Java 序列化对象列表

我对如何序列化和反序列化问题对象列表感到困惑

我有一个Survey类，它有一个名为Questions的属性，这是一个Question对象列表

我希望能够序列化调查属性以及每个问题的所有属性

不幸的是，到目前为止，我没有运气，以下是我所拥有的。谢谢你的帮助

public void loadData(Boolean isSurvey) throws FileNotFoundException {
    System.out.println("Select a file: ");
    FileInputStream fileIn;

    if (isSurvey) {
        String fileName = listFiles("surveys").get(input.getIntInput(fileCount - 1));
        fileIn = new FileInputStream("surveys/" + fileName);
    } else {
        String fileName = listFiles("tests").get(input.getIntInput(fileCount - 1));
        fileIn = new FileInputStream("tests/" + fileName);
    }

    Question q = null;
    try
    {
        ObjectInputStream in = new ObjectInputStream(fileIn);
        q = (Question) in.readObject();
        in.close();
        fileIn.close();
    }catch(IOException i){
        i.printStackTrace();
    }catch(ClassNotFoundException c) {
        System.out.println("Not found");
        c.printStackTrace();
    }
    System.out.println("Deserialized Question...");
    System.out.println("prompt: " + q.prompt);
}

public void saveData(Survey survey, Test test, Boolean isSurvey, String fileName) {
    try {
        File surveyDir = new File("surveys");
        File testDir = new File("tests");

        if ((!(surveyDir.exists()) && isSurvey)) {
            System.out.println("Creating Survey directory. . .");
            surveyDir.mkdir();
        }
        if ((!(testDir.exists())) && !(isSurvey)) {
            System.out.println("Creating Test directory. . .");
            testDir.mkdir();
        }

        if (isSurvey) {
            FileOutputStream fileOut = new FileOutputStream("surveys/" + fileName);
            ObjectOutputStream out = new ObjectOutputStream(fileOut);

            for (Question question : survey.questions) {
                out.writeObject(survey.questions);
            }
            out.close();
            fileOut.close();
        } else {
            FileOutputStream fileOut = new FileOutputStream("tests/" + fileName);
            ObjectOutputStream out = new ObjectOutputStream(fileOut);

            for (Question question : test.questions) {
                out.writeObject(question);
            }
            out.close();
            fileOut.close();
        }


    } catch(IOException i) {
        i.printStackTrace();
    }
}

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您是否已经用java.io.Serializable实现了要编写的对象

我注意到的另一件事是，您编写了一个集合对象

for (Question question : survey.questions) {
    out.writeObject(survey.questions);
}

但你把它当作问题对象来读

for (Question question : survey.questions) {
    out.writeObject(survey.questions);
}

如果您编写的对象是集合。下面是一个示例，如果它是列表集合

q = (List<Question>) in.readObject();

---

不幸的是，我在发布时已经实现了它。谢谢你：什么样的收集是调查。问题。您可以直接强制转换，因为集合类已实现Serializable.survey.questions是ArrayList questions=new ArrayList“No luck”不是问题描述。再试一次。的副本不完整。

q = (List<Question>) in.readObject();