Java JUnit4看不到bean

Java JUnit4看不到bean,java,hibernate,spring,unit-testing,junit,Java,Hibernate,Spring,Unit Testing,Junit,我在类中使用@Bean和@Annotation,如下所示: @Transactional @Configuration public class UserDAO { @Bean public UserDAO userDAO() { return new UserDAO(); } private HibernateTemplate hibernateTemplate; @Autowired public void setS

我在类中使用@Bean和@Annotation,如下所示:

@Transactional
@Configuration
public class UserDAO {

    @Bean
    public UserDAO userDAO()
    {
        return new UserDAO();
    }
    private HibernateTemplate hibernateTemplate;

    @Autowired
    public void setSessionFactory(SessionFactory sessionFactory) {
        this.hibernateTemplate = new HibernateTemplate(sessionFactory);
    }

    public void Save(User s){
        this.hibernateTemplate.save(s);
    }
}
@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration (locations = {"classpath:**/spring-servlet.xml"})
@DependsOn("UserDAO")
@Transactional
@Configuration
public class UserDAOTest extends AbstractTransactionalDataSourceSpringContextTests {

    @Autowired
    private UserDAO userDAO;
    @Autowired
    private SessionFactory sessionFactory;

    public UserDAO getUserDAO() {
        return userDAO;
    }
    public void setUserDAO(UserDAO userDAO) {
        this.userDAO = userDAO;
    }
    public SessionFactory getSessionFactory() {
        return sessionFactory;
    }
    public void setSessionFactory(SessionFactory sessionFactory) {
        this.sessionFactory = sessionFactory;
    }


    @Test
    public void testSave() {
        User spr = new User();
        spr.setKzId(0);
        spr.setOpis("User test");
        spr.setPlan("Plan test");
        spr.setPolrocze(1);
        spr.setPrognoza1("test1");
        spr.setPrognoza2("test2");
        spr.setRok(2000);
        userDAO.Save(spr);
        User spr2 = userDAO.GetUserById(spr.getId());
        Assert.assertEquals("User test", spr2.getOpis());
    }

}
这是我的spring-servlet.xml。注意,我没有编写任何类似“userDAO”的bean:

<?xml  version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop"
    xmlns:context="http://www.springframework.org/schema/context"
    (...)

    <context:annotation-config />
    <tx:annotation-driven transaction-manager="txManager" />
    <bean id="txManager"
        class="org.springframework.orm.hibernate3.HibernateTransactionManager">
        <property name="sessionFactory">
            <ref local="sessionFactory" />
        </property>
    </bean>
    <bean id="jspViewResolver"
        (...)
    </bean>

    <bean id="pdfViewResolver" class="org.springframework.web.servlet.view.XmlViewResolver">
            (...)
    </bean> 

    <bean
        class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" />

    <bean class="org.springframework.jmx.export.MBeanExporter">
        <property name="autodetect" value="false" />
        <property name="assembler">
            <bean id="jmxAssembler"
                class="org.springframework.jmx.export.assembler.MetadataMBeanInfoAssembler">
                <property name="attributeSource">
                    <bean
                        class="org.springframework.jmx.export.annotation.AnnotationJmxAttributeSource" />
                </property>
            </bean>
        </property>

    </bean>
    <context:component-scan base-package="pl.edm.taskcards.spring" />
    <context:component-scan base-package="pl.raban.resource.spring" />

    <bean id="messageSource"
        class="org.springframework.context.support.ResourceBundleMessageSource"
        p:basename="messages" />

    <bean id="openSessionInViewInterceptor"
        class="org.springframework.orm.hibernate3.support.OpenSessionInViewInterceptor">
        <property name="sessionFactory" ref="sessionFactory" />
    </bean>


    <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource"
        (...)
    </bean>




    <bean id="sessionFactory"
        class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean">
        <property name="dataSource" ref="dataSource" />
        <property name="packagesToScan">
            <list>
                <value>pl.edm.taskcards.spring</value>
                <value>pl.raban.resource.spring</value>
            </list>
        </property>
        <property name="hibernateProperties">
            <props>
                <prop key="hibernate.dialect">org.hibernate.dialect.PostgreSQLDialect</prop>
                <prop key="hibernate.show_sql">true</prop>
                <prop key="hibernate.connection.useUnicode">true</prop>
                <prop key="hibernate.connection.characterEncoding">UTF-8</prop>
                <prop key="hibernate.jdbc.batch_size">0</prop>
                <prop key="hibernate.query.substitutions">true 1, false 0</prop>
            </props>
        </property>
    </bean>
    <tx:annotation-driven />

</beans>
但在我运行此测试后,出现了错误:


您需要为UserDao类声明一个bean。

您需要为UserDao类声明一个bean。

我认为您在这里混淆了一些机制。@Configuration类提供bean,但不应该是bean本身

使用@Component直接创建bean,或者将@Configuration注释放在另一个类上

了解更多有关概念的信息:

a b

但是它应该仍然有效,即使你混淆了概念

然而,问题应该在这里:

@ContextConfiguration (locations = {
    "file:/src/main/webapp/WEB-INF/spring-servlet.xml"})
两个问题: A. b如果您的spring上下文在WEB-INF中,则它不在类路径上,因此无法通过类路径找到:*/spring-servlet.xml。我不知道在单元/集成测试中访问这样一个上下文的标准方法是什么,但我会尝试以下方法:

