在定义动态数组的同时调用构造函数-Java

使用此示例：

public class ExampleData {

  private List<String> directories;
  private String exampleString;


  public ExampleData (String[] directories, String exampleString) {
    this.directories = new ArrayList<String>(Arrays.<String> asList(directories));
    this.exampleString= exampleString;
  }
}

public class Test{

  private String[] directories={"/tmp/17","/tmp/18"};
  private ExampleData eD = 
        new ExampleData(directories, "Test");
}

public class Test{

  private ExampleData eD = 
        new ExampleData({"/tmp/17","/tmp/18"}, "Test");
}

为什么我可以用前面的代码而不是下一个代码调用它的构造函数：

public class ExampleData {

  private List<String> directories;
  private String exampleString;


  public ExampleData (String[] directories, String exampleString) {
    this.directories = new ArrayList<String>(Arrays.<String> asList(directories));
    this.exampleString= exampleString;
  }
}

public class Test{

  private String[] directories={"/tmp/17","/tmp/18"};
  private ExampleData eD = 
        new ExampleData(directories, "Test");
}

public class Test{

  private ExampleData eD = 
        new ExampleData({"/tmp/17","/tmp/18"}, "Test");
}

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因为，首先需要创建/tmp/17和/tmp/18，然后才能将它们放入列表或其他任何内容中。它们的构造函数需要单独调用

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此外，idk使用什么语言编写代码，但（{/tmp/17“，“/tmp/18”}，…）这似乎是错误的。我的意思是大括号中的曲线大括号…

Java就是不接受这种语法。你可以改为写作

private ExampleData eD = 
    new ExampleData(new String[]{"/tmp/17", "/tmp/18"}, "Test");

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谢谢你的回答。