion.CHROME);
        try {

            final HtmlPage page = webClient.getPage "https://www.linkedin.com/secure/login");

            final HtmlForm form = page.getForms().get(0);
            final HtmlSubmitInput button = form.getInputByName("signin");
            final HtmlTextInput emailBtn = form.getInputByName("session_key");
            final HtmlPasswordInput passBtn = form.getInputByName("session_password");

            emailBtn.setValueAttribute(username);
            passBtn.setValueAttribute(password);

            final HtmlPage page2 = button.click();
            System.out.println(page2.getWebResponse().getContentAsString());

        } catch (Exception ex ){
            ex.printStackTrace();
        } 

    }

请您协助查找我的代码有什么问题，以及我登录后如何导航到另一个页面。

试试这个

在这里我找到了linkedin登录的解决方案

   try {
        String url = "https://www.linkedin.com/uas/login?goback=&trk=hb_signin";
        final WebClient webClient = new WebClient();
        webClient.getOptions().setJavaScriptEnabled(false);
        webClient.getOptions().setCssEnabled(false);

        final HtmlPage loginPage = webClient.getPage(url);
        //Get Form By name 
        final HtmlForm loginForm = loginPage.getFormByName("login");
        final HtmlSubmitInput button = loginForm.getInputByName("signin");
        final HtmlTextInput usernameTextField = loginForm.getInputByName("session_key");
        final HtmlPasswordInput passwordTextField = loginForm.getInputByName("session_password");
        usernameTextField.setValueAttribute(userName);//your Linkedin Username
        passwordTextField.setValueAttribute(password);//Your Linkedin Password
        final HtmlPage responsePage = button.click();
        String htmlBody = responsePage.getWebResponse().getContentAsString();
        System.out.println(htmlBody);
    } catch (Exception ex) {
        ex.printStackTrace();
    }

---

您是否尝试过

webClient.setAjaxController（新的NicelyResynchronizingAjaxController（））？我尝试了“webClient.setAjaxController（新的NicelyResynchronizingAjaxController（））”。但是我不能登录。