@Transactional
@Configuration
public class UserDAO {

    @Bean
    public UserDAO userDAO()
    {
        return new UserDAO();
    }
    private HibernateTemplate hibernateTemplate;

    @Autowired
    public void setSessionFactory(SessionFactory sessionFactory) {
        this.hibernateTemplate = new HibernateTemplate(sessionFactory);
    }

    public void Save(User s){
        this.hibernateTemplate.save(s);
    }
}
@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration (locations = {"classpath:**/spring-servlet.xml"})
@DependsOn("UserDAO")
@Transactional
@Configuration
public class UserDAOTest extends AbstractTransactionalDataSourceSpringContextTests {

    @Autowired
    private UserDAO userDAO;
    @Autowired
    private SessionFactory sessionFactory;

    public UserDAO getUserDAO() {
        return userDAO;
    }
    public void setUserDAO(UserDAO userDAO) {
        this.userDAO = userDAO;
    }
    public SessionFactory getSessionFactory() {
        return sessionFactory;
    }
    public void setSessionFactory(SessionFactory sessionFactory) {
        this.sessionFactory = sessionFactory;
    }


    @Test
    public void testSave() {
        User spr = new User();
        spr.setKzId(0);
        spr.setOpis("User test");
        spr.setPlan("Plan test");
        spr.setPolrocze(1);
        spr.setPrognoza1("test1");
        spr.setPrognoza2("test2");
        spr.setRok(2000);
        userDAO.Save(spr);
        User spr2 = userDAO.GetUserById(spr.getId());
        Assert.assertEquals("User test", spr2.getOpis());
    }

}

请参见

我认为您在这里混淆了一些机制。@Configuration类提供bean,但不应该是bean本身

使用@Component直接创建bean,或者将@Configuration注释放在另一个类上

了解更多有关概念的信息:

a b

但是它应该仍然有效,即使你混淆了概念

然而,问题应该在这里:

@ContextConfiguration (locations = {
    "file:/src/main/webapp/WEB-INF/spring-servlet.xml"})
两个问题: A. b如果您的spring上下文在WEB-INF中,则它不在类路径上,因此无法通过类路径找到:*/spring-servlet.xml。我不知道在单元/集成测试中访问这样一个上下文的标准方法是什么,但我会尝试以下方法:

@Transactional
@Configuration
public class UserDAO {

    @Bean
    public UserDAO userDAO()
    {
        return new UserDAO();
    }
    private HibernateTemplate hibernateTemplate;

    @Autowired
    public void setSessionFactory(SessionFactory sessionFactory) {
        this.hibernateTemplate = new HibernateTemplate(sessionFactory);
    }

    public void Save(User s){
        this.hibernateTemplate.save(s);
    }
}
@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration (locations = {"classpath:**/spring-servlet.xml"})
@DependsOn("UserDAO")
@Transactional
@Configuration
public class UserDAOTest extends AbstractTransactionalDataSourceSpringContextTests {

    @Autowired
    private UserDAO userDAO;
    @Autowired
    private SessionFactory sessionFactory;

    public UserDAO getUserDAO() {
        return userDAO;
    }
    public void setUserDAO(UserDAO userDAO) {
        this.userDAO = userDAO;
    }
    public SessionFactory getSessionFactory() {
        return sessionFactory;
    }
    public void setSessionFactory(SessionFactory sessionFactory) {
        this.sessionFactory = sessionFactory;
    }


    @Test
    public void testSave() {
        User spr = new User();
        spr.setKzId(0);
        spr.setOpis("User test");
        spr.setPlan("Plan test");
        spr.setPolrocze(1);
        spr.setPrognoza1("test1");
        spr.setPrognoza2("test2");
        spr.setRok(2000);
        userDAO.Save(spr);
        User spr2 = userDAO.GetUserById(spr.getId());
        Assert.assertEquals("User test", spr2.getOpis());
    }

}

请参见

spring-servlet.xml文件在哪里?我猜它在WEB-INF下,如果是这样,您就不能使用classpath加载它:正如您在测试类中所做的那样?

spring-servlet.xml文件在哪里?我猜它在WEB-INF下,如果是这样的话,您就不能像在测试类中那样使用classpath加载它?

您的意思是在我的spring-servlet.xml中编写bean吗?这是唯一的办法吗?是的。是的,据我所知。你的意思是在我的spring-servlet.xml中编写bean吗?这是唯一的办法吗?是的。据我所知,是的。xml中有一个组件扫描,它应该选择UserDAO-配置是一种组件,所以组件扫描会选择它。@gkamal你说得对。虽然这是丑陋的地狱,我认为问题在于其他地方看到我的更新。哦,我刚才看到你得出了同样的结论+我遇到了同样的问题。奇怪的是,spring一开始就不会抱怨通配符……xml中有一个组件扫描,它应该选择UserDAO——配置是一种组件,所以组件扫描会选择它。@gkamal你说得对。虽然这是丑陋的地狱,我认为问题在于其他地方看到我的更新。哦,我刚才看到你得出了同样的结论+我遇到了同样的问题。奇怪的是,spring一开始根本不会抱怨通配符。。